1. <1 and <2 are supplementary angles. m<1 is 4y+7, and m<2 is 9y + 4. Find m<2.
Supplemental angles sum to 180°....so we have that
[4y + 7 ] + [ 9y + 4] = 180 simplify
13y + 11 = 180 subtract 11 from both sides
13y = 169 divide both sides by 13
y = 13
So m < 2 = 9(13) + 4 = 117 + 4 = 121°
2. GI bisects
3. The midpoint of UV is (5, 11). The coordinates of one endpoint are U(3, 5). Find the coordinates of endpoint V.
We can solve this using the midpoint formula
[ 3 + x ] / 2 = 5 multiply both sides by 2 [5 + y ] / 2 = 11 multiply both sides by 2
3 + x = 10 subtract 3 from both sides 5 + y = 22 subtract 5 from both sides
x = 7 y = 17
So.... V = ( 7, 17)
4. Find the distance between points M(6, 16) and Z(-1, 14) to the nearest tenth.
Distance =sqrt [ ( -1 - 6)^2 + ( 16 - 14)^2 ] = sqrt [ (-7)^2 + 2^2 ] = sqrt [ 49 + 4] = sqrt [ 53] ≈ 7.3 units