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As she can split her candy bars into any fraction, she can technically share them with infinite kids.

*NOTE: Don't say infinity. infinity isn't a number. I think of it as a concept - always bigger than the biggest number calculable or memorable or storable in any way, shape, or form.

10^-3= 0.001, so we can make our equation: 0.001x=38.35. If we multiply each side of the equation by 1000, we get x=38,350.

WHY?!?! I have tried 

64, 4, 84, 1, 80 and 2!! HOW HARD IS THIS??

The answer 1 was incorrect, I just can't figure this one out!

This is a math forum, and the poster is a serious user.  seriously doubt he would post a joke like that unless it was somehow indicated to be a joke thread.

There are 4 that have 1 entry point from the C, and you can't use the middle C, because if you get there, there is nothing to go to: 4(1*1*3) makes 12 (you have to move diagonally away, then vertical, then you are at the middle and can go diagonally or horizontal, making 3 possibilities.)

Starting from the middle outside: 4(2 + 10 = 12) = 48.

Staring from the top and bottom center: 2(2 + 3 + 3 + 2 = 10) = 20.

I'm getting 80, but I feel like I did the last one wrong.

If you want to get scientific notation, put in your equation, then press enter. It will show you a step taken to get the solution, or just the solution. Press enter again. It should show you the answer. Press enter again, and it should show you the solution in scientific notation.

To add on to Cavallin ^^^

Theres also this thing called the double negative rule where if you have 

(-2) - (-7)                If you take away the parenthesis you see two negative symbols right next to each other

If ever you see that    -2 - -7         the double negative turns into a positive so your new problem would be

-2 +7 = 5

If you have a 1/80 chance of getting a certain outcome, the probability you will get a certain outcome is (1 - outcome)^tries.  So, the chance of not getting a 1/80 outcome over 173 tries is (1-(1/80))^173 = 0.1134799259264859, or about 11.35%. With 4 people doing this many tries, the outcome is just as likely as one person doing 4 times 173 tries, so the probability would be ((1-(1/80))^173)^4 = 0.0001658349921536, or about 0.0166%.

Okay so i think what your asking  is

one and three fifths times a negative three fourths?

Thats the Quadratic Formula, you plug in the appropriate numbers according to the letts

(Example:

4x² + 5x +7

(a)     (b)  (c)

You can divide fractions. However, in general, you can just flip the second fraction (take the reciprocal) and then multiply the 2 fractions. To include one specific thing as a fraction on this calculator, you can place parenthesis around the fraction, and separate the numerator or denominator with a slash (x/y) --> \(\frac{x}{y}\) . If you're talking about on this calculator, you can type (a/b)/(c/d) to do this: \(\frac{a}{b}\div\frac{c}{d}\) .

I hope this helped!

Isn't that the quadratic formula?

(-2) - (-7) = 5

Think of it as you having a 2$ debt, then you get rid of a 7$ debt. Sorry for bad english, btw why don't you just use the calculator for that problem?

its =4.259577444

or = 4.3

Here's the way I do it

x / [ x - 3 ]  -   3/10  =  1 / [ 2 ( x - 3) ]    multiply through by 2

2x / [ x - 3 ]  -  6/10  =   1 / (x - 3)     rearrange as

2x / [ x - 3]  -  1 / [x - 3]   = 6/10          reduce 6/10  to 3/5

[ 2x - 1 ] / [ x - 3 ]  =   3/5       cross- multiply

5 [ 2x - 1 ]  =  3 [ x - 3]     simplify

10x  - 5  =  3x - 9     add 5  to both sides, subtract 3x from both sides

7x  =  -4     divide both sides by  7

x = - 4 / 7

We need to solve this........h = hours that equalize the costs

26 + 3.25h  = 24 + 3.50h        subtract  24, 3.25 from each side

2  =  .25h      divide both sides by .25

8 = h

Here's the graph : https://www.desmos.com/calculator/xvecjgpras

In the form ax^2  + bx + c   the x value that will give the minimum is

-b / [ 2a]

So  we have    x^2  + 11x - 5

a =  1     b =  11

So

-b / [2a]   =   - 11 / [ 2 * 1]  =   - 11 / 2

And this is the x value that minimizes the function

The solution is the point that lies on both lines....that is the point where the two lines touch.

It looks like that is the point  (-2, 2)   

x  =  2y - 5

5x - 6y  =  7        Since  x = 2y - 5 , we can substitute  2y - 5  in for  x .

5(2y - 5) - 6y  =  7           Distribute  5  to the terms in partenthesees.

10y - 25 - 6y  =  7            Add  25  to both sides of the equation.

10y - 6y  =  7 + 25           Combine like terms.

4y  =  32        Divide both sides by  4 .

y  =  8            Plug this value for  y  into the first equation to find  x .

x  =  2(8) - 5

x  =  16 - 5

x  =  11          

z = x^2+2y^2+6x-4y+22   complete the square on x and y

[x^2 + 6x + 9]  +  2 [ y^2 - 2y + 1]  +  22   =  z + 11

(x +3)^2   + 2(y -1)^2   =   z - 11

This will be minimized when  the right side = 0    ⇒   z = 11

Thanks so much