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The mean is the average.....add all of the numbers ( there is 14 of them)

    add all of the numbers and divide by 14    to get the avereage(mean) ....you can do it !

One out of 6 chance you will roll a three    1/6

Probability of a 6    1 out of 6 chance   1/6

Probabilty of a 5                                    1/6

1/6 + 1/6 = 2/6 = 1/3

it is correct. I read your answer wrong. 

Find the lengths as follows:

how do you find the side lengths?

Calculate the area of the LARGE triangle...then subtrat the two smaller triangles.

You can calculate the angles of ADE.....find the hypotenuse....you are given two sides

    then you can calculate the angles FEB  CDG   etc

       Example : 180 - AED - 90  = FEB       to find the side lengths of those triangles and their areas......etc,,,

Or calculate the area AED and add the rectangle when you find the side lengths.....

A less confusing version of the problem:

Find all real numbers \(\frac{2}{3} t - 1 < t + 7 \le -2t + 15 \)

Find a linear inequality with the following solution set. Each grid line represents one unit.
 

(Give your answer in "standard form"  or  where   and  are integers with no common factor other than 1.)

Find a linear inequality with the following solution set. Each grid line represents one unit.

(Give your answer in "standard form"  or  where   and  are integers with no common factor other than 1.)

I do not think it should even be called a constant coefficient.  I think it is just a CONSTANT.

A coefficient is attached to a pronumeral, like in 3y  the 3 is the coefficient.

But a constant is by itself and usually tacked on the end. 

Thanks Chris,

That addition should be helpful :)

nvm, It does not work. it says it is wrong. SRRY

Thank you, I didnt really get what a "constant coefficient" was, but realized its basically the same thing as a coefficient.

\(\text{Just add up the constant terms...}\\ 3(-4) + 2(7) - 5(-1) = \\ -12 + 14+ 5 = 7\)

THX FOR the help

3x + 4y  = 15   ⇒  4y  = 15-3x    ⇒  y  =  [ 15 -3x ] / 4       (1) 

x^2 + y^2  = 9        (2)

Sub (1) into 2 for y  and we have

x^2  +  ( [15 - 3x ] / 4 )^2  = 9            simplify

x^2  + (1/16) ( 9x^2  - 90x + 225)  = 9          multiply through by 16

16x^2  + 9x^2 - 90x + 225  =  144

25x^2  - 90x  + 81  = 0         factor

(5x - 9) (5x - 9)  = 0

(5x- 9)^2  = 0         take the square root

5x  - 9  = 0      add 9 to both sides

5x  = 9      divide both sides by 5

x  = 9/5

And using (1)

y  =   [ 15 - 3(9/5) ] / 4   =  [ 15 - 27/5 ] / 4   =  [ 75 - 27 ]/ 20  =  48 / 20   =   12 / 5

So  the intersection point is  ( 9/5, 12/5)

I come up with the following:

the 75 degree angle between the two first chords is repeated until the endpoint is back to A

the ARC this angle encompasses is  2 * 75 = 150 degrees

Keep adding 150 degree shifts until the endpoint coincides with A:

The LCM of 150 and 360 degrees (which will bring us back to A) is 1800

    1800/150 = 12  angles which will require a total of 13 chords to complete

x^3 - 3x + 1   ≤  2x^2 + 4          subtract  2x^2 + 4 from both sides

x^3 - 2x^2 - 3x - 3  ≤  0

This would be difficult to solve algebraically....here is a graphical  solution : 

https://www.desmos.com/calculator/vep7c7esur

The graph shows that the solution is on the interval   (-infinity, ≈ 3.221 ]

10^n = 10^(-5) *  √ [ 10^73 / 0.001 ]

10^n  = 10^(-5) * ( 10^73 / 10 ^(-3) ) ^(1/2)

10^n =  10^(-5) * ( 10^76)^(1/2)  

10^n = 10^(-5) * 10^38

10^n = 10^33

n = 33

OK, Leo....!!!!

x^2 + y^2 + 2x - 4y - 8      complete the square on x and y

x^2 +2x + 1  + y^2 - 4y + 4   - 1   - 4      factor

(x + 1)^2   + (y - 2)^2   -   5

The minimum value of  -5    will be  achieved when x = -1  and y  = 2

Thanks, CPhill! :)

See my answer here:

 https://web2.0calc.com/questions/help_9450

thanks nevertheless

What is the value of n  such that  \(10^n = 10^{-5}\times \sqrt{\frac{10^{73}}{0.001}} \)?

\(n\cdot log 10 = log (\)\(10^{-5}\times \sqrt{\frac{10^{73}}{0.001}}\))

\(n=log(10^{-5}\cdot \sqrt{\frac{10^{73}}{0.001}})\\ n=log(10^{-5}\cdot10^{38})\\ n=log (10^{33})\\ \color{blue}n=33\)

  !
 

"Coplanar" means, that points are situated in one plane.

If you have a flat surface, like a soccer-field, and you mark random points on this soccer-field, the points will all be coplanar.

Anything that is above or below the soccer-field is not colplanar with the points that are on the soccer-field.

The picture you present shows the points A, B and R to be colinear. That means, they are all connected by a straight line. As they are connected by a straight line, they don't span up a plane. Thus they can't be coplanar, because you need any combination of the points A, B oder R and another point outside the line AB. Depending on which point other than A, B or R you choose, you will have a plane. All three points, A, B and R will be coplanar with that plane.