Hi,
Im the creator of this question and wanted to solve it for anyone who needs help with a similar question because I didn't really understand Melody's answer. This was on of my practice questions on my study guide and found out later that my teacher said we didn't need to use a table of values so I solved it with my sister's help. :)
So it's a lot like algerbra except a lot more annoying in my opinion because i struggle with factoring. So you start by setting everything etting everything to zero.
\(x^2-6x+8=x-2 \)
Subtract x and ad 2 to both sides to set the equation equal to 0
\(x^2-7x+10=0\)
Factor
\((x-5)(x-2)=0\)
\(x-5=0\)
\(x-2=0\)
\(x = 5, 2\)
Really hope this helps anybody struggling with this. Can't 100% confirm this is right because this is my own work BUT this is how I got my answer for this question.
