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Will you have time to help with 2 more questions?

Thank you!! 

r  =  sqrt (x^2 + y^2)

r^2  = x^2 + y^2

2^2   =  x^2 + y^2  

x^2 + y^2  = 4         [ a circle centered at the origin with a radius of 2 ]

Oops!!!!....round to  40.01°

Thank you!

We only need to  look at  elements  C₁₁ and B₁₁

C₁₁  - B₁₁   =   9 - 2  =   7

Only one resultant matrix  C - B  [ the last one ]  has  a "7"  in row 1, column 1

Also, thank you for helping!

So, the answer is only "40"? No decimal?

The guest has used the substitution method.....

And since  x  = -1

Then y  =  2(-1)  =  - 2

1/2 x 4 would equal 4/2. 4 divided by 2 is 2, so...

1/2 x 4 = 2

Angle B  =  180  - 26.8 - 32.5  =  120.7°

So....we can use the Law of Sines

b / sin 120.7  = 25 / sin 32.5       

b  =   25 * sin (120.7) / sin (32.5)  ≈  40

Symmetry about the line  θ  = pi / 2

[  In other words....the graph is symmetric about the y axis  ]

Moderate negative

[A  strong negative would be almost linear falling from left to right ]

y = 2x 

y = 3x + 1

I'm not certain what you're asking.  Solve for x?  Just set the two expressions equal.

                                                 3x + 1 = 2x

Subtract 2x from each side       3x – 2x + 1 = 2x – 2x

                                                   x + 1 = 0

Subtract 1 from each side           x + 1 – 1 = 0 – 1

                                                    x = –1

x = –1

We can use the Law of Sines, here

sin C / 14  =  sin (110) / 18      multiply both sides by 14

sin C  = 14 * sin (110)  / 18      take the sine inverse

arcsin  [ 14 * sin (110) / 18 ]  ≈    47°

For the first one, the coordinates given form a Hexagon that can be split into a rectangle and 2 triangles by cutting lines from (3,7) to (3,1) and from (7,7) to (7,1). The rectangle in the middle would have width of 4 and height of 6.

Therefore the area of the rectangle would be 4 x 6 = 24.

The height of one of the two triangles is 3 and the base is 6, so the area of one of the triangles is 3 x 6/2 = 9

Then we have to do the perimeter.

The side length of one of the legs of the triangles is 3\(\sqrt2\)

3\(\sqrt2\) x 4 (amount of legs) = 12\(\sqrt2\)

The width of the rectangle is 4, 4 x 2= 8

The total perimeter would then be 12\(\sqrt2\) + 8

First one......let's get the area...first.....the easiest way to do this one is to divide the shape up into two triangles and a rectangle, thusly :

Notice that the area of the triangle on the left  = base * height  / 2  = 6 * 3  /2  = 9 units^2

And....by symmetry....the triangle on the right has the same area......and the area of the rectangle  = 4*6 = 24 units^2

So....the area  =  9 + 9 + 24  =  42 units^2

Perimeter....note that we only need to find EF because  the outer sides of the triangles are all equal

So EF   = sqrt [ (3 - 0)^2 + (7 - 4)^2 ]  = sqrt [ 9 + 9 ]  = sqrt (18)  =  sqrt (9) *sqrt (2)  = 3sqrt(2)

So....we have   4 * 3sqrt (2)  =  12 sqrt (2)  units

And the top and bottom sides of the rectangle are 4 units each

So...the perimeter  =  4 + 4 + 12sqrt (2)   =   8 + 12sqrt(2) units

We are choosing any 6 of 11  = C(11,6)  = 462

The common ratio is 2....so....

Sum   =   first term  [ 1 - common ratio^7 ]   / [ 1 - common ratio ]  =

(1/2) [ 1 - 2^7 ] / [ 1 - 2 ]    =

(1/2) [ -127] / [ -1]  =

(1/2) (127)  =

63.5

5/26 *4/25

You will get the same answer

4x - y = 3    ⇒  y = 4x - 3   (1) 

2x + 3y = 19    (2)

Put  (1) into (2)  for y  and we have

2x + 3(4x - 3)  = 19       simplify

2x + 12x - 9  = 19

14x - 9  =  19       add 9 to both sides

14x  = 28     divide both sides by 14

x  = 2

And using (1)  y  =  4(2) - 3  =  5

Answer: 462.