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Calculate $157,198.00 x 20% compounded daily x 89days

157198.00(1.2)^89= $$

1752176755001.65= $$

-Fitz-

GuestOct 6, 2012

+3146

8^2=8^2+a^2-2*8*a*cos(62)

64=64+a^2-16a*cos(62) | -64 on both sides
64-64=64-64+a^2-16a*cos(62)
a^2-16a*cos(62) = 0

a^2-16*cos(62)*a = 0
define constant z as "-16*cos(62)"
a^2+z*a = 0
a*a+z*a=0
a* ( a + z ) = 0

this is zero if a or ( a + z ) is zero.
a is zero if a = 0. (solution 1)
a+z=0 is zero if a=16*cos(62)=7.511545004574252 (solution 2)

solution {a=7.511545004574252, a=0}

adminOct 6, 2012

If someone has a tinypic account can you please change the tags if you could? Someone must have put them up haha...

GuestOct 6, 2012

Oct 5, 2012

3x-2(5x-3)=7
=3x-10x+6=7 I-6
=3x-10x =1
=-7x =1I:-7
=x =-1/7

GuestOct 5, 2012

+3146

Schüler98:
Der Erfinder des Schach-Spiels erbat sich als Lohn für das erste Feld ein Reiskorn. Für jedes weitere Feld jeweils das doppelte des vorhergehenden Feldes.

0. Feld: 1 Reiskorn
1. Feld: 2 Reiskorn
2. Feld: 4 Reiskorn
3. Feld: 8 Reiskorn
4. Feld: 16 Reiskörner

Summe von 64 Feldern: 2^0 + 2^1 + 2^2 + 2^3 + ... + 2^63 = 1 + 2+ 4+ 8+ 16 + ...

und:
1 + 2 = 4 - 1
1 + 2+ 4 = 8-1
1 + 2+ 4+ 8 = 16-1

Summe aller vorherigen Felder = Anzahl auf nächstem Feld minus 1.

somit bei 64 Felder: 2^64-1 Reiskörner auf dem Schachbrett.

[input]2^64-1[/input]
test:
[input]sum(2^(x-1),x=1..64)[/input]

[input](2^64-1) * 1g/50 in tonnen[/input]

[input]368934881474.19103232 / 50e6[/input]

-----

[input]2^x-1 = 50000000 * 1000 * 1000 * 1/50[/input]
=> 40 Felder = 50mio Tonnen

adminOct 5, 2012

+3146

daniboi:

x + y = 100
x - y = 28

[input]solve( x + y = 100, x - y = 28 )[/input]

adminOct 5, 2012

+3146

[input]100MB / 56kbit/s in min[/input]

adminOct 5, 2012

Hi guys, I would just like to say..

HELLO

That is all.
-Fitz-

GuestOct 5, 2012

Oct 4, 2012

Well...
Actually it seems quite complicated but I may try to solve.
If it's still in effect - contact me)

Jamie85Oct 4, 2012

Guest:
x^2-y^2=(x-y)(x+y)
25p^2-100q^2=(5p-10q)(5p+10q)

I hope it is helpful

ax^2+bx+c

I assume that a=d*e and c=f*g.
if (d*g)+(e*f)=b, we can factorize the equation lie that (dx+f)(ex+g).

2x^2-13x-7
| |
V V
1 -7
2 1

2*(-7)+1*1=-13, so now we can write (2x-7)(x+1)

GuestOct 4, 2012

x^2-y^2=(x-y)(x+y)
25p^2-100q^2=(5p-10q)(5p+10q)

I hope it is helpful

GuestOct 4, 2012

Oct 3, 2012

always 1

-Fitz-

GuestOct 3, 2012

Yes

-Fitz-

GuestOct 3, 2012

Just use your head! Significant figures are simple once you have the processes down.7

-Fitz-

GuestOct 3, 2012

+28

Wow

MathIsHardOct 3, 2012

Thanks you have me really help

GuestOct 3, 2012

Jonas:
Hallo, ich weiß nicht wie ich es lösen könnte: Die Summe zweier Zahlen ist 100 vermindert um 28. Ich weiß das ich er x+y=100 aber was muss ich dann machen ?