Thankns Ninja,
OR you could just copy it into the site calculator!
$${\frac{{\left({\mathtt{4}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{5}}}\right)}^{{\mathtt{2}}}{\mathtt{\,\times\,}}\left({\mathtt{2.63}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{17}}}\right)}{{\mathtt{6.7}}}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{3}}} = {\mathtt{62\,805\,970\,149.253\: \!731\: \!343\: \!283\: \!582\: \!1}}$$
If I was going to do it more by hand. I'm sure this is the same as Ninja, just presented a little differently.
$$\\\frac{(4 \times 10^{-5})^2(2.63 \times 10^{17})}{6.7} \times 10^3\\\\
\frac{16 \times 10^{-10}\times 2.63 \times 10^{17}}{6.7}\times 10^3 \\\\
\frac{16 \times 2.63}{6.7}\times 10^{
(3-10+17)} \\\\
6.28060\times 10^{
10} \qquad \mbox{Correct to 6 significant figures}\\\\$$
One of us has made a mistake Ninja. Can you find it?
I found it - you put 10^3 on the bottom and I put it one the top.
Both interpretations are valid. That is why people need to use brackets (properly)!