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(9b + 7) / (b + 7) in base 12 =A6 / 16 = 7 with no remainder.

(9b + 7) =12^1*9 + 7 = 126 in base 10

(b + 7) = 11 + 7 = 18 in base 10

126 / 18 = 7 with no remainder.

This was answered already just a few days ago.....see

https://web2.0calc.com/questions/base-question_2

Thanks CPhill, unfortunately I can't see your diagram but I think i get the gist!

Well that's interesting, I can't even see my own diagram either... Thank you for the help Alan, I hope this isn't a permanent problem.  Could it be because of the slow phasing out of Adobe Flash Player from Google Chrome? (I'm just spitballing here)

Strangely, I can see the images from the Answers page, but if I jump into the answer itself I can’t!!

(Except for the right angled triangle, which I can see from within the question and answers).

You got it !!

∑[3n - 2], n, 1, 25 ] = 925

Note: you can use the on-site calculator here by entering it like this:

Sum ((3n - 2), n, 1, 25) = 925

I still cannot see any of them either.

I can't see any of the images....I've noted the problem to the Admin

Currently I’m using an iPad and this particular image is clear. It’s a right-angled triangle, LJK,

angle L is 60deg, hypotenuse LK is 20.

There are other images in other postings which do seem to suffer from the “waiting for moderation” with the iPad.

Glad to help, OBT....!!!

thank you cphill

How are you seeing this, alan??

What browser do you use  ??

We have the following terms

2/3  + (2/3)^2  + (2/3)^3   + (2/3)^4 + .....

The common ratio between terms is (2/3)....so....this converges to :

(2/3)  / [ 1 - 2/3]   =

(2/3) / (1/3)  =

(2/3) * (3/1)  =

2

Here's a pic, ACG :

The perpendicular bisectors meet at  (7, 3.5)......this is the circle's center

The equation of the circle  is

(x - 3.5)^2 + ( y - 7)^2  =  3.5^2

So.....the radius is 3.5

i am working with sigma at the time, i will give this a whirl

so 3n-2 with all numbers from 1-25 plugged and then those added

i think its about 925

Thank you for helping me!

How come you can see this but I cannot?   All of the Q's, submitted for the last couple of days , with diagrams (INCLUDING answers I submitted with diagrams) STILL display 'waiting for moderation...'   ????

there are fourteen

Avg rate of change from 1 to 4  =

] 244  - 484 ]  /  [ 4 - 1 ]  =

[ -240 ]  / 3  =

-80

wow i leave a question overnight and get answers galore. thanks guest for giving me the formula

LJ = 20cos(60)

JK = 20sin(60)

Area = (1/2)*LJ*JK

note that cos(60) = 1/2 and sin(60) = sqrt(3)/2

Thanks EP!!

Sorry.....the  'waiting for moderation...'   thing is not working again today.   I cannot see your diagram.

x

x+2

sqrt(x+2)

4 * sqrt(x+2)

4* sqrt(x+2) = -16   There are no real solutions to this as we cannot, by convention, get a negative sqrt

square both sides    16 (x+2) = 256

(x+2) = 16

x=14                 Extraneous

From MathIsFun website:

Example: you have an equation and after some work come up with two roots (where it equals zero) "a" and "b". When you put "a" into the original equation it becomes zero, but when you put in "b" it doesn't. So "b" is an extraneous root. This often happens when we square both sides during our solution.

Oh, that's okay. Here's a link to the picture of the function table: https://imgur.com/a/X2mIu

Thank you so much for trying to help me.