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The calculator helps:)

$${\mathtt{\,-\,}}\left({\mathtt{0.5}}{\mathtt{\,\times\,}}-{\mathtt{113}}\right) = {\frac{{\mathtt{113}}}{{\mathtt{2}}}} = {\mathtt{56.5}}$$

This is the same as dividing -113 by -2.

I checked it on the calculator and the answer is x=((x2f(x)-9)/4)

Thank you Alan.

 equation for this function is f(x) = -x^2 + 4x + 9 assumes its maximum value for which value of x

Answer: 37,916,037,355.966839

 $${\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{5}} = {\mathtt{25}}$$ :/

That is what my 5th grade teacher told me!

With the assumption that both masses are equal and momentum is conserved the momentum equations can be written as:

Horizontal:   17 = v1*cos(45) + v2*cos(30)

Vertical:         0 = -v1*sin(45) + v2*sin(30)

These can be solved easily enough to find v1 ≈ 8.8 and v2 ≈ 12.4

However, this must be an inelastic collision, because kinetic energy is not conserved.  That is 1/2*17² ≠ 1/2*v1² + 1/2*v2².

Check your question it does not make sense. 

Where are the numbers?

tu cola ES 5 por 5

2.55 is correct if you use 9.8 for g and zero for μ.  I used 9.81 for g and 0.1 for μ which is why our final numerical results are slightly different.  

If you use the kinetic energy approach you don't need the negative sign on the m*g*sin(30).  The sign in my approach indicates that the direction down the slope is negative, and that the acceleration up the slope is negative (i.e. it is actually a deceleration).

0 & -49?

What are you doing Nat that you like cubed numbers and irrationals a lot?"

Loling at CPhil reply. I've no idea about i yet. 

DOes i before a term have a different function to i after a term?

that was a very nice explaination NinjaDevo!

hey CPhill!

My instructor said that this was "overthought"?