Thanks, hectictar.......here's another way, but...it uses some Calculus
xy = 3/2 → y = 3 / [ 2x ] (1)
10x + 3y/5 (2)
Sub (1) into (2)
10x + 9 / [10x] take the derivative of this and set it to 0
10 - (9/10)x^(-2) = 0 multiply through by x^2
10x^2 - (9/10) = 0 add 9/10 to both sides
10x^2 = 9/10 multiply through by 10
100x^2 = 9 divide both sides by 100
x^2 = 9 / 100 take the positive root
x = 3/10
And y is found using xy = 3/2
(3/10) y = (3/2) multiply both sides by 10/3
y = 5
So....the minimum is 10(3/10) + 3*5 /5 = 3 + 3 = 6
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