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DOH...I wasn't thinking!!!

He has worn the same number.....so

(1/5)W = (5/8)B    multiply both sides by  5

W  = (25/8)B

So....he has 25 white and 8 black

So....after 5 days  he has worn  5 white  = (1/5) of the white   and  5 black  = 5/8 of the black

So.....he has worn   [ 5 + 5 ] / [ 25 + 8 ]  =  10 / 33  of the total

"Your answer is incorrect, but you still have another shot at this problem. Check your work carefully and try again."

also i already got that and it was rong b4 i asked

 Translate four units left and two units down

OK....just set the function =   108    and we have that

108  = -6t^2 + 51t        rearrange as

6t^2 - 51 t   + 108  =   0         divide through by 3

2t^2 - 17 t +  36  =  0        factor....if we can

(2t  - 9 ) (t - 4)  = 0

Set both factors to 0  and solve for t   and we get two times

t = 9/2 sec    and  t =  4 sec

So  9/2 sec is correct....

NVM....

OK man....!!!!

D.....from the origin.....go  3 units to the left on x  and, from here, 2 units up on y.....

Oh okay! I just made it more complicated than it actually was! Thank you for the help!!

OK.....probably not 0 for the perimeter.....look at this

Easy to find the distance from (1,1) to (1,4)  = 3   and from (1,1) to (5,1)  = 4

Distance from (1,4) to(5,1)  =  sqrt [ ( 5 - 1)^2 + (4 - 1)^2 ]  = sqrt [ 4^2 + 3^2 ]  = sqrt(25)  = 5

So....the perimeter  = 3 + 4 + 5  =  12

You got the area correct...= 6 units^2......good job  !!!!

Okay so... I don't think I did this correctly. I got 0 for the perimeter and 6^2 units for the area.

OK.....submit your answers if you want to, and I'll check them....

(f + g) (x)  =   f(x) + g(x)

Based on this.....can you find the answer....????

Great. Thank you. I'm going to try the second one now. It's probably going to take me a few minutes though.

First one

Distance from (0,1) to(4,1)  = 3

Distance from (0,1) to ( 2,4)  =   sqrt [ ( 2 - 0)^2 + (4-1)^2 ]  = sqrt (2^2 + 3^2) = sqrt(13)

Distance from (4.1) to ( 2.4)  = sqrt [ (4-2)^2 + (4-1)^2 ]  = sqrt (2^2 + 3^2 )  =  sqrt (13)

So....perimeter  =   3 + 2sqrt(13)   units

Area  = base * height  / 2  = ( 4 * 3) / 2 =  12 /2  units^2  =  6 units^2

Based on this....do you want to try the second one ???

A parameter is derived using the entire population

A statistic is derived from a subset of the population

a) uses 85% of the population, it's a statistic

b) uses the entire population, it's a parameter

c) only uses 28 swim teams out of however many there are across America.  It's a statistic

d) uses the whole population (for the district anyway), it's a parameter

This is the second time you answer my questions, and I’m more then grateful for your help. Thank you so much, it makes more sense now! 

answer (d) is correct

p[even]=3/4

p[odd]=1/4

\(T(x,y) = xy^2 + x^2 y\\ \text{in general given a function }F(x,y)\\ \nabla F = \left(\dfrac{\partial F}{\partial x},~\dfrac{\partial F}{\partial y}\right)\)

\(a)~\nabla T = \left(y^2+2xy,~2xy+x^2\right)\\ b)~u=Q-P = (2,-2)\\ \dfrac{u}{|u|} = \dfrac{1}{\sqrt{2}}(1,-1)\\ \nabla_u T = \nabla T \cdot \dfrac{u}{|u|} = \left . \dfrac{y^2-x^2}{\sqrt{2}} \right |_{(-1,3)}=4\sqrt{2} \\ c)~\text{The most rapid decrease occurs in the direction of the gradient}\\ \left . \nabla T \right|_{(-1,3)} = \dfrac{(-3,5)}{|(-3,5)|} = \dfrac{1}{\sqrt{34}}(-3,5)\)

True, I feel like everybody will be more likely to click on the one that seems urgent then the one that just posts the question

Try using substituion method to solve this problem, where you find what S equals in terms of B, then substituting S in the second equation for that.

Here's my attempt

P(6)  =  P( 2 on first roll) * P ( 4 on second roll)  + P(4 on first roll) *P(2 on second roll)  =

                  (1/4)(2/3)       +    ( 1/2) (1/3)   =   

                      2/12   +  1/6   =

                               4/12  = 

                                1/3

P (8)  =  P(4 on both rolls)  =  (1/2) ( 1/3)  =  1/6

P(9)  =  P( 2 on first roll) * P ( 7 on second roll)  + P(7 on first roll) *P(2 on second roll)  =

                  (1/4)(1/3)       +    ( 1/4) (1/3)   =   

                      1/12   +  1/12   =

                               2/12  = 

                                1/6

P(11)  =  P( 4 on first roll) * P ( 7 on second roll)  + P(7 on first roll) *P(4 on second roll)  =

                  (1/2)(1/3)       +    ( 1/4) (2/3)   =   

                      1/6   +  2/12   =

                         2/12   + 2/12   = 

                                4/12 =

                                1/3

So...

P(6)  = 1/3

P (8 or 9)  =  1/6 + 1/6  = 1/3

P(11)  = 1/3

So....D seems to provide a fair division

D)If the sum is 6, a small cone will be ordered.
If the sum is 8 or 9, a medium cone will be ordered.
If the sum is 11, a large cone will be ordered.

Let the price of 1 burger =B

Let the price of 1 soda    =S

2B + S = $2.10....................(1)

B + 2S = $2.40....................(2)

Now, you have 2 simultaneous equations. Do you think you can solve them? Try it.

1.2 x 1.2 =1.44. Then:

1.2 x 1.2 =log(1.44)

1.2 x 1.2 =0.15836 . Remember what I said. When you multiply 2 numbers by each other, you must ADD their logs.

log(1.2) + log(1.2) =0.15836.

0.15836 divide it by 2 =0.07918 - This is log of 1.2, because:

log(1.2) =0.07918 + log(1.2) =0.07918 =log(1.44) =0.15836, or just:

.07918 + 0.07918 =0.15836 [You ADD the 2 logs of 1.2 together to get the log of 1.44]. Got it?