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Answered here :  https://web2.0calc.com/questions/help-please_9376

Well.....what is YOUR pace?  How old are you?  DO you have any significant health issues?  Diabetes?  Heart problems/arrythmias (IHSS?) or family history of such??  Neuropathies?  Arthritis? Ostreoporosis?  Blood probllems?   Back problems?  Cancer?

How tall are you?  How much do you weigh?

 As you can see THIS is not the forum to ask such health problems.....see your doctor if you have such questions......

RS  =  sqrt [ 17^2 - 8^2 ]  = sqrt (289 - 64 ]  = sqrt [ 225]  =  15

sin Q  = SR / QS  =   ????             csc Q =  the reciprocal of the sine

cos Q  = QR / QS  =   ?????          sec Q  = the reciprocal of the cos

tan Q = SR / QR  =  ????               cot Q  =  the reciprocal of the tan

Got enough here to get you started, GM ????

4. 5 sin^2(x) - 2 sin(x) = cos^2(x)

5sin^2 x - 2sin x  = 1 - sin^2 x

6sin^2x - 2sin x - 1  =  0

(3sin x + 1) ( 2sin x - 1)  = 0

3sin x  = 1

sin x  = 1/3     take the arcsin

arcsin (1/3) =   x   ≈  .34 rads      and x ≈  [ pi - .34] rads ≈  2.80 rads

And

2sin x  - 1  = 0

2sin x  = 1

sin x  = 1/2      and this occurs at x = pi/6    and x  = 5pi/6

What does that L-shaped symbol mean? It is neither "floor" nor "ceiling". Never seen it before!.

x =k * y^3/sqrt(z)
3 = k * y^3 /sqrt(12)
x = k * y^3/sqrt(75), solve for k, x, y
k =2.5,  x=0.34641  and  y^3 =6/5 =1.2. OR:

k=sqrt(12),  x =6/5 and   y^3 =3
Note : Somebody should check this! Thanks.

2.   2 cos^2(x) = 3 cos(x)     subtract  3cos (x) from both sides

2cos^2(x)  - 3 cos (x)  = 0       

cos (x)  [  2cosx - 3 ]  = 0

So

cos x  = 0.....and this occurs at  x=    pi/2   and   x = 3pi/2

Or

2cosx - 3  = 0

2cosx  = 3

cos x = 3/2     impossible

1. tan(-x) = tan(x)

Note that    tan (-x)  = -tan(x)....so we have

-tan (x)  = tan(x)          add tan (x) to both sides

0 =  2 tan x               divide both sides by 2

0  = tan x   ....   and this occurs at x = 0   and x  = pi

I won't give you the exact answers, but I will give you hints that you should use to EASILY solve them.

Remember:                 (ex: Sin(D)=\(\frac{9}{15}\Rightarrow\boxed{\frac{3}{5}}\))

Sine Ratio is \(\frac{Opposite}{Hypotenuse}\)

Cosine Ratio is \(\frac{Adjacent}{Hypotenuse}\)

Tangent Ratio is \(\frac{Opposite}{Adjacent}\)

Also remember:              (ex: Csc(D)=\(\frac{1}{\frac{3}{5}}\Rightarrow\boxed{\frac{5}{3}}\)

Secant is \(\frac{1}{Cosine}\)

Cosecant is \(\frac{1}{Sine}\)

Cotangent is \(\frac{1}{Tangent}\)

Lets say x=1

So now the question is : "What percent of 5 is equal to 1/5"

Multiply 5 by 20 so it is 100, it is easier to find the percentage when it is 100. Also multiply 1/5 by 100 too.

Now what percent of 100 is 4? 

The answer is obviosuly 4%

(x/5) / (5x) = 1/25 =0.04 x 100 =4%

You can keep a slow but constant pace and run 2 miles, it doesn't matter about the time

Because the sum goes on forever, we know that the sum from 5/9 on is 1, so 1 + 1 + 1 = 3

Sure.  Go for it.  Let us know how it goes.

I was able to get a pretty good score in math on the SAT just by studying from various AOPS textbooks. Khan Academy has also made a SAT practice that has problems in math that are similar to the ones on the test

There is a 1/2 probability that you took the first right path, then another 1/2 probability that you took the next fork correctly

1/2 x 1/2 = 1/4 probability that you took the correct path

You should use the addition method when there are two of the same amount of variables or in a situation where you could easily multiply one equation to get the same amount of variables in the other, like 2 equations both having 4x.

If it is hard, then just use substitution

2x + 4y = 8

4x + 6y = 14

I know this isn't a real linear function, but you can see that you can easily divide the second equation by 2 so that both equations have 2x, then you ocan do the addition method

5x + 3y = 18

17x + 7y = 3

Here, it would take more work to make either x or y be the same value, so you could do the substituion method.

To solve this problem, we can plug in the correct number to solve this problem.

Number N

So we can plug in 19 for the number n.

So our equation now is a19 = -2(19-3),

From this we can get 16*(-2) = -32. 

So our answer would be -32 

No we kind of dont, thats the whole point of "n". This is an arithmetic sequence problem, and we can use that to solve the problem. We do not always need the first number. All you have to do is plug in 19 as the value as n. Its that simple.

Let's see if I remember this......!!!!!

sin 45 / 13.5  = sin B '  / 18

sin B'  =  (18/13.5) sin 45

Take the sine inverse

arcsin [ (18/13.5) sin 45 ]   ≈  70.53....° 

But  this  angle is obtuse....so....its measure  =  109.47°

And since  we have an isosceles triangle on the right

Then angle B  is supplemental to 109.47  ≈   70.53°

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Yep.....looking at your other one right now