Thanks, Gavin!
Here's a solution.
l=b+16, where l=length and b=breadth
l:b=4:3, so that's 4x:3x
So, x=16
4x=64, and 3x=48
Thus, 64:48=4:3
I'll start off with 44.
Apply complex arithmetic rule: (a+bi)(c+di)=(ac-bd)(ad+bc)i
a=4, b=3, c=5, d=-6
Plugging them in, we have:
(4*5-3(-6))+(4(-6)+3*5)i
So, simplifying, we get \(38-9i\)
please explain each of them thoroughly
Total Area: 10*9=90u^2
Area of D: 9*3=27u^2
So, \(\frac{27}{90}=\frac{9}{30}=\boxed{\frac{3}{10}}\)
43. \(x\leq -4\) or \(x \geq 3\)
44. Apply complex arithmetic rule, to get 38-9i, (A)
250(1/2)^(1000/2000)
Let us first reduce the above expression:
250*1/2^1/2 Since 1,000/2,000 =1/2
250*sqrt(1/2) But sqrt(1/2) = 1 / sqrt(2)
250 * 1 / sqrt(2), or:
250 / sqrt(2).
So, 250 is a factor of 250(1/2)^(1000/2000).
41. |3x+6|-8=-2
3x+6-8=-2 so 3x-2=-2
x=0- one solution
and -4, (B)
It just takes practice :)
Thank you.
guest,
thank you very much, it frustrates me that I cannot "see" the problem at first!..Thanx a lot!
Hi Omi67,
Thank you..I see it now, I just CANNOT "see" the sum when I face it...frustrating!!..Thank you kindly!!
Let the 3-legged tables = T
Then the 4-legged tables =32 - T
3T + 4(32 - T) =115
3T + 128 - 4T =115
-T =115 - 128
-T =- 13 multiply both sides by -1
T = 13 - 3-legged tables
32 - 13 = 19 - 4-legged tables.
How many tables are there in the room of each type?
Just sub zero for x in your function:
C = 0.25x² - 80x + 300
C = 0.25(0)^2 - 80(0) + 300
C = 0 - 0 + 300
C = $300, or D on your list.
