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the graph shifts 7 units left and 2 units up.

Here's a more formal way to do this, ACG

Let  the radius of the smaller circle  = R

Then the radius of the larger circle is just the radius of the smaller circle plus the width of the track, W

So

The circumference of the smaller circle plus 10pi ft  = the circumference of the larger circle

So we have

2pi(R) + 10pi   =  2pi (R + W)

2pi (R) + 10 pi  =  2pi (R)  + 2pi(W)        subtract 2pi (R) from  both sides

10 pi  = 2pi (W)

10  = 2W

5 (feet)  = W   = width of the track

f(x)=x^2-9/x-3

f(x)=(x+3)(x-3)/(x-3)

x-3=0

x=3

3^2-9/3-3

9-9/3-3

0/0=0

y=0

hole at (3, 0)

Yeah lol. I started to put the numbers into my calculator but then i saw the zero. Lol.

E(x)=(1-x)(6x-8)+16-9x^2

(1 - x) * 2 * (3x - 4) +  (4 - 3x) ( 4 + 3x)

-2 (1 - x) (4 - 3x)  + (4 - 3x ) (4 + 3x)   take out the GCF

(4 - 3x )  [ -2(1-x) + (4 + 3x ) ]

(4 - 3x ) [ -2 + 2x + 4 + 3x ]

(4 - 3x)  ( 5x + 2 )

bottom right graph

Vertical asymptote: x=-4

Horizontal asymptote: y=-6

I have noticed that guests have a tendency to be ruder than regular users. Im not saying every guest does it, but i have seen a lot of guests say rude things. Maybe it is just one guest, but i dont know.

What do u wana talk about? Im realy bored and i just wana chat about stuff.

 In mathematics, the functions of the whole part are functions that take a real number and return a whole number, either by excess or by default.
 Function floor (or ground), that to each real number assigns the nearest whole number by defect, that is to say, the greater whole number equal or smaller than that real number.
 Let's evaluate the extremes of the interval
 x = -3
 g (-3) = floor (-3) -2 = -5
 x = 3
 g (3) = floor (3) -2 = 1
 Therefore, the graph that best corresponds to the function in the given interval is the attached graph.

top right graph

Which graph represents the function?

graph 1

1. The area of her garden is  25 * 15    = 375 ft^2

So......we can find the side of a square with the same area, thusly :

375  = side^2      take the square root of both sides

√375  =  side

So....the perimeter of the square is 4 times this  =  4√375 = 77.4 ft

2.   Area of rectangle 14 * 16  =  224

Side of square  = √224.....  15 mm   GOOD JOB  !!!!

3.   The perimeter is given by    4√ [50 *32]  = 4 √1600  = 4*40  =  160 ft

You may have forgoten to multiply the side of the square by 4 to get the perimeter  ???

3).

A=l*w

A=50*32

A=1600

√1600=40

p=40*4

p=160ft

B.160ft

1) A=l*w

    A=25*15

    A=375

   √375=19.4

    19.4*4=77.4ft

   C). 77.4ft

2.

area of rectangle = length * width

area of rectangle = 14mm * 16mm

area of rectangle = 244mm^2

√244mm = 15mm

D = 15mm 

So is my answer the correct answer?

Nice, qualitystreet   !!!

6cm/4cm=1.5

1.5²=2.25

20cm²*2.25=45cm²

The scale factor  of the larger triangle to the smaller  =  6/4  =  3/2

The  area of the larger triangle  =

(Area of smaller triangle )  *  (scale factor)^2  =

20    *  (3/2)^2  =

20  * 9/4  =

(20/4) * 9  =

5 * 9   =

45 cm^2

v=4/3*3.14*r^3

v=4/3*3.14*3.25^3

v=4/3*3.14*34.3

v=144m^3

A car depreciates(lost its value) at a rate of 30% per year. How much will a $20,000 car be worth in 5 years?

1.

area of trapezoid (park)

A = (a + b) ÷ 2 * h

A = (25 + 33) ÷ 2 * 30

A = (58) ÷ 2 * 30

A = 29 * 30

A = 870yd^2 

area of circle (fountain)

A = π * r^2

A = π * 4^2

A = π * 16

A = 50yd^2 (nearest whole number)

area of park - area of founatin = area of the park without the fountain

870yd^2 - 50yd^2 = 820yd^2

Area of rectangle  = 15 * 27   = 405 mm^2

Area of square   =  side^2   .......so...

405 = side^2       take the square root of both sides

√405  =  side  ≈  20.1 mm

E(x)=-(3x-4)(5x+2)