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it would be B. Ideally it would be 10/52

First one.....we have 52  candies....10 are red.....can you find the answer  ????

Second one

Midpoint  [ (-3 + 3)/2 , (3 + 0)/2) ]  =  ( 0, 1.5)

Distance from  pool to tennis courts   =

sqrt  [ ( -3 - 0)^2 + (1.5 - 3)^2 ] = 

sqrt [ 9 + 2.25)  = 

3.35 miles

(2x^2 + 7x + 6) / (x^2 + x - 6)

_________________________   =

(4x^2 - 9)  / ( x^2  - 5x + 6)

(2x^2 + 7x + 6)           (x^2 - 5x + 6)

_____________  *     ___________      =

   (x^2 + x - 6)               (4x^2  - 9)

(2x  + 3) ( x + 2)            (x - 2) ( x - 3)

_____________   *      ______________    =

(x + 3) ( x - 2)               (2x + 3) ( 2x - 3)

(x + 2) (x - 3)

___________   You are correct  !!!

(x + 3)(2x - 3)

1)   This is known  as the Intersecting Chord Theorem....

We have that   

3 * 5  =  4 * x            divide both sides by 4

15 / 4   =  x     =   3.75

2)  B) m∠TPS = m∠RPQ

3) E) ∠ BAD ≅ ∠BED

If 99%  are tetras.....then  .99 * 200  =  198 are tetras  

Let N be the number of tetras to be removed....so

[ 198 - N  ] / [ 200 - N ]  =  .98      cross-multiply

198 - N  =  .98 [ 200 - N ]

198 - N =  196 - .98N        Add N to both sides......subtract 196 from both sides

2  =  .02N                     Divide both sides by  .02

100 = N  =  the number to be removed

Proof

[ 198 - 100 ] / [ 200 - 100]  =

98 / 100   =   .98  = 98%

1) sin B

2) We have two rectagles, here....one  is a 5 x 4 rectangle  and the other is a   15 x 3 rectangle

So.....thetotal area  is  ( 5 x 4)  + (15 x 3)   =  (20) + ( 45)  =   65 yards^2

3)  We have a right triangle  with legs of 3 and 6

The hypotenuse    = sqrt  (3^2 + 6^2)   =  sqrt ( 9 + 36)  =  sqrt (45)  ≈  6.7 units

So the perimeter  =  3 + 6 + 6.7  ≈   15.7 units

I am pretty sure that you have to assume z = a+bi and then plug it into the equation to solve it.

Point taken!

Thanks!

Now I know I failed the bonus question on my test

yeppers!

200 (.99)    number of tetras originally    now subtrac x from that number

200(.99) - x       the TOTAL number of fish also gets decreases to 200 - x

The tetras remaining in the tank   200(.99) - x

    divided by the total number of fish  200- x   = 98 %

[200(.99) - x ] / (200-x) = .98     solve for 'x' the number of tetras to remove....  

2.  just add the precentages, cus thats all it wants, so 18 + 35 = 53

(p,q,r) = (1,4,-11)

1  Then you will have to add that percentage and the percentage 10000-14999 together

2 Correct

1. yes

2. A

Sorry that is wrong

1   What about the portion of the circle labelled 'Under 10,000'   Isn't this less than 15000 too?

2   2 would be the people who take CALCULUS and statistics only.....we want Number theory and Statistics only.......?

1. E

2. B

Venn digram....   what number is shown where ONLY the Statistics  and  Number theories overlap each other?

  What do you think?

Look at the circle graph and add the percentages that represent less than $ 15, 000 .....what do you get?

B) $3,600.

I believe your question states Barbara is 76....is that correct?

   Can you clarify your question....it makes no sense as written......

The graph shows that 18% of the total is spent on food....

                                    18% of 20000 = what?

       18% / 100%    x 20,000 = ? 

Let A = (a,b), B = (c,d), and C = (e,f).  Use perpendicular bisectors to compute the center of the circumcircle of ABC.  The computations are really easy.