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Great - It's been lonely around here - DragonSlayer made sure we didn't get too lonely.

I bet he has missed the rest of the 'rat pack'!

Well done, Stu.......I will give points to you and Melody......it appears that we all believe that it's impossible....however.....a consensus of opinion was once the justification for believing that the Earth was flat, too!!....

LOL!!!!!

Yes Melody im back , i just reahed home!Sooo happy to be home!But i'll post my return on Sunday morning!For something special tomorrow!!!

Heaps of really cool stuff!!

Lots of stuff to do with rates of change and areas and volumes. (complicated ones)

Calculus is brilliant!

Rosala is back!

Mutiny on The Bounty !!!!.......or, I should say......."The Forum" !!!!

(I think the "Rats" just took the weekend off, really).......

Stu I expect your answer is the better intuitive approach but you have not shown where 1.619 came from.

So your 'proof' is only the germ of an idea.

No my approach was similar to yours only I had a page of Latex which I lost.

Without doing any maths it appears obvious that it will not be possible.

I'm sure that Alan will come up with a much more intuitive logic as to why this cannot be.

I do not intend to redo mine.

DragonSlayer not only you but all of us our RATS!Dont worry your not alone and btw we are all good rats !!

"Anybody else have a different approach???.......there might be a more common sense reasoning....or perhaps I could be incorrect!!" CPhill. 

Same approach but different tact.

Note: I got in there with the right answer first. 

Mmmm.....this is an interesting question.......I don't really know!!!...let's see what happens.....

V_s = V_c   ????

Let's find the length of the side of the cube that  will make the volumes equal.....

(4/3)*pi*r³ = s³       take the cube root of both sides.......

r*[(4/3)*pi]^1/3  = s

So this is the length of the side of the cube that makes the volumes equal.

Now let's solve for the length of the side of the cube that makes the areas equal.....

A_s = A_c      ????

4*pi*r²  =  6s²      divide by 6 on both sides

(2/3)*pi*r² = s²       take the square root of both sides

r*[(2/3)*pi]^1/2  = s

And that's the length of the side of the cube that makes the areas equal.

But...it appears that we have a contradiction here.......the length of side of the cube that makes the volumes equal isn't the same as the length of the side of the cube that makes the areas equal. And since our cube isn't a "flexible" one, it seems that the answer to the question is........no.....

Anybody else have a different approach???.......there might be a more common sense reasoning....or perhaps I could be incorrect!!

I just proved that this was impossible but the whole lot got delted on me.

I hate it when that happens!   

Also spell check ;) . Also super and subscript to not have to be so dificult to use then take off, ever single time.

Since some of these seem to be the application of the exponent rule .... (a^b)^c = a^bc ... I'm assuming that 56 might be:

(x^-4/7)⁷ =

x^-4

We can only guess, at this point.....!!!

an EXPONENT is superscript to the top right of a number, agebraic letter or brackets also know as an INDEX OR POWER. 4^{16. In this case it is the 16.} It can also included everything that apears in the position of the 16 such as

4^{n/4 where n is representinga value.}

Good evening Sasini,

Multiply and divide are equally important  and the multiply comes first so that is the one that should be done first. 

It actually won't make any difference to this answer but technically that is how it is.

$$50*6/10-6+36\\
= 300/10-6+36\\
=30-6+36\\
=24+36\\
=60$$

This solving has a method .

1. st we sove the brackets
2. nd we devide
3. re one is mutipy
4. last one is add & substract

I am sorry but this is not a question.  You need to be more specific!  

Sunday 3/8/14

Rosala's back!   

@@ End of Day Wrap :    Sat 2/8/14     Sydney, Australia     Time 9:50pm        ♬                       

Hello everyone,        ♫♪

There were not many questions today but there were some good answers from CPhill, DragonSlayer554, AzizHusain and NinjaDevo.  Thank you.  

Today I referred an asker to a previous question that I pulled from NinjaDevo's new thread "Great answers to Learn from"    Thanks Ninja.  

It would be really good if all answerers made themselves very knowledgable about the contents of Ninja's 2 sticky threads. "Great answers to Learn from" and "Reference Material".  They are invaluable and they should be used regularly.                                 ♪ ♫ 

Now for the interest threads:

A treason plot has been uncovered!     

Dragon will you quit bringing up really old threads just so that you can post on them.

If you don't I will rip your head of with my very sharp teeth!

Go to this thread for new people