Solution:
\(V = \pi * r^2 * h \pm \text {(error)}\\ \small \text {For this equation, the easiest method is to calculate each error as a decimal and }\\ \small \text {then use the sum of the decimals to calculate the error range.}\\ \large \text { }\\ \text {Gauss Error Function } \small \text { (uncertainties in decimal).}\\ r= 10 cm \pm 0.03\\ r_{error} = (2)\frac{0.03}{10} = 0.006\\ h= 20 cm \pm 0.05\\ h_{error} = \frac{0.05}{20} = 0.003\\ \small \text{sum of errors } = 0.006+0.003 = 0.009\\ V_{error} = 0.009 (6283.18) = \pm 56.54cm^3 \\ \large \text { }\\ V= \pi * 10^2 * 20 = 6283cm^3 \pm 56.54cm^3 \, | \,\small \text{68% confidence interval}\\ 6226.6cm^3 \leq V \leq 6339.7cm^3 \, | \,\small \text{68% confidence interval}\\ \)
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https://web2.0calc.com/questions/physics_81#r2
GA