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1)

The orbit of the moon isn't perfectly regular

The Sun appears at different places with respect to Earth and Moon during different days and your model may not account for this.  (Though modern models do)

There may be local geography that manages to somehow pool or channel water in places afftecting the tidal height.

2)  It will be the fractional duration of the day that has passed.  It can be calculated (to the nearest second) as

\(\text{fractional part of the day} = \dfrac{\text{seconds since midnight}}{24\cdot 3600}\)

well you've ticked the right answer.. 

Is there a question?

a) no, these shouldn't depend on one another

b) yes, and we expect more depth with more rainfall, thus positive correlation

c) no, these shouldn't be correlated

d) these are correlated but we expect less of one with more of the other, i.e. a negative correlation.

The answer is (b)

Group the first two together and the second two together. For the first group, factor out 10x² and for the second group, factor out 2. 

10x³ + 20x² + 2x + 4

10x³ + 20x²           2x + 4

10x² (x + 2)         2 (x + 2)

Now the factors in the parenthases are the same. 

(10x² + 2) (x + 2)

2(5x² + 1) (x + 2)

This question its like "we will take the 0" But 0 is not positive so no we will not take it!

Hope I help you to understand​!

Yes right question because the exercise say solutions we will have 4 positive integer values of k

If it is 5, then the disciminant is 0, but the problem says solutions, which implies that there is more than one. Am I just being dumb or do we actually have to consider this?

\(x= {-b \pm \sqrt{b^2-4ac} \over 2a}={-10\pm \sqrt{10^2-4k^2} \over 2k}\) If  rational solutions means x real so must \(10^2-4k^2> 0 \)

So \(k=1,2,3,4\) 

Total 4 positive integer values of k

Hope this helps! 

10x^3 + 20x^2 + 2x + 4       factor by grouping

10x^2 ( x + 2)  + 2 ( x + 2)

(x + 2) ( 10x^2 + 2)

(x + 2) * 2( 5x^2 + 1)

2 ( 5x^2 + 1) ( x + 2)

It's \((3x+4)(9x^2-12x+16)\) because if you do distributive property you will have \(27x^3+64\)

Hope this helps! 

lol you can call it fast walking 

Haha ....Rico is turning in 10 minute miles....THAT is NOT walking...that is jogging!

Let Donna's rate be R

And Rico's rate is R + 2

And we know that

R / [ R + 2 ]  = 2 / 3    cross-multiply

[ R + 2 ] * 2  =  3R

2R + 4  = 3R     subtract 2R  from  both sides

4  = R  = Donna's Rate  = 4 mph

And Rico's rate  =  6 mph

And 2 hrs 10min  =  2 + 1/6 hrs  =  13/6 hrs

So...Rate  * Time  = Distance

6 * (13/6)   =   

13 miles 

Thanks, ILP......!!!!

Angle OAD  is a right angle

So....Angle AOD is complementary to Angle OAD  =  90 - 28  = 62°  = Angle AOC

Note that Angle AOC is a central angle intercepting minor  arc CA

And Angle ABC  is an inscribed angle intercepting minor arc CA....so it has 1/2 the measure of AOD  =  (1/2) (62)  =  31° 

Ok she drives distance of (120+150) miles in total in (2+1+3) hours trip total. 

So we have \(\frac{(120+150)}{(2+1+3)}=\frac{270}{6}=45\) 

Finally the average driving speed, in miles per hour, during her trip is:

45 miles/hour

Hope this helps! 

sin ( u + v)   =  sin u cos v +  sin v cos u

Note...sin v  = sqrt  [ 1 - cos^2v]  = sqrt [  1 - (-8/17)^2]   =  sqrt [ 1 - 64 / 289]   = sqrt [ [289 - 64 ] / 289]  = sqrt[ 225/289]  =  15/17...and this is positve in Q2

cos u  = sqrt [ 1 - sin ^2u ]  = sqrt [ 1 - (7/25)^2 ] = sqrt [ 1 - 49 / 625 ] = sqrt [ [625- 49]/ 625 ]=

sqrt [ 576/ 625]   =  24 / 25....but...this is Q2 angle so cos u =  -24/25

So...we have

7/25   * -8 /17   +   15 /17  *  -24 / 25  =

[-56 -  360] / [ 425   =

-416 / 425

well... this triangle i beleive has a right angle and thats 90 degrease and since you are missing a number and the numbers in a triangle always add up to 180 just add 28 and 90 and whatever the answer is subtract that from 180 and that how you get the missing number *remember that there is a right angle thats why there is only one missing number . i only know that one.. i think thats right

thank you

'C'

The ratio of prices of  3 to 13 glue sticks is  $5.79/x

Yes, the answer is 'C'

13 glue sticks is to $x    as   4 glue sticks is to $7.76

13/x = 4/7.76

I think it's the way you are entering data into the first box

For example

The first one should be

C (  [ 8 ,1 ] )   

So...     8,1   should be the answer in the box

Knowing this....the rest should be easy

i beleive that the answer is c

I think you got a bunch of red 'x's because you didn't write the left side of the expression as

 c 8,1

 c 8,2

.

.

.

etc

First box ⇒  GR

Box under this  ⇒ BR

Box to the right of this ⇒ BB