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Looks like someone copied and pasted their math homework.

Why aren't you able to, Melody? Is that how this website is with profiles?

ok but people being rude to me and that was not posed to be there so im sorry it was for someone else she was being rude and then said sorry so I forgave her im so sorry this was here. I will leave but I need the calc for something be for I leave.

Same here PM!

$2\log_2(x+5)-\log_2(x-9)-\log_2(x+53)=1\\ \log_2\left(\dfrac{(x+5)^2}{(x-9)(x+53)}\right)=1\\ \dfrac{(x+5)^2}{(x-9)(x+53)} = 2$

$x^2+10x+25 = 2x^2+88x-954\\ x^2+78x-979=0\\ (x+89)(x-11) = 0\\ x = -89, 11$

$\text{However }x=-89 \text{ ends up lying outside the domain of the log functions in the original equation}\\ \text{so it's not a valid solution. Thus }x=11 \text{ is the only solution}$

Awesome. Thank you for your help on all of these I appreaciate taking out the time to help me. Really thank you !

18 cm is    (18 - 15.2)/3.3 = .8485 (rounded to .85)  HIGHER than the mean......look at your POSITIVE z-score table  under .85 to find the number .8023  this represents the corn cob fraction that is less than 18 cm

.8023 x 250 =~ 200  corn cobs < 18cm  

The answer is C. It's obviously a reflection across the x axis, and then just use similar triangles, and see which points are the same. 

Hope this helps!

Not exactly sure what the question is here. The one comes up twice because numbers go 9 then 10.

Keep in mind he spelt knowledge wrong

Thats what i mean by "solve from there"

I will take note of all of these thanks

Awesome thanks for checking that one . I just wanted to double check

Thankyou