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Well, I got it off of the SAT practice. How is it rubbish exactly...... I don't get this question either

(x^2+9) (x^2+9). they equal that equation. maybbee....

It is a rubbish question. 

shhhh

"this question is too abstract for me" Is.....is that a pun????

Thank you!!!

Eh...no big deal, Hectictar...now we know the area and  perimeter.......LOL!!!

Ohh......I should have read that more carefully!!!

Hectictar has given the perimeter of the third one....to find the area

If we moved the triangle above the red line down and joined it to the bottom  of the figure....we would have a square that is  23 ft on each side....so..the area  is   side^2 =  23^2  = 529 ft^2

C  is true

f(t)   = beginning population * ( 1 + growth rate)^t

f(t)  =    4800  ( 1 +  .02)^t

First of all...there are about   1.09 yds  in one meter

So  

3.7 m  x   1.09 yds / 1 m   =   [cancel the  m  ] and we have    3.7 x 1.09  ≈  4.033  yds

I'm unsure about the  "c"   in part (f)  ...is this supposed  to  be  centiliters  ???

17.5  kg  =   17500 g

The volume of the solid is

300 * 100 * .25  = 7500 cm^3

So...the density  is     17500 g  / 7500 cm^3   ≈  2.33 g / cm^3

3x  + 4y    = 72

To find the  y intercept, let  x  = 0  and we have

3(0)  + 4y  = 72

4y  = 72    divide by 4

y   =   18

To find the  x  intercept, let  y  =0  and we have

3x  + 4(0)   = 72

3x  = 72  divide by 3

x  = 24

Here's a possibility  :

l  h - 12.5  l  =  2.5

Note

l 15  - 12.5  l  = l 2.5   l  = 2.5       and   l 10  - 12.5   l  =    l -2.5 l  =  2.5

I tried to do these the way the instructions say to do it...

(a)      \(\frac{12\text{ in}}{1\text{ ft}}=\frac{x\text{ in}}{19\text{ ft}}\\~\\ \frac{12\text{ in}\cdot19\text{ ft}}{1\text{ ft}}=x\text{ in}\\~\\ 228\text{ in}=x\text{ in}\)

So..    19 ft  =  228 in

(b)      \(\frac{1\text{ yd}}{3\text{ ft}}=\frac{x\text{ yd}}{19\text{ ft}}\\~\\ \frac{1\text{ yd}\cdot19\text{ ft}}{3\text{ ft}}=x\text{ yd}\\~\\ \frac{19}{3}\text{ yd}=x\text{ yd}\\~\\ 6.3\text{ yd}\approx x\text{ yd} \)

So..    19 ft  ≈  6.3 yd

1. 6.5 x 10^6

2. 5.94 x 10^-3

3. 1.2 x 10^2

4. 2.05 x 10^-2

5. 7 x 10^-1

1. 15800

2. .205

3. .005

4. 300000

5. 60.8

x-intercept = 24

y-intercept = 18

Actually I think I got this lol

A short ton = 2,000 pounds.

260,000 / 2,000 =130 - short tons - the weight of adult Blue Whale.

130/6.5 =20 times heavier is a Blue Whale compared to an African Elephant.

(18)

Here is one way to look at it....

This kite is made up of four right triangles:

The total area of the kite is the sum of the areas of these four triangles.

area of kite  =  area of red △ + area of blue △ + area of green △ + area of purple △

Now we need to find the area of each triangle.

area of a triangle  =  (1/2)(length of base)(height)

area of red triangle  =  (1/2)(7)(3)

area of blue triangle  =  (1/2)(7)(3)

area of green triangle  =  (1/2)(3.5)(3)

area of purple triangle  =  (1/2)(3.5)(3)

Now we can find area of kite.

area of kite  =  (1/2)(7)(3) + (1/2)(7)(3) + (1/2)(3.5)(3) + (1/2)(3.5)(3)

area of kite  =  (7)(3) + (3.5)(3)

area of kite  =  3(7 + 3.5)

area of kite  =  3(10.5)

area of kite  =  31.5        That is in ft²

Can you help me figure out how to do the second one? 

The third question says, "Find the area of the parallelogram."

So we know that the shape is a parallelogram, and we know that the opposite sides are congruent.

That means the unlabeled side lengths would be labeled like this:

And...

the perimeter, in ft   =   26 + 23 + 26 + 23   =   98

Thank you, I got the answer for a

Remember, the perimeter of any polygon is the sum of the lengths of its sides.

So to find the perimeter of  (a)  and  (b) ,  add up the lengths of the sides.

I'll do  (b) :

perimeter of shape  b  , in meters   =   3.4 + 3 + 2 + 2.8 + 3.8

perimeter of shape  b  , in meters   =   15

The answer to part  (b)  is  15 .

Can you answer part (a)? To get the answer, add up the lengths of the four sides.