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A person standing at the top of Mountain Rainier would be approximately 2.7 mi high. The radius of earth is 3959 mi.

What is the distance to the horizon from this point?

We can use the Pythagorean Theorem, here 

We have a right triangle with a hypotenuse of 3959 + 2.7  = 3961.7 mi

And the radius of the Earth represents one of the legs...so....the distance to the horizon is the other leg and given by :

√ [ 3961.7^2  - 3959^2 ]   ≈  146.2 mi

 The line of sight to the horizon , the radius at the horizon and the radius at the mountain from a right angle triangle, so Pythagoras's theorem gives 

d = sqrt( ((R+h)^2 - R^2) 

= sqrt( 2Rh + h^2) 

= 146.2mi

oh ok how did you get the answe?

the answer is 146.2

im not sure i dont think so 

do we need to find the point at the centre of the earth or the point on the circumfernce of earth?

Let N be the number

( [ N * 3]  + 4 )  / 4  =   N - 3

(3N + 4 ) / 4  =  N  - 3       multiply both sides by 4

3N + 4  =  4 (N - 3)

3N + 4   =  4N - 12       add 12 to both sides, subtract 3N from both sides

16  =  N

So

16  - 3   =   13

oh ok lol

nevermind

A person standing at the top of Mountain Rainier would be approximately 2.7 mi high. The radius of earth is 3959 mi.

What is the distance to the horizon from this point?

Enter your answer as a decimal in the box. Round only your final answer to the nearest tenth.

yes me please

no problem

can someone answer another question?

? * 3 + 4 ÷ 4 = ? - 3

16 * 3 + 4 ÷ 4 

48 + 4 ÷ 4 

52 ÷ 4 

13

13 3 less than 16

I believe this is a similar problem to finding the number of distingiushable "words" that can be made from a "word"  with repeated letters

Let each rocking chair be represented by the letter "A"

Let each stool be represented by the letter "B"

Then....we are looking for the number  of distingiushable "words" that can made from the word

AAAAAAAABB

This is given by

  10!

_____  =     45  ways

8! * 2!

nevermind

I need help.

16

a tangent and radius meet at 90 degrees

use Pythagorean theorem 

c= 3959mi + 4.5mi

c= 3963.5mi

a^2 = c^2 - b^2

a^2 = 3963.5^2 - 3959^2

a^2 = 35651.25

a= √35651.25

a= 188.8mi (nearest tenth)

The area  of the base is given by

(1/2) AB * AC  sin (90)  =   AB * AC / 2    =  x * x  / 2  = x^2 / 2

The height is AD  = 2AB  =  2x

So.......using the formula

72  =  (1/3)  base area * height     ....   subbing the above, we have

72 = (1/3) [x^2/2] * [2x]

72 = (1/3) [ x^3]        multiply  both sides by 3

216  =  x^3         take the cube root of both sides

6 (cm)   = x

8)In the diagram, XY and XprimeYprime are diameters of the two bases of the cylinder, and XY is parallel to XprimeYprime. We know [XYYprimeXprime] = 30. Find the lateral surface area of the cylinder.

I'm assuming that  [ XYY'X']  represents the area of the cross-section....then  the area can also be represented by

2r * h

So

2r * h  = 30

r * h  = 15

So....the lateral surface area, based on this assumption is

2pi  *r * h    =

2pi (15)  = 

30 pi  units^2

This is just the sine function shifted down 2 units

Here's the graph

https://www.desmos.com/calculator/kiylmiq5lm

Which graph represents the function?

This is the ceiling function shifted down 3 units

To find out which graph is correct....

Let  x  =2

ceiling (2)  - 3=   2  - 3  =  -1

Let x = 2.5

ceiling (2.5) - 3  = 3 - 3  = 0

Let x  = 3

ceiling (3) - 3   =  3 - 3  = 0

The botom right graph is the correct one....

Which graph represents the function?