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This unit might be very helpful for you 

If you know that they are wrong then you must know what the answer is already.

So why do you give people here less information than what you have been given?

Well, this is what happens when you give wrong numbers in your questions!!!!,

Formula: FV =P x {[1 + R]^N -1 / R}

                FV =600 x {[1 + 0.04/12]^(7*12) - 1 / (0.04/12)}

                FV =600 x {[1.003333333]^84 - 1 / (0.003333333)}

                FV =600 x {[1.3225138..] - 1 / (0.003333333)}

                FV =600 x            96.7541591656..........

                FV =$58,052.50 - Balance in Yolanda's account after 7 years.

 Zach's Account:

              FV =7,200 x {{1+0.04]^7 -1 / 0.04}

              FV =$58,867.72 - Balance in Zach's account after 7 years.

Yeah thanks both wrong though! Thank you for trying! 

Just try to imagine how much money Yolanda and Zach would have if the APR was 44%... 

Assuming month = 30 days.

Yolanda's savings after n years = \(Y_n\)

Zach's savings after n years = \(Z_n\)

Yolanda's DPR ==> \(DPR={APR\over365}={4\%\over365}=.0109589041096\%\)

Zach's DPR is the same.

Monthly percentage rate of both accounts ==> \(.0109589041096\%*30=0.328767123288\%\)

Yolanda will have total savings of \($(600*7*12+600*0.328767123288\%*7*12)\) 600 being the monthly deposit, 7*12 being the total months in 7 years, and 600*0.328767123288% being the monthly percentage rate. Computing, we get \(Y_7=$50565.6986301\).

Zach will have total savings of \($(7200*7+7200*7*4\%)\) 7200 being the yearly deposit, 7 being the number of years, 7200*7*4% being the interest after 7 years. Computing, we get \(Z_7=$52416\).

Comparing the two, we see that Zach's investment strategy is more effective. 

P.S. I might be wrong

This is what I think

a) yes

b) and c)  The wording is strange but it is not contiuous at x=-1

d,e,f,and g are all -infinity

h) it is not continuous at x=-4

i,j,k,l all =0

m) Yes f is continuous at x=-2

----

n)    1

o)    -2

p) undefined

q)   f(-1)=-2

r)  f is not continuous at x=-1

s,t,u,v all =-2

w) f is continous at x = 3  (I think)

Infinite discontinuity at x=-4

x)  Jump discontinuity at x=-1

That is it I think.....

sin(110°) = sin(180° - 70°)  →  sin(180°)*cos(70°) - sin(70°)*cos(180°)  →  0*cos(70°) - sin(70°)*(-1)  → sin(70°)

So sin(70°)/sin(110°) = 1

.

\(55=\frac{55}{1}\)

It is where the y=(x-1)^4  is undeneath the y=x-1 curve!    

That should be enough info :)

Thanks so so sooo much! Just one question, how did you know what sin 70 divided by sin 110 is?

That would be amazing! Thanks!

Thanks!​

Expand and simplify.

(t-1)^3 + 6(t-1)^2 + 12(t-1) + 8

Formula:
\([1+(t-1)]^3 = t^3 = (t-1)^3 + 3(t-1)^2+3(t-1) + 1 \)

\(\begin{array}{|rcll|} \hline && \mathbf{(t-1)^3 + 6(t-1)^2 + 12(t-1) + 8 } \\ &=& (t-1)^3 + 3(t-1)^2+3(t-1) +1 \\ && \quad + 3(t-1)^2+9(t-1)+7 \\ &=& t^3 + 3(t-1)^2+9(t-1)+7 \\ &=& t^3 + 3(t^2-2t+1)+9t-9+7 \\ &=& t^3 + 3t^2-6t+3+9t-9+7 \\ &=& t^3 + 3t^2+3t+1 \quad & | \quad (1+t)^3 = t^3+3t^2+3t+1 \\ &\mathbf{=}& \mathbf{(1+t)^3} \\ \hline \end{array} \)

Im not much help i havent taken stats or whatever this is, but i do remember for problems like this you can refer to independent variables. x per a month and so.

It's actually 5% and then 5.5% I typed it wrong... still don't know the Answer 

It's actually 4% so what would be the answer? 

I do not know what you mean here.  What folders?

I have never seen modular arithemtic graphed before.

I blanked all but one of the graphs to see what it would look like.

It is super interesting. 

Thanks for sharing :)

1000 - 25x  >  250

Add  25x  to both sides.

1000  >  250 + 25x

Subtract  250  from both sides.

1000 - 250  >  25x

750  >  25x

Divide both sides by  25 .

30  >  x

That is the same as saying

x  <  30

From  100 - 199, These are the numbers containing a zero:

100, 101, 102, 103, 104, 105, 106, 107, 108, 109, 110, 120, 130, 140, 150, 160, 170, 180, 190

There are  19  of them.

From 100 - 199, there are 19 .

From 200 - 299, there are 19 .

From 300 - 399, there are 19 .   etc.

From 100 - 999, there are  19 * 9  numbers containing zero.

And there are 900 numbers from 100 - 999, including 100 and 999.

So the probability  =  \(\frac{19*9}{900}\,=\,\frac{171}{900}\)       ???

Let the starting price be x

Satrting Value=x

The price of a stock increased by $3/day for six days,

new value = x+3*6 = x+18

then decreased by $2/day for three days

new value = x+18 - 2*3 = x+12

and then decreased by $5/day for two more days.

new value = x+12 -5*2 = x+2

If the final price of the stock was $39, what was its starting price?

x+2=39

x=37

The starting price was $37

Thanks!!!

If we look at it like this, we can see that  ∠AEF  and  ∠CAD  will add to  180° .

∠AEF + ∠CAD  =  180°            Plug in   10( ∠BAC ) - 12°   for  ∠AEF .

10( ∠BAC ) - 12°   +   ∠CAD  =  180°             And since  AB bisects ∠CAD,  ∠CAD  =  2( ∠BAC ) .

10( ∠BAC ) - 12°   +   2( ∠BAC )  =  180°       Add  12°  to both sides of this equation.

10( ∠BAC ) + 2( ∠BAC )  =  180° + 12°          Combine like terms.

12( ∠BAC )  =  192°                Divide both sides by  12 .

∠BAC  =  16°

And remember that

∠CAD  =  2( ∠BAC )      So...

∠CAD  =  2( 16° )

∠CAD  =  32°

I don't know that...