(x-30)+(x-30)+(x-30)=540 Remove parens
x-30 + x -30 + x -30 = 540 Gather 'like' terms
3x - 90 = 540 Add 90 to both sides of equation
3x = 630 Divide both sides by 3
x = 210
2.6=−0.2t Divide both sides by -0.2 to find
t = -13
See the answer here: https://web2.0calc.com/questions/help_11700
How about
\(\frac{3}{2}*20=d\)
Where d is the number of days that she walks.
I agree, infinity isn't considered a number. Plus infinity is never ending, while 6^6^5^4^3^2^1 does have an end.
thank you very much
Yeah!!!
-221 is waht online base 3 calc says
What would you like to do with this expression? It equals 5 (7+6s-9t)
No, it isn't......infinity cannot be 'reached'...it is a concept. Your number is VERY large and you might be able to act as though it is near infinity compared to other numbers in your compution or equation....., but in reality it is not.....
C. there is a value of 'x' in that interval where the denominator =0 ....At x = 2 results in denominator = 0 Undefined, NOT Allowed....
B. The positive and the negative areas cancel each other out......the midline is y = 0
As a ratio:
(20 cm * 20 cm * x) / 23.16 gm = 1 cm^3 /19.3 gm
Solve for 'x'
x = ( 1 * 23.16)/(19.3 * 20 * 20) = .003 cm thick
5*5*5 = 125
\(5n-(2n+3)(2n+1) \text{ (what I assume you meant)} =\\ 5n - 4n^2-8n-3 =\\ -n^2 - 13n -3 = \\ -\left(n^2+13n + \dfrac{13}{2}\right)-\dfrac{13}{2}-3 = \\ -\left(n+\dfrac{13}{2}\right)^2 - \dfrac{19}{2}\\ \text{and this is clearly negative}\)
y^3 = k/(cubrt(z))
2^3 = k /(cubrt(1) results in
k = 8
y^3 = 8/(cubrt(z))
When y = 4 find z
4^3 = 8 /(cubrt z)
8/4^3 = cubrt z
8 / 64 = cubrt z
1/8 = cubrt z cube both sides of the equation to find 'z'
1 / 512 = z When y = 4
Starts t 0 at t= 0
goes positive 15 then back to zero then -15 and back to 0 at t= 3 from t=0 to t=3 is one full period = 3 seconds
3.3333333333333 x 10^(-3)
\(343_{10}=1000_7\)
So the 4 or 5 must be in the 49's, 7's or 1's place.
There are \(49\times 2=98\) , \(7\times 2=14\) , and \(1\times 2=2\), so \(98+2+14=114\).
There are 114 of those integers.
You are very welcome!
:P
life is something that is misjudged by everyone and taken for granted life is a preases gift given to you by who knows what and they will trust you to do as what is right... that is life
a) Find the sum of the values of where the vertical asymptotes of are located.
Are you ok?
A very long prison sentence for something stupid that you did.
1 1/2 of -4 = -2 -2^2 = 4 Add 4
2 1/2 of -8 is -4 -4^2 =16 Add 16
3 Must have leading coefficient of 1 , so divide through by 3 to get
x^2 + 6x = 8
then 1/2 of 6 is 3 3^2 = 9 add 9
1/2 of 2/3 is 1/3 1/3^2 = 1/9 add 1/9
