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Plzzzzzzz someone help me

Last one: There are 6 faces, I think, wait, yes! So, the area of the first face, 2nd face: 2(20*10)=2(200)=400yd^2

Area of the 3rd face, 4th face: 2(20*20)=2(400)=800yd^2

Ares of the 5th face, and 6th face: 2(20*10)=2*200=400yd^2.

Thus, the surafce area is 400+400+800=1600yd^2. You're correct!

Yep ur right it was a question on my math hw I thought I’d post.     Lol

GCF common factor is the way to solve it! The GCF is 6, because it's the greatest number that evenly divided 12,24, and 30.

The GCF for \(30, 24,\) and \(12\) is \(6\). This means that there will be \(6\) tanks. (Correct me if I'm wrong, I'm not so sure about this one. I may have read it wrong).

- Daisy

You cannot simplify a negative number, because no two same numbers with any positivity have a product that is negative. \(\sqrt{-64} = 8i\). \(i\) stands for an imaginary number. 

- Daisy

Thank you! This helped!

a)

You just plug in the values, and evaluate the expression. 

b) 

\(x+y=\sqrt{x^2+y^2}\\ (x+y)^2=x^2+y^2\\ x^2+2xy+y^2=x^2+y^2\\ 2xy=0\)

Therefore, either x, y, or both variables have to be 0 for the expression to be equal. 

This works in reverse. If \(x+y\ne\sqrt{x^2+y^2}\), then \(2xy\ne0\).

I hope this helped,

Gavin. 

1. 

\(5ax^2 + x^3 - 5a - x\\ =(5ax^2-5a)+(x^3-x)\\ =5a(x^2-1)+x(x^2-1)\\ =(x^2-1)(5a+x)\\ =(x-1)(x+1)(5a+x)\\\)

2. 

\(a^2 - b^2 + 12b - 36\\ =a^2 - (b^2 - 12b + 36)\\ =a^2 - (b - 6)^2\\ =[a - (b - 6)][a + (b - 6)]\\ =(a - b + 6)(a + b - 6)\)

3.

\(3x^3 - x^2y + 6x^2y - 2xy^2 + 3xy^2 - y^3\\ =x^2(3x - y) + 2xy(3x - y) + y^2(3x-y)\\ =(3x - y)(x^2 + 2xy + y^2)\\ =(3x - y)(x + y)^2\)

I hope this helped,

Gavin

4√12 * 5√10  =

4 √ [4 * 3]  * 5 √ [ 5*2 ]= 

8√3  * 5√10

So...the answer is...No !!

2x+y−z =−3

5x−2y+2z = 24

3x−z = 5    (1)

Using the last equation    z = 3x  - 5

Using (1) and the first equation we get :

2x + y - (3x - 5)  =  -3

2x + y - 3x + 5  = -3

-x + y + 5  = -3

y  = x - 8   (2)

Sub  (1)  and (2) into  the second equation and we have

5x - 2(x - 8 ) + 2(3x - 5)  = 24

5x  - 2x + 16 + 6x - 10  = 24

9x + 6  = 24  subtract 6 from each side

9x  =18  divide both sids by 9

x  = 2

And using (2)... y  = 2 - 8   =  -6

And z = 3(2) - 5  = 6  - 5   = 1

So   (x, y, z)  = ( 2, -6, 1)

Oh my goodness, I don't know how I could ever repay you!! <3

1. The correct way to answer the problem is: √ 50 = √ 25 · 2 = √ 25 · √ 2 = 5 √ 2

Last One  [ you owe me  BIG TIME...LOL!!! ]

Rational

These might be anything but here is the graph of   y  = (x + 1)  /( x - 1)  :  https://www.desmos.com/calculator/watidrudhk

[ This is actually the graph of a "rotated" hyperbola ]

End Behavior : Far left end : UP   ...as we approach x = 1 from  the  left :  DOWN....as we approach x = 1 from the right : UP.....as we approach infinity : DOWN

Avg Rate of Change...Calculus, again...there is no "average rate of change"...the slope at any point on the graph is :

-2/ (x -1)^2

Positive/ Negative : The graph is  above the x axis  on  (-inf, -1) U ( 1, inf)..it is below the x axis on ( -1, 1)

x, y intercepts  :  intercepts x axis at  (-1,0)  and the y axis  at (0, -1)

Real World :  If you find any, let me know  !!!  LOL!!!

Exponential

See the graph of  y  = 2^x   :  https://www.desmos.com/calculator/btsykhud9v

End Behavior...at the left end, the graph approaches  y  = 0   ...at the right end it approaches  infinity  = "up"

Avg Rate of Change ;: Calculius again....there is no average rate of change....th slope at any x value  is   2^x * ln (2)

Positve/ Negative :  The graph is positive for all x...the range is  (0, inf )

x , y intercepts  -  no x intercept...y intercept is  (0,1).... [which is true for all graphs of the form  y  =  a^x]

Real world :  Used to model growth rates in populations, etc.

Log

See the graph of  y  = log (x)  here   : https://www.desmos.com/calculator/nxcaogf186

End Behavior :  Near x  = 0, the graph turns downward.....as the graph increases from left to right, its end behavior  is "up" on the right

Avg Rate of Change....there is no "Average rate of change"...again Calculus will show that the slope at any point x  is :

1 / [x ln 10 ]

Positive/ Negative  :  the graph is  negative  [ below the x axis} on  (0, 1)....the graph is above the x axis on (1, inf)

x, y intercept :   this graph never intercepts y, because we can't take the log log of  x  = 0.....the x intercpt  is at  x  = 1

Real World :  logs are used in  the calculation of magnitudes of earthquakes

It's alright I can think of some real world problems ^-^

Area to  be covered  x  [  qts / area ]

[ 241  + 59  ]  x   [ 2  / 200 ]  = 

[ 300]  x [ 1 / 100] =

300 / 100  =

3 quarts

Square root

See the graph of  y  = https://www.desmos.com/calculator/cooqsnkeug

End behavior.....this graph  always rises from left to right on its domain.....so..."Up"  on the right

Average Rate of  Change :  THere is no "average rate of change"...again....this requires Calculus...the "average rate of change "  is the slope at any point on the graph  [except x =   0 ] and is  given by   (1/2) x ^(-1/2)...at  x = 0  th slope is undefined

Positive/Negative :  The graph has a range  of  [0, infinity)  it is never negative

x / y intercept  = (0,0)

Again....I can't name any real world applications off the top of my head....(sorry !! )

Yeah I got one for real world, thanks ^-^

Second one

The graph is  of  y  = l x l  .....https://www.desmos.com/calculator/wn5b3geed5

End behavior : Up at both ends

Average rate of change :  on (-inf, 0)  the average rate of change  = -1....on (0, inf), the average rate of change is 1

Positiive / Negative  -  the graph is never negative...thae range  is [ 0, inf )

X, y intercept  = (0,0)

How used in the real world : Can't think of any....but I'm sure there are some  !!!

You are a freaking lifesaver, I love you xD

Thank you so much!

Well..I'll see what  I can do....but...I can't promise that I can get to each one!!!

First one

Th quadratic is  y  = x^2   [a parabola ]

Here's the graph : https://www.desmos.com/calculator/3gdzi6zvsn

End Behavior :  Up  at both ends

Average Rate of Change  [ I don't see how your teacher expects you to know this ... you need Calculus]....there is  no "average rate of change"....the rate of change [slope of the graph ]  at any value of x  = 2x

Positve/Negative  ..I assume this refers to the range ??...The graph is never negative  for  y...in other words, the range is  [0, infinity )

x intercept  and y intercept  =  (0,0)

How used in the real world.....If you have a sattelite dish....it is a parabola....the satellite beams the signal to the dish...it is reflected back to the focus of the parabola and transmitted to your inside receiver 

Thank you, CPhill! 

x+5y=-15, y=1/5x+1. First, rearrange, then we can multiply the second equation by 5, and let the first equation be.

x+5y=-15   x-5y=-5

Now, we can subtract! 5y--5y=-15--5, 10y=-10, so y=-1.

We can plug the value of y in the first equation, in order to solve for x.

x+5(-1)=-15, x+-5=-15, x-5=-15, x=-10.

Thus, the answer is (-10,-1).