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It will be an "imaginary" number  ⇒  " i "

Note  √-1   is defined as  " i "

For example   

√ [ - 4 ]  =  √-1 * √4   =   i * 2   =    2i

what is it then

You can....but...it's not a real number

cos (195)  = 

cos (135 + 60) =

cos135cos60 - sin135sin60 = 

-√2/2 * 1/2  -  √2/2 * √3/2    =

-√2/4 - √6/4 =

- [ √2 + √6 ] / 4  =

-√2 [ 1 + √ 3 ] /  4

ANSWER ME NOW! MY SNAP IS @ethannater2917

the image has to be .png or .jpeg if it is not this type of image it may not work by link but you can right click and click "save image as" and select the folder to save in and click save 

then clickthen click upload then select ALL FILES then select the image then upload the image.

\(work = time \times power\\ work = (1200s)(3500W) = 4.2 MJoule\)

Thank a mill

y = -x + 7

y = 0.5(x - 3)^2

Set the y's equal

0.5( x - 3)^2 =  - x + 7     to make this easier, multiply through by 2....this gets rid of the "0.5"

(x - 3)^2   = -2x + 14          simplify

x^2 - 6x + 9 =  -2x + 14      rearrange as

x^2 - 4x - 5  =  0   factor

(x - 5) ( x + 1) = 0

Setting each factor to 0 and solving for x produces

x = 5        or     x   =   - 1

And using y = - x + 7

When x = 5, y = -5 + 7  = 2

When x = -1, y = -(-1 )  + 7   =  8

So.....the solutions are   ( 5, 2)     and  ( -1. 8)

on a scientific cacl only?

not what you meant sorry

No prob !!!

The key is to multiply n times something to "match" the first term(s)

              n^3   -  7n^2  + 6n + 4

n + 1   [  n^4  - 6n^3  - n^2 + 10n + 6 ]

              n^4  +1n^3

             _______________________

                       -7n^3  - n^2

                      -7n^3 - 7n^2         

                    _________________

                                  6n^2  + 10n

                                  6n^2  + 6n

                                 ____________

                                              4n  + 6

                                              4n  + 4

                                            ________

                                                      2

The answer is

n^3 - 7n^2 + 6n + 4     remainder  2 / ( x + 1)

Here's something that might help :  https://www.purplemath.com/modules/polydiv2.htm

Thanks 😉😉😉

Find all points, if any, where y - 4x = 12 intersects 2 - y = 2(x + 2)^2

Let's write the first as   y = 4x + 12

And the second as   y = 2 - 2(x + 2)^2

Set the y's equal and we have

2 - 2(x + 2)^2   =  4x + 12       simplify

2 - 2 [ x^2 + 4x + 4 ] = 4x + 12

2 - 2x^2 - 8x - 8 = 4x + 12

-2x^2 - 8x - 6   =  4x + 12       rearramge as

-2x^2 - 12x - 18 = 0        divide through by -2

x^2 + 6x + 9   =   0       factor

(x + 3)^2 = 0   take the square root

x + 3   =  0     subtract 3 from both sides

x = -3

And using y = 4x + 12

Then y =  4(-3) + 12  =  0

So....the solution is  ( - 3, 0 )

Here's the graph that confirms this :  https://www.desmos.com/calculator/6uplog6lqb

So is my answer plausible despite the answer in the textbook?

Also, I'm a little confused about the method you've used.

You don't just cheat your supposed to ask a real question that you don't know 👎👎👎 is my answer.

OK IM SHOOK!! I actually got A! BUT I THOUGHT I WAS COMPLETELY WRONG ok im sorry im freaking out lol

W(x) is exponential, Z(x) is a polynomial

The point (0, 1) is on W(x) and the function grows as x increases....this is characteristic of an exponential growth function

For Z(x)....it is symmetric about x = 4.....so.....this is a probably a polynomial (a parabola )

[ It also might be an absolute value function but that isn't a choice.... ]

There is a quick answer to this.....but let's solve it algebraically, first

Note   2sqrt(3) =  sqrt(12)

So.....the remaining leg is

√ [ [sqrt(12)]^2 - [sqrt (3)]^2 ]    =  √ [12 - 3] = sqrt [ 9 ] =    3 units

Note that if the hypotenuse is  2√3     and   the shortest leg  is  √3......then we have a 30 -60 -90 right triangle

The the angle opposite the hypotenuse =  90°

The angle opposite the shortest leg = 30°

So.....the remaining leg is opposite the 60°   =    √3 *√3    =     3     ...just what we  found !!!!

Very nice, Heureka......I wondered if there was a way to determine this "by hand"

I think since you know the fake weighs a bit less, it will take 3 tries...

place 6 on each side    the lighter side has the fake

take the lighter side    and place   3   on each side

the lighter side again will have the fake

place one of each of these 3 on opposite sides of the scale......if they balance the one NOT on the scale is the fake....

   if they do NOT balance, the lighter side is the fake.

You COULD get lucky and pick two coins at random and one will weigh less ...if you luckily picked the fake...so in this case it would be ONE try would be the MINIMUM>

cphill did this alreadyyyyyyyyyyyyyyyyyyyyyyyyyyyyy

https://web2.0calc.com/questions/help_3472

lol dude 

(a) If I use the number 8 and follow MathWizard's steps, what number will I get?

2 - 8  = - 6

-6 * 5 = -30

"  half the difference when 24 is subtracted from 12 times their original number."   translates to

(1/2) ( 8 * 12 - 24 ]  =    (1/2) [ 96 - 24 ]  = (1/2)(72) = 36

-30 + 36 =  6