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yeah, i have the same problem and it was not correct

neither is 240

is there 6C3 somewhere?

$\text{This is just a point slope problem in disguise}\\ \text{the two points are }(x_1,y_1)= (1,5),~(x_2,y_2) = (-1,1)\\ \text{determine the slope of the line } a = \dfrac{y_2-y_1}{x_2-x_1}\\ \text{use that with either point to determine }b\\ \text{then }h(6) = a (6) + b$

I used the https://ptable.com 

O2=2(15.999)=31.998

N2=2(14.007)=28.014

NO2=14.007+2(15.999)=46.005

Lets solve one by one using unit conversions

O2=1 mol/31.998 g

88g of O2= 88*1 mol/31.998g

88/31.998 moles of O2=2.531408213013313332083 moles of O2

N2=1 mol/28.014

88g of N2=88*1 mol/28.014

88/28.014 moles of N2=3.141286499607339187549 moles of N2

NO2= 1 mol/46.005

12g of NO2=12*1 mol/46.005

12/46.005 moles of NO2=0.2608412129116400391262 moles of NO2

0.2608412129116400391262/5.933535925532292558758=0.04396050115568149888328. To make life simpler, im going to round it to

0.04396.

Fractional form is 

1099/25000

I dont know if this is correct-It doesnt seem like it-but I tried 

Good answer by Melody: https://web2.0calc.com/questions/find-a-base-7-three-digit-number-which-has-its-digits-reversed-when-expressed-in-base-9-you-do-not-need-to-indicate-the-base-with-a-subscr

f(x)=3x^2+10x-8,g(x)=3x^2-2x

(f/g)(x)=3x^2+10x-8/3x^2-2x

(3x-2)(x+4)/x(3x-2)

the 3x-2 cancel

x+4/x

It is the third answer

f(x)=g(x), so x^2-6x+8=x-2

x^2-7x+10=0

(x-5)(x-2)=0

x=5,2

Thank You!

it looks to be NUMBER_MAX in Java

$\cos(315^\circ) = \dfrac{\sqrt{2}}{2}\\ \sin(315^\circ) = -\dfrac{\sqrt{2}}{2}\\ z=\dfrac{3\sqrt{2}}{2} - i \dfrac{3\sqrt{2}}{2}\\ \text{now just apply the results of the last problem}$

The complex plane has x on one axis and iy on the other.

(-5 -3i) is 5 units to the left of 0 on the x-axis, and 3 units down.

$288_{10} = 2\cdot 144 = 2\cdot 12^2 \Rightarrow 200_{12}\\ {\dfrac{1}{288}}_{10} = {\dfrac{1}{200}}_{12}\\ \text{Did you want the duodecimal representation?}\\ \dfrac{\frac{1}{288}}{\frac{1}{12^3}} = 6\\ \dfrac{1}{288}_{10} = 0.006_{12}$

dude

http://www.math.hawaii.edu/~ramsey/Probability/TwoDice.html

I believe your answer but prove it.

$\text{interpreting this mangled bit of text I get}\\ a_n^2 - a_{n-1} a_{n+1}=(-1)^n,~n\in \mathbb{N}\\ a_0=1,~a_1=5$

$\text{one would think we'd like to calculate } a_2 \text{ next}\\ \text{applying the rule with }n=1 \text{ we have}\\ a_1^2 - a_0 a_2 = (-1)^1 = -1\\ 5^2 - (1) a_2 = -1\\ a_2 = 26$

$\text{Now just repeat that with }n=2 \text{ to solve for }a_3$