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Thanks,  Melody....here's another approch

Area   = (1/2) 30 * 40  =  (1/2) 50  * h

600  = 25 h

24  = h  = the shortest altitude

John, Johan, and Jonathan collect postage stamps. Johan and Jonathan have the same number of stamps. Two times Johan’s collection is eleven less than five times John’s collection, and three times Jonathan’s collection is three less than seven times John’s collection.

Call the number that Johan  has  = x....and the number that Jonathan has  = y   so   x  = y

Call the number of stamps that John has  =  z   ......so...we have these  two additional equations

2x + 11  = 5z

3y + 3 =  7z

Since Johan and Jonathan have the same number of stamps,  the first equation becomes

2y  + 11  = 5z        divide both side by 5

[2y + 11 ] / 5  = z      sub this into the second equation for z

3y + 3  =  7 [ 2y + 11 ]  / 5      multiply both sides by 5

15y + 15 =   7 [ 2y + 11]

15y + 15  = 14y  + 77    subtract 15, 14y from both sides

y = 62 

Using   2y + 11  = 5z   we have that

2(62) + 11  = 5z

124 + 11  = 5z

135  = 5z    divide both sides by 5

27  = z  = John's stamps

height of the ball   =   h(t)   =   -16t² + 20t + 2

The maximum value for  h(t)  will occur when  t  =  $\frac{-20}{2(-16)}$   =   $\frac58$

It will take  5/8 of a second,  or  0.625 seconds, for the ball to reach its maximum height.

To find the ball's maximum height, plug in  5/8  for  t .

h( 5/8 )  =  -16( 5/8 )²  +  20( 5/8 ) + 2

h( 5/8 )  =  -16( 25/64 )  +  50/4  +  2

h( 5/8 )  =  -25/4  +  50/4  + 8/4

h( 5/8 )  =  33/4

The maximum height is  33/4  feet,  or  8.25  feet.

The area of the rectangle is   width   *  height

The width  is  (x + 3)

The height is ( x + 2)

So....the area is    (x + 3) ( x + 2)  =9    simplify

x^2 + 5x  + 6  = 9      subtract 6 from both sides

x^2 + 5x  = 3

Yup! :)

a newspaper?

-_- the question wont paste in. It keeps deleting. 

Not  sure about this one, Julius....!!!!

Harmonic mean  =  

1/ m =      Average of the recipocals  =    (1/a + 1 /b) / 2   =   (a + b) / [2ab]     (1)

So....m  is the reciprocal of (1) =   [ 2ab ] / ( a + b)

Thank you sooo much! 

Let's call the distance that he paddles one way  = D....note that the distances going and coming are the same  ...so....

And  Distance  / Rate  = time  [ In hours]...so...

D / 3  +  D / 2  =  2.5    simplify

D [  2 + 3 ] / 6  = 2.5   multiply both sides by 6

D [ 5 ]  =  15      divide both sides by  5

D  = 3 km

nioce!

I still need a-f though, thatnks for a and b!

Use these equations to solve:

$x+y=74 \tiny \text { Total heads; x = number of humans and y = number of horses} \\ 2x+4y=196 \tiny \text{ Total legs: each human has two and each horse has 4}\\ \text { Solve for x and y}\\ $

What in the heck are you talking about?! 

Thanks

For A, since a correct answer is worth 2, and an incorrect is worth -1/2, it is simple multiplication

30*2=60

-1/2*5= -2.5

Subtract 2.5 from 60

60-2.5=57.5

In total, that leaves 57.5 points.

For B, I would have to say it is not possible to determine the score based off correct answers, due to the fact that incorrect answers deduct points, and unanswered aren't worth anything.

A concert at a graveyard came to a sudden halt when a skeleton approched the group.

He said, "Could you try tiba bit more quiet? I'm trying to sleep."

The singer replied with, "Sorry, we were bonely trying to have a bit of skelefun."

Q. How do you confuse a blond?

A. Put her in a round room and tell her to sit in the corner.

27? i just chose a random answer...

Okay, problem solved:

1. I have moved "MIN:=20000;" to next row after "WRITELN(' ');"

2. I changed "IF D

3. I moved that parole to the loop.

And.. now it's perfectly working. :3

f(2)  =  4² - 1   =   16 - 1   =   15           At  2  hours, there are  15  students enrolled.

f(4)  =  4⁴ - 1   =   256 - 1   =   255       At  4  hours, there are  255  students enrolled.

The number of students goes from  15  to  255 .

255 - 15  =  240      So the number of students increased by  240 .

The number of hours goes from  2  to  4 .

4 - 2  =  2      So the number of hours increased by  2 .

In  2  hours time, the number of students increased by  240 .

On average, that is an increase of  240/2  ,  or  120 ,  students per hour.

The average increase in the number of students per hour is  120  .