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Thanks you for responding to me. 

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ok that is fine and yes it was the LaTex that i was referring to.

It would be a good idea for you to experiment a little and try and work out basic latex coding that will help.

Did you open the latex box in the ribbon and paste the coding into that ?

Or did you enter it some other way?

I just found this.  So it ist is 6.6.6    Iguess that can be writen as 6^3

Thanks!

Thanks, I'm reading the answer right now! By poor presentation, do you mean the latex not going to the next line, because I don't know how to do that. If that's not the problem then please tell me. I use this site frequently but haven't made an account yet. I want to improve my questions in the future.

There is no plane here as it is 2 dimensional, can I swap 'plane' for 'line'  I guess I can

and if so then you (or the asking guest) is correct.  C is right.

Great explanation guest. !

I never thought about answering it becasue the presentation was so poor.

If I cannot read something, I will rarely answer it.

I have improved your presentation now and asdf335 has given you an answer.    Thanks asdf335  :))

I have not checked if it is correct partly because I consider that to be your job.

If you do not understand the answer or you think it is incorrect then say so. 

Whether you are happy or not please thank asdf335 on the thread for his time.

Also, thank you guest for reposting in this way. This is exactly as it should be done.   

Nice, asdf.....!!!!

since ad/db is 1/5, then the ratio of the heights of the two triangles if you turned it so that line BEC is horizontal would be 5/(1+5) or 5/6, and the ratio of the bases is 2/(2+3) or 2/5. then, the ratio of the areas DEB/ABC = 5/6*2/5 or 1/3, so the area of triangle ABC is just 48*3 or 144.

This is a little trickier than it seems......let us assume that all the buses travel at the same speed

Let us suppose that a bus leaves Dallas at the same time  that a bus arrives from Houston...we don't count that one

Notice that, at that point.....there is another Dalllas-bound bus that is 30min from Dallas

But....since the buses travel at the same speed, and they travel towards each other,  they will actually  meet  15 min after the bus bound for Houston leaves Dallas 

Then, when these buses meet, there is another bus bound for Dallas that is 30min from the Houston- bound bus....but they will again meet in another 15 min because they are traveling towards each other

So....following this pattern, the Houston- bound bus will meet a Dallas-bound bus every 15 min

Notice that  the Houston-bound bus will meet the last Dallas-bound bus 4 hrs, 45 min into its trip

At this point it will have met 19 Dallas-bound buses

And in another 15 min....it wiil arrive at the Houston station at the top of the hour and not pass any more buses 

So...it will pass 19 Dallas-bound buses on the way.....

the slope of the two known points is (-4-2)/(1-3) or -6/-2 which is 3, and the slope of (a, 6) and (3, 2) must also be 3 for them to all be on the same line. the slope of those two points is (6-2)/(a-3), which must be 3, so 4/(a-3) is 3, and 4=3a-9, so 3a=13 and a=13/3.

HOPE THIS HELPED!

Meoldy: Here are a couple of answers to the same question(I think!):

https://web2.0calc.com/questions/please-help_50163
https://web2.0calc.com/questions/help-fast_79662

i think its a, some residents that dont have an address may want their say

did your teacher teach this they way she was taught? ive never heard of this before

you should like math its awesome!!!

go to art of problem solving, they have really good fun stuff

using the quadratic formula, the discriminant is a^2-20a, which must be an perfect square. it factors as a(a-20). settings this equal to some perfect squares and repeating the quadratic formula, you can get the new discriminant, which is 400+(the perfect square). this is also a perfect square, so you can write it as 400+(perfect square)=(another perfect square). subtracting, you get a difference of squares where the difference is 400. the perfect square on the left side can be 99^2, 48^2, 21^2, 15^2, and 0^2. plugging it back in, you get the equations

a^2-20a-99^2=0

a^2-20a-48^2=0

a^2-20a-21^2=0

a^2-20a-15^2=0

a^2-20a-0^2=0

since a is an integer, the square root of the discriminant is an integer. therefore you can take out the first equation, the third equation, and the fourth equation. solving the remaining two, you get the values of a as -16, 0, 20, and 36 and the answer is 4.

HOPE THIS HELPED!!!!

also, to check, you can plug in the values and solve for x.

Here is another way:

2017/2 =1008 divisible by 2 - 2017/6 =336 divisible by 6.

1008  -   336 =672 - divisible by 2 but not by 3.

Thank You!!!

It took me much longer than it needed to solve this problem, thank you for this solution

The LCM of all numbers from 1 to 130 is the PRODUCT of all Prime numbers up 130. That is:

2 x 3 x  5 x 7...........up to 127.

The LCM of all numbers from 1 to 125 is exactly the same EXCEPT 127, since it is > 125.

Therefore, when you divide them everything cancels out EXCEPT 127, which is the QUOTIENT.

while a houston bus is traveling, it takes 5 hours, and since the dallas buses leave every hour on the half hour, the answer is 5/(1/2) or 10.

HOPE THIS HELPED!!

Thank you so much!

Thank you so much!

If we were trying to solve this problem, you have to make 2 equations. We have H and C to represent hamburgers and cheeseburgers, respectively. The problem states that the shop sold a combined total of 614 hamburger and cheeseburgers, the equation for this is:

H + C = 614

And the shop also states that there we 64 more cheeseburgers sold than hamburgers. This also means that it would take 64 more hamburgers to equal the number of cheeseburgers sold. So the equation for this is:

C = 64 + H

Now, we can substitute the second equation into the first equation. So what we get is:

2H + 64 = 614

Then solving,

2H = 550

H=275

This means that 275 hamburgers were sold on Friday.

Let x = hamburgers    then x+64 = cheeseburgers     ......   added together = 614

x +  x + 64 = 614

2x = 550

x = hamburgers = 275