All Answers 352701 Answers

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Hi there...

I'm seriously starting to feel like the boy who cried wolf.
But anyway, here is more proof to prove my point...

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Nr.01. = (1.1)=(x) , x=(1.1) 
Nr.02. = (1.11)=(x) , x=(1.11) 
Nr.03. = (1.111)=(x) , x=(1.111) 
Nr.04. = (1.1111)=(x) , x=(1.1111) 
Nr.05. = (1.11111)=(x) , x=(1.11111) 
Nr.06. = (1.111111)=(x) , x=(1.111111) 
Nr.07. = (1.1111111)=(x) , x=(1.1111111) <<--(The highest/lowest value before the calculator starts acting up.) 
Nr.08. = (1.11111111)=(x) , x=(1.111111109999999899999990999999189999927099993438999409509947) 
Nr.09. = (1.111111111)=(x) , x=(1.111111111000000033999989596003183623025811354101725644871953) 
Nr.10. = (1.1111111111)=(x) , x=(1.111111111100000042939834054717312139475505782960351171426863) 
Nr.11. = (1.11111111111)=(x) , x=(1.111111111110000054733903646988672615840246218900933056468895) 
Nr.12. = (1.111111111111)=(x) , x=(1.111111111110999924331163114504424459963040074298586753464506) 
Nr.13. = (1.1111111111111)=(x) , x=(1.111111111111100058224110397027914373688492606069121342691441) 
Nr.14. = (1.11111111111111)=(x) , x=(1.111111111111111111111111111111111111111111111111111111111111) 
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Nr.01. = (2.2)=(x) , x=(2.2) 
Nr.02. = (2.22)=(x) , x=(2.22) 
Nr.03. = (2.222)=(x) , x=(2.222) 
Nr.04. = (2.2222)=(x) , x=(2.2222) 
Nr.05. = (2.22222)=(x) , x=(2.22222) 
Nr.06. = (2.222222)=(x) , x=(2.222222) 
Nr.07. = (2.2222222)=(x) , x=(2.2222222) <<--(The highest/lowest value before the calculator starts acting up.) 
Nr.08. = (2.22222222)=(x) , x=(2.222222219999999599999927999987039997667199580095924417266395) 
Nr.09. = (2.222222222)=(x) , x=(2.222222222000000067999979192006367246051622708203451289743905) 
Nr.10. = (2.2222222222)=(x) , x=(2.222222222200000085879668109434624278951011565920702342853726) 
Nr.11. = (2.22222222222)=(x) , x=(2.22222222222000010946780729397734523168049243780186611293779) 
Nr.12. = (2.222222222222)=(x) , x=(2.222222222221999848662326229008848919926080148597173506929012) 
Nr.13. = (2.2222222222222)=(x) , x=(2.222222222222200116448220813846771137549073306993425803191007) 
Nr.14. = (2.22222222222222)=(x) , x=(2.222222222222222222222222222222222222222222222222222222222222) 
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Nr.01. = (3.3)=(x) , x=(3.3) 
Nr.02. = (3.33)=(x) , x=(3.33) 
Nr.03. = (3.333)=(x) , x=(3.333) 
Nr.04. = (3.3333)=(x) , x=(3.3333) 
Nr.05. = (3.33333)=(x) , x=(3.33333) 
Nr.06. = (3.333333)=(x) , x=(3.333333) 
Nr.07. = (3.3333333)=(x) , x=(3.3333333) <<--(The highest/lowest value before the calculator starts acting up.) 
Nr.08. = (3.33333333)=(x) , x=(3.333333329999999799999987999999279999956799997407999844479991) 
Nr.09. = (3.333333333)=(x) , x=(3.333333333000000119999956800015551994401282015538474406149214) 
Nr.10. = (3.3333333333)=(x) , x=(3.33333333330000014526936690157210625860371437915236421608151) 
Nr.11. = (3.33333333333)=(x) , x=(3.333333333330000147753950340726203737731783264851668165525808) 
Nr.12. = (3.333333333333)=(x) , x=(3.333333333332999970366472796378650719760884823291352809948811) 
Nr.13. = (3.3333333333333)=(x) , x=(3.333333333333300174672331191083743121065477818207364028074322) 
Nr.14. = (3.33333333333333)=(x) , x=(3.333333333333333333333333333333333333333333333333333333333333) 
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Nr.01. = (4.4)=(x) , x=(4.4) 
Nr.02. = (4.44)=(x) , x=(4.44) 
Nr.03. = (4.444)=(x) , x=(4.444) 
Nr.04. = (4.4444)=(x) , x=(4.4444) 
Nr.05. = (4.44444)=(x) , x=(4.44444) 
Nr.06. = (4.444444)=(x) , x=(4.444444) 
Nr.07. = (4.4444444)=(x) , x=(4.4444444) <<--(The highest/lowest value before the calculator starts acting up.) 
Nr.08. = (4.44444444)=(x) , x=(4.444444439999998399999423999792639925350373126134325408357147) 
Nr.09. = (4.444444444)=(x) , x=(4.444444444000000127999963136010616828942353264602259794549179) 
Nr.10. = (4.4444444444)=(x) , x=(4.444444444400000171839335600392834641144143480283647831304025) 
Nr.11. = (4.44444444444)=(x) , x=(4.444444444440000218936414509139666511511883408706210896887841) 
Nr.12. = (4.444444444444)=(x) , x=(4.444444444443999697324652458017697839852160297194347013858024) 
Nr.13. = (4.4444444444444)=(x) , x=(4.444444444444400232896441706857311835573876860928474772052722) 
Nr.14. = (4.44444444444444)=(x) , x=(4.444444444444444444444444444444444444444444444444444444444444) 
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Nr.01. = (5.5)=(x) , x=(5.5) 
Nr.02. = (5.55)=(x) , x=(5.55) 
Nr.03. = (5.555)=(x) , x=(5.555) 
Nr.04. = (5.5555)=(x) , x=(5.5555) 
Nr.05. = (5.55555)=(x) , x=(5.55555) 
Nr.06. = (5.555555)=(x) , x=(5.555555) 
Nr.07. = (5.5555555)=(x) , x=(5.5555555) 
Nr.08. = (5.55555555)=(x) , x=(5.55555555) <<--(The highest/lowest value before the calculator starts acting up.) 
Nr.09. = (5.555555555)=(x) , x=(5.555555554999999724999863874932618091645955364747905550213247) 
Nr.10. = (5.5555555555)=(x) , x=(5.555555555499999797999265525329450097880555893701229497670454) 
Nr.11. = (5.55555555555)=(x) , x=(5.555555555549999856991318827838815516166320085628692159602011) 
Nr.12. = (5.555555555555)=(x) , x=(5.555555555555000235705080161396932197211516024862172170290504) 
Nr.13. = (5.5555555555555)=(x) , x=(5.555555555555500291120551985139571868442463030345606713457203) 
Nr.14. = (5.55555555555555)=(x) , x=(5.555555555555555555555555555555555555555555555555555555555556) 
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Nr.01. = (6.6)=(x) , x=(6.6) 
Nr.02. = (6.66)=(x) , x=(6.66) 
Nr.03. = (6.666)=(x) , x=(6.666) 
Nr.04. = (6.6666)=(x) , x=(6.6666) 
Nr.05. = (6.66666)=(x) , x=(6.66666) 
Nr.06. = (6.666666)=(x) , x=(6.666666) 
Nr.07. = (6.6666666)=(x) , x=(6.6666666) <<--(The highest/lowest value before the calculator starts acting up.) 
Nr.08. = (6.66666666)=(x) , x=(6.666666659999999599999975999998559999913599994815999688959981) 
Nr.09. = (6.666666666)=(x) , x=(6.666666666000000239999913600031103988802564031076948812298428) 
Nr.10. = (6.6666666666)=(x) , x=(6.666666666600000290558733628815352171169097176606865476637507) 
Nr.11. = (6.66666666666)=(x) , x=(6.666666666660000295508100663722320397511401443044780451224098) 
Nr.12. = (6.666666666666)=(x) , x=(6.666666666665999940732947593112919566590446985028535318440817) 
Nr.13. = (6.6666666666666)=(x) , x=(6.666666666666600349344662401958428632314856071963223225326607) 
Nr.14. = (6.66666666666666)=(x) , x=(6.666666666666666666666666666666666666666666666666666666666667) 
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Nr.01. = (7.7)=(x) , x=(7.7) 
Nr.02. = (7.77)=(x) , x=(7.77) 
Nr.03. = (7.777)=(x) , x=(7.777) 
Nr.04. = (7.7777)=(x) , x=(7.7777) 
Nr.05. = (7.77777)=(x) , x=(7.77777) 
Nr.06. = (7.777777)=(x) , x=(7.777777) 
Nr.07. = (7.7777777)=(x) , x=(7.7777777) <<--(The highest/lowest value before the calculator starts acting up.) 
Nr.08. = (7.77777777)=(x) , x=(7.777777769999999299999936999994329999489699954072995866569628) 
Nr.09. = (7.777777777)=(x) , x=(7.777777776999999831999963711992161790306946706300488560905529) 
Nr.10. = (7.7777777777)=(x) , x=(7.777777777699999840119671349996427052655449438541865866659476) 
Nr.11. = (7.77777777777)=(x) , x=(7.777777777769999856810263909892220416502657118121933487627463) 
Nr.12. = (7.777777777777)=(x) , x=(7.777777777776999579969779793322925192433322629789790523087688) 
Nr.13. = (7.7777777777777)=(x) , x=(7.77777777777770034177777877372739638896828809824198768928826) 
Nr.14. = (7.77777777777777)=(x) , x=(7.777777777777777777777777777777777777777777777777777777777778) 
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Nr.01. = (8.8)=(x) , x=(8.8) 
Nr.02. = (8.88)=(x) , x=(8.88) 
Nr.03. = (8.888)=(x) , x=(8.888) 
Nr.04. = (8.8888)=(x) , x=(8.8888) 
Nr.05. = (8.88888)=(x) , x=(8.88888) 
Nr.06. = (8.888888)=(x) , x=(8.888888) 
Nr.07. = (8.8888888)=(x) , x=(8.8888888) <<--(The highest/lowest value before the calculator starts acting up.) 
Nr.08. = (8.88888888)=(x) , x=(8.888888879999993599995391996682237611211080071977651823909313) 
Nr.09. = (8.888888888)=(x) , x=(8.888888888000000255999926272021233657884706529204519589098358) 
Nr.10. = (8.8888888888)=(x) , x=(8.88888888880000034367867120078566928228828696056729566260805) 
Nr.11. = (8.88888888888)=(x) , x=(8.888888888880000437872829018279333023023766817412421793775683) 
Nr.12. = (8.888888888888)=(x) , x=(8.888888888887999394649336959635485774688130313806357927256895) 
Nr.13. = (8.8888888888888)=(x) , x=(8.88888888888880046579288373036970191134969764980122776329503) 
Nr.14. = (8.88888888888888)=(x) , x=(8.888888888888888888888888888888888888888888888888888888888889) 
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Nr.01. = (9.9)=(x) , x=(9.9) 
Nr.02. = (9.99)=(x) , x=(9.99) 
Nr.03. = (9.999)=(x) , x=(9.999) 
Nr.04. = (9.9999)=(x) , x=(9.9999) 
Nr.05. = (9.99999)=(x) , x=(9.99999) 
Nr.06. = (9.999999)=(x) , x=(9.999999) 
Nr.07. = (9.9999999)=(x) , x=(9.9999999) <<--(The highest/lowest value before the calculator starts acting up.) 
Nr.08. = (9.99999999)=(x) , x=(9.99999998999999919999993599999487999959039996723199737855979) 
Nr.09. = (9.999999999)=(x) , x=(9.999999998999999917999993275999448631954787820292601263993304) 
Nr.10. = (9.9999999999)=(x) , x=(9.999999999899999991729999316070943439067022410842753376695704) 
Nr.11. = (9.99999999999)=(x) , x=(9.9999999999900008873510538231775908275207451430641839579843) 
Nr.12. = (9.999999999999)=(x) , x=(9.999999999998999911099418389135952159282654469874058429846432) 
Nr.13. = (9.9999999999999)=(x) , x=(9.999999999999900524016993593042171753382302613619473966180804) 
Nr.14. = (9.99999999999999)=(x) , x=(10) 
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To summarize...:
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Nr.07. = (1.1111111)=(x) , x=(1.1111111) <<--(The highest/lowest value before the calculator starts acting up.) 

Nr.07. = (2.2222222)=(x) , x=(2.2222222) <<--(The highest/lowest value before the calculator starts acting up.) 
Nr.07. = (3.3333333)=(x) , x=(3.3333333) <<--(The highest/lowest value before the calculator starts acting up.) 
Nr.07. = (4.4444444)=(x) , x=(4.4444444) <<--(The highest/lowest value before the calculator starts acting up.) 
Nr.08. = (5.55555555)=(x) , x=(5.55555555) <<--(The highest/lowest value before the calculator starts acting up.) 
Nr.07. = (6.6666666)=(x) , x=(6.6666666) <<--(The highest/lowest value before the calculator starts acting up.) 
Nr.07. = (7.7777777)=(x) , x=(7.7777777) <<--(The highest/lowest value before the calculator starts acting up.) 
Nr.07. = (8.8888888)=(x) , x=(8.8888888) <<--(The highest/lowest value before the calculator starts acting up.) 
Nr.07. = (9.9999999)=(x) , x=(9.9999999) <<--(The highest/lowest value before the calculator starts acting up.) 
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Pretty much on average that means 8 digits or 1 Whole/Natural single digit number followed by 7 decimals.
Out of 60 digits or 1 Whole/Natural single digit number followed by 59 decimals, functionality claimed by the maker(s) of this calculator.
That's a huge discrepancy...
One which I really wish that they would fix.
But I'm getting the feeling that they don't seem to care.

Seeing that when I tried to make them aware of this before, they just quoted me their disclaimer.
Which in turn makes the "Report a problem"-function a simple gimmick and as such pretty useless.

Logically...
With a function like "Report a problem", one would naturally expect them to want feedback.
Especially when something clearly seem to be wrong somewhere/somehow.

 

Kind regards

BizzyX

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If I understand the question correctly, I have a different answer.

Given these points  A = (0,0)  B = (1,0)  C = (1,1)  D = (0,1)

The first line segment will go from point A to point X on BC with X = (1,¾).

Using the distance formula, this distance is 5/4.

The next line segment will go from point X to point Y or CD with Y = (2/3,1).

This distance is 5/12.

The next line segment will go from point Y to point Z on AD with Z = (0, ½).

This distance is 5/6.

The next line segment will go from point Z to point W on AB with W = (2/3,0)

This distance is 5/6.

The next line segment will go from point W to point V on BC with V = (1, ¼).

This distance is 5/12.

The next line segment will go from point V to point D (a vertex).

This distance is 5/6.

Adding these distances together:  5/4 + 5/12 + 5/6 + 5/6 + 5/12 + 5/4  =  5.

H = .75 K

H+30 = .8 (1.25K)          since  H = .75K   substitute this in

.75K + 30 = .8(1.25K)

.75K + 30 = K

.25K = 30

K = 120            then     H = .75K = 90       YOU should check these answers.....are they correct?   WHat do YOU think?

                              If you add 25  to H    does it equal    80% of 1.25 K    ?  

3log₂6  =  log₂6³  =  log₂216

2  =  log₂4

So:  3log₂6 - 2  =  log₂216 - log₂4  =  log₂(216/4)  =  log₂54

Great, thanks!

You calculated that 2/5^ths of the swim team are boys.

This means that 3/5^ths of the swim team are girls.

Which I think is correct.

Ok I see your answer now, I have commented and asked another question.  Thanks. :) 

Thanks very much peerless cucumber.

As EP has pointed out it does not fit with your original one.

You need a graph that goes through (0,0)  and goes down from that point. 

Try the others and see which one works..  

According to the Henderson Hassleback equation

pH = pka+log ([A-]/[HA])

     _{Does that get you started?} 

That is not the graph pictured in your question now is it?    You have the amplitude correct.....but look at the origin....something is amiss there, no?

    what can you do to flip a sine wave?

When the ball hits the ground    h will be = 0

h(t) = -16t^2 + 64t + 80

0 = h(t) = -16t^2 + 64t + 80      Solve for 't' using Quadratic Formula   

     One answer provided by the Quad Form will be -1    ......you want the POSITIVE  answer for 't'

21  P 3 = 7980

21 x 20 x 19 =  7980 ways

No you didn't answer my most recent question yet.

I asked you for a link to your graph that you said you drew.

You have not yet answered my last question on this thread either.  I asked you for the equation of the x axis.  It was #13 on this thread.

I answered.

Solution:

This is an elementary physics question. Use the formula below, relating the physical constants of the material property to the variable properties of a circuit conductor (wire).

\({}\)

\( \Large G=\sigma \frac {A}{l} \qquad|\qquad \small \text{Where G = conductance, σ =conductivity, A = cross-sectional area, and l = length of the conductor. }\\ \)

\(\text {Rearrange to solve for (l).} \\ \)

Note: In your post, you list the conductivity of the copper (wire) as 5.80E8. This value is more than nine (9) times higher than pure silver (wire) and almost 10 times higher than pure copper (wire).  

GA

f(x)=1/2 cos x  graphed

What exactly do you need help with? You were provided with a full answer on how to do this! 

I had another question for you here too.

Sorry, but I feel like LaTeX is really hard to read when its not converted.

Yes everythign you just said is correct.

So what is the equation of the line do you think.  (Look at the last examples if you are still confused)

The formula of the volume. a square pyramid is \(V=a^2\frac{h}{3}\) when \(a\) is the base edge and \(h\) is the height. Putting the numbers into the formula gets us \(V=7^{2}\frac{14}{3}\). Computing this we get \(49 \cdot \frac{14}{3}\) \(\to \frac{686}{3}\). \(\frac{686}{3}\approx228. \overline{6}\). 

I also contacted Geno for advice. :D

A = (-4, 0)

B = (0, 0)

C = (1, 0)

D = (3, 0)

E = (10, 0)

Are these correct? If so, I'm notice they're all on the same line, their Y is ultimately 0.