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Its some more Spanish , that works even if its just an educated guess it really helps !

oh yes! I forgot about that also plural would be aquallas not aqualla that is just feminine .That makes so much sense thanks ! Ive posted another question if you dont mind checking it out just to double check some of my respones.

Why wouldnt it be D , using the singular form of aquel ? wouldnt u use aquella if there was more than one ?

Well, it is a difficult sequence, or rather sequences! There are actually 99 sequences that you have to sum up individually, and then take the sum of ALL the sums!.

They go like this:
2 + 3 + 4 + 5........100 - with 99 terms and comm. diff=1
6 + 8 + 10 + 12....100 - with 98 terms and comm. diff=2
12 + 15 + 18 +......100 - with 97 terms and comm. diff=3
And so on till: 99 x 100 =9900 - being the sum of the last sequence.
Only a spreadsheet or a computer code could sum them up for you. I wrote a short computer code that sums them up as follows:
5049 +  10094 +  15132 +  20160 +  25175 +  30174 +  35154 +  40112 +  45045 +  49950 +  54824 +  59664 +  64467 +  69230 +  73950 +  78624 +  83249 +  87822 +  92340 +  96800 +  101199 +  105534 +  109802 +  114000 +  118125 +  122174 +  126144 +  130032 +  133835 +  137550 +  141174 +  144704 +  148137 +  151470 +  154700 +  157824 +  160839 +  163742 +  166530 +  169200 +  171749 +  174174 +  176472 +  178640 +  180675 +  182574 +  184334 +  185952 +  187425 +  188750 +  189924 +  190944 +  191807 +  192510 +  193050 +  193424 +  193629 +  193662 +  193520 +  193200 +  192699 +  192014 +  191142 +  190080 +  188825 +  187374 +  185724 +  183872 +  181815 +  179550 +  177074 +  174384 +  171477 +  168350 +  165000 +  161424 +  157619 +  153582 +  149310 +  144800 +  140049 +  135054 +  129812 +  124320 +  118575 +  112574 +  106314 +  99792 +  93005 +  85950 +  78624 +  71024 +  63147 +  54990 +  46550 +  37824 +  28809 +  19502 +  9900 = 12,582,075.
Alternatively, there is a pattern called "closed form" that applies to every term above and it looks like this:
5050*n - 1/2 * [n^3 + n^2]. Example: First term:
5050*1 - 1/2 * [1^3 + 1^2] =5050 - 1 =5049. And with this "closed form" you can use any calculator that has sigma(∑) built into it and sum them all up. You should get the same total as above:12,582,075.

OHH thank you!!

Note that   

.134  in base 10    =    1/10  + 3/10^2  + 4/10^3

So...this would indicate that    .10101 in base 2 must be

1/2 + 0 /2^2 + 1/2*3 + 0 /2^4 + 1/2^5  =

1/2  + 0 +  1/8  + 0 +  1/32  =  [ get a common denominator of 32 ]

16/32 + 4/32 + 1/32 =

21 / 32    =  .65625₁₀

Need polynomial division here, GM

So we have

             2x^2   +  2x    + 11

x - 3  [   2x^3  - 4x^2  +  5x   - 1 ]

             2x^3 -  6x^2

             ____________________

                        2x^2  + 5x

                        2x^2  -  6x

                       ________________

                                  11x  -  1

                                   11x - 33

                                  _______

                                           32

So

2x^2 + 2x + 11  +    (32) / (x - 3)

We have 

2 possibilities for one dot/dash  =    = 2

2^2  possibilities for two dots/dashes     = 4

2^3 possibilities for  three dots /dashes  = 8

2^4  possibilities for  4 dots/dashes  = 16

So.....    2  + 4 + 8 + 16  =      30 distinct symbols

The amplitude can be found as follows

l highest point on graph - lowest point on graph l / 2  =

l -.5 - ( - 3.5) l  /  2  =

l -.5 + 3.5 l / 2  =

l 3 l  / 2

3 / 2  =

1.5  =  Amplitude

Second one

[(-1)^3 - 5] / 10 =  -6/ 10 = -.6

[ (-.6)^3 - 10 ] / 5   = -.5216

[ (-.5216)^3 - 5] / 10  = -0.5141909

[( -0.5141909)^3 - 5 ] / 10   = -0.5135948

[(-0.5135948)^3 - 5 ] / 10  = -0.5135475

[(-0.5135475)^3 -  5 ] / 10   = -0.5135438   

{ (-0.5135438)^3 - 5 ] / 10    =  -0.513543                

I didn't get the last one right

\(x_{n+1} = \dfrac{(x_n)^3-1}{4},~x_1 = -1\\ x_2 = \dfrac{(x_1)^3-1}{4} = \dfrac{(-1)^3-1}{4} = -\dfrac 1 2\\ x_3 = \dfrac{(x_2)^3-1}{4} = \dfrac{\left(-\dfrac 1 2\right)^3 - 1}{4} = -\dfrac{9}{32}\)

\(\text{The solution occurs when the recursion has stabilized on a single value}\\ \text{so just run the iteration until }x_{n+1} = x_n \text{ to 6 decimal places}\\ \text{Use a spreadsheet or something}\\ \text{You should get }x = -0.254101 \)

Now just copy this method for problem 2 which has a slightly different recursion relation.

I'll make those posts invisible...and I agree....you shouldn't be attacked...just because it might be easy for others doesn't mean that it's easy for everyone....

'Speed' is a component of velocity....if you change 'speed' you change velocity

The other component of Velocity is DIRECTION....if you change direction, you change velocity....

A change in velocity over time  is acceleration  

So  TRUE.

This won't pull up for me....

Nothing is shown.....

Your solutions are correct....!!!!