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\(x(x-3)=1\)

\($\frac{a+\sqrt{b}}{c}$ and $\frac{a-\sqrt{b}}{c}$\)

x( x - 3)  = 1

x^2 - 3x   = 1     subtract 1 from  both sides

x^2  - 3x  + 1    = 0  

Using the quadratic formula...   we have

x  =  [3 ±√ [9 - 4(1)(1) ]  / 2   =  [ 3 ±√ 5 ] / 2

So  abc  =  3 * 5 * 2    =  30

(a)

C  = 90 t        where t is the number of hours and  C is the  customers served

(b)

t is the independent variable

C is the dependent variable

(c)

C  = 90(11)   =  990 customers

I'll do  (a)...you can try  b

Slope  =  [ subtract the y coordinates  in some order ] / [  subtract the x coordinates in the same order ]

[Note...the order does not matter as long as it's the same ] 

So we have for (a)

Slope =  [ 5 - 5] / [ 6-  -1 ]  =  0 / 7    =  0

The slope of a tangent line to the circle at any point is given by   -x / y   where  (x,y)  is the point

So...the slope of this line is  (-8/ 15)

And using the point....we have

y  =(-8/15) ( x -8)  + 15    simplify

y = (-8/15)x + 64/15 + 225/15

y = (-8/15)x + 289/15

Hello GingerAle. I like your name. Ginger Ale is my favorite drink. What's yours?

Well, enjoy being 18.

The trird term is 13  and the fourth term is 18

So....the common difference  =  5

To find the first term, we have

13 - 2d  =   13 - 2(5)   = 13  - 10    =  3

So....the 50th term is

3 + 5 (50 - 1)  =

3 + 5(49)  =

248  ⇒ "A"

Let x be the number of  software programs to be produced and y  be the number of  video games to be produced

We have this system of constraints

x ≤ 200

y≤ 300

x + y ≤ 425

And we wish to maximize this objective function

50x  + 35y

Look at the graph of the constraints, here : https://www.desmos.com/calculator/bbbhypnku7

The possible values  of (x , y)  occur at the corner points of the feasible  region , namely at (125, 300)  or ( 200, 225)

Plugging these into the objective function, we get

50(125) + 35(300)  =   $16,750

50(200) + 35(225)  =  $17,875

Then....200 software programs should be produced and  225 video games should be produced

Thanks

-5/2(3x+4)< 6-3x        multiply through by 2 to clear the fraction and we have

-5(3x + 4)  < 12 - 6x      distribute the -5 across the terms in the parentheses

-15x - 20 < 12 -  6x    add 15x to both sides, subtract 12 from both sides

-32 < 9x       divide both sides by 9

-32 / 9  <  x   which is the same as  x > - 32 / 9

welp

time to get yerself a wife

Lol yes thanks

OK....good....[ we ALL mess up here and there.....LOL!!! ]

ohh i see where i messed up

(728.32+1109.90) -99.48 -33.5 -18.23 - 72.05  = $1614.96

\(h(x)\,=\,5f(x)-\frac23g(x)\\~\\ \frac{d}{dx}[h(x)]\,=\,\frac{d}{dx}[5f(x)-\frac23g(x)]\\~\\ \frac{d}{dx}[h(x)]\,=\,\frac{d}{dx}[5f(x)]-\frac{d}{dx}[\frac23g(x)]\\~\\ \frac{d}{dx}[h(x)]\,=\,5\frac{d}{dx}[f(x)]-\frac23\frac{d}{dx}[g(x)]\\~\\ h'(x)\,=\,5f'(x)-\frac23g'(x)\)

That is the most you can say I think. 

We want to know what each company charges for a 5 mile trip, so we want to know what is the fare price when the number of miles is 5 ?

So look at  5  on the miles axis, then go up until you reach the fare price at  5 miles.

What DC said !!!!!!

Is it C

who is not ready for Halloween