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I'm desperate for space on my pc that's why.

I know it's weird but I need a place to store memes

This could be someone's usb...

If you were worried it had illegal material on it wth did you pick it up for?

Apply a hammer repeatedly to it or toss it into a fire.

You shouldn't plug it in if it's not yours...

Ok, sounds like a plan stan.

and you can just wipe your fingerprints off with a wet washcloth so you'll be fine

If I want to wipe it I need to plug it into my computer, My friend has a junker pc, but I don't if that'll help considering I don't even know what is on the drive.

Then what do you mean by wiping it without damaging your pc?

Not yet, it's sitting in a box on top of my dresser.

Did you plug it into your computer?

good.

If it has malicious things, it could be traced back to me with finger prints.

I was thinking more of a find a safe way to wipe the usb without damaging my pc.

turn it into a lost and found type place and leave it there

I found the answer with wolframalpha,simply enter these b/d=-0.5-1.5i  , (a+b)/(c+d)=3+4.5i, a/c =1.5-2.5i to wolframalpha to get the answer.However, I still encourage you to give this a try by yourself.

ST is parallel to QR

detailed hints: you have to find the angles and know why they are what they are.

1) find angle PST in terms of x                           180-(2x+8)      

2) Find angle PTS in terms of x                            x

3)  Solve for x

4)  Determine STR

You can ask for more help if you do not get a particular step but think about it first.

Yes that is MUCH better  

Hi Fiora,

I think you have misunderstood.  I do not think this is intended as a unit circle question.

I think the radius is 24 and the area of the sector is 24pi   units^2

\(Area = \frac{degrees \;of\;arc}{360}\times \pi r^2\\ 24\pi = \frac{degrees \;of\;arc}{360}\times \pi *24^2\\ 1 = \frac{degrees \;of\;arc}{360}\times 24\\ 1 = \frac{degrees \;of\;arc}{15}\\ degrees \;of\;arc =15\) 

I have edited the question, is this good enough

Use the function y = 10x + 9 to make an input-output table.

Write the equations of the lines that form the four sides of the right trapezoid with vertices at (−16, 7), (−16, −4), (5, −4), and (16, 7).

A and B must be integers in the range 0 to 8  (I'll assume here that A and B are both non-zero)

AB_9  is   9A+B

B0_9  is   9*B+0

So    9A+B + A = 9B + 0   or  10A = 8B

The only combination of integers in the range 1 to 8 that satisfy the above equality is A = 4 and B = 5, so A*B = 20 (in base 10).

Triangles $BDC$ and $ACD$ are coplanar and isosceles. If we have $m\angle ABC = 70^\circ$, what is $m\angle BAC$, in degrees?

In the diagram, $R$ is on $QS$ and $QR=8$. Also, $PR=12$, $\angle PRQ=120^\circ$, and $\angle RPS = 90^\circ$. What is the area of $\triangle QPS$?

\\S**t, I type my answer then I pressed "post new answer", then all my work gone.

Anyway, denote point (0.62200155,0.78301601) as point B and (0,1) as point A and center point O. connect point A and O,point B and point O.

The length of major arc AB is r*\(\Theta \) where r=1 since it is a unit circle and  \(\Theta \) =asin(y/r)=asin(0.78301601)

r*\(\Theta \)=1*asin(0.78301601)=0.89950000524

you can also verify this with acos=(x/r)

See the following link for visualization:

24 is impossible value of a sector in a unit circle,since the area of unit circle is pi*1^2=pi.