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Thank you!!!

\((a+b)^n = \sum \limits_{k=0}^n \dbinom{n}{k}a^k b^{n-k}\)

\(\left(x^2 + \dfrac 1 4 \right)^4 = \sum \limits_{k=0}^4 \dbinom{4}{k}(x^2)^k \left(\dfrac 1 4\right)^{n-k}\\ \text{The constant term appears when $k=0$}\\ \dbinom{4}{0}\left(\dfrac 1 4\right)^4 = \dfrac{1}{256} \)

Answer is 5 

p(1,-1) = 2

p(-5,-2) = -1

p(2,-1) = 5

....I used an online summation calculator to find that....

1  as x gets bigger so does 5^x  and so does the expression :  Growth

2 as x gets bigger so does (6/5)^x      Growth

3  As x gets bigger  3/8 ^x gets smaller    decay

if the number that is raised to the 'x' power is  greater than 1    growth

if the number is less than one    decay

~ 45.5     is what I find  

thanks

3*1  +4  + 4 *5  = 27

I think the 6/7   might be NEGATIVE  6/7

https://web2.0calc.com/questions/help_51380

A. \(30-\frac{30}{6}\). \(\frac{30}{6}=5\). \(30-5=25\). You have been posting a lot of problems. Why don't you post your attempts at solving next time. I am asuming this is for homework?

-KeyLimePi\(\pi\pi\pi\)

B. False. -3>-2 suggests that -3 is greater than -2 which is incorrect. A true statement would be -3 is a solution of y<-2.

-KeyLimePi\(\pi\pi\pi\)

I havent been able to uplode a image either.

Okay. Thank you. I was worried it was only my problem.

What do YOU think the answers are, MSW?

Yes ! it is C      try answering the others too...

Yah,,,,, website is not working again.....cannot upload imgaes....try again later 

By the way.... it's not all my questions and it's just some questions i have trouble in

is it C ?

You are posting a lot of homework -like questions.....tell us what YOU think the answer is, then we will help you out .....rather than just giving you answers...   

I don't know what you're doing but there's no way you can be asking questions about probability

when you don't know how to turn addition and multiplication into symbols.

Are you sharing the account among several people?

Are you just trying to produce an answer key to some test or study guide?

\(\text{The coefficient of $x^3$ is -1 times the sum of the roots}\\ \text{The constant term is the product of all the roots}\\ \text{Thus if the coefficients are rational and $\sqrt{2}+\sqrt{5}$ is a root then so must the following be roots}\\ -\sqrt{2}+\sqrt{5},~\sqrt{2}-\sqrt{5},~-\sqrt{2}-\sqrt{5}\)

\(\text{Using those 4 roots expand out $\prod \limits_{k=1}^4 (x-r_k)$ and find the coefficient of the $x^3$ term}\\ \text{This is the negative of $p(1)$ i.e. the sum of the coefficients of the quartic}\\ \text{You should get the sum is equal to $2\sqrt{5}$}\)

IT'S FOR MATH

if you have to ask about this question then just close your math book and go into politics

ONLY the radius, x , should be squared....NOT the 3.14

3.14 x^2