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would it be 50pi - 96

Those were correct! Thank you!

Well....YOU do the math and tell me.....I try not to give answers only.....you can do it very easily.....

s =server

Salad = s+5

chef =  s +   s + 5           summed = 70

s     + s+5       +    s + s+5    = 70     solve for server, s       then salad = s+5       chef = 2s+5  

what would it equal if you subtract those

Sold 2/7     then   5/7 are left                     1/2 sold means   1/2 left

o =  t +120

5/7 t = 1/2 (t+120)     solve for t       ( then o = t +120)

*** see above ***

The factors of 33 are 1,3,11,33

The factors of 93 are 1,3,31,93

Area of a circle = pi r^2

area of the semi circle = 1/2 pi r^2

area of the triangle to subtract from the semi circle area = 1/2  b h =  1/2  12  16

1/2 pi 10^2   -    1/2 *12 *16 = blue area

Yeah. The problem was poorly worded. It depends on whether he meant 1/3  of what was left, or 1/3 of all his cards.

Well... I don't think any of them are the "safest". It just depends on what Anti-Virus software you use. I personally use McAfee and MalwareBytes Premium. I just use Google Chrome, because... i'm used to it.

You might have to check this for me. Idk if this is correct:

(1) There are 11 balls in total, with 8 white and 3 red.

First ball: You have a 8/11 chance of the first ball being white, and a 3/11 chance of it being red.

Second ball: This depends on what you drew on the first ball. If you drew a white first, you now have a 7/10 chance of getting white.

Total probability for both white: 8/11 * 7/10 (since both are independent events) = 28/55.

(2) There are 11 balls in total, with 8 white and 3 red.

First ball: You have a 3/11 chance of being red.

Second ball: If you drew red the first time, you now have a 2/10 chance of it being red.

Total probability for both red: 3/11 * 2/10 = 3/55

(3) I don't really know how to do this, can someone solve this?

@geno3141 your 2nd probability is wrong, should be 5/66 *4= 20/66=10/33, instead of 2/33

For this problem, we can use complementary counting. We can count the ways to find 4 pennies and 3  pennies and 1 nickel and subtract it from the total.

For 4 pennies, it is 5/11*4/10*3/9*2/8 which equals 1/66. 

For 3 pennies and one nickel, it is 5/11*4/10*3/9*6/8 which equals 1/22. There are 4 ways to do this, so the probability is 4/22.

When we add the probabilities, 1/66+4/22=13/66. We subtract this from 66/66 to get 53/66

Melody, I actually finished the problem and just forgot to tell you, and I got the same answer. Thanks for your imput though!! 

The three vertices of the triangle are (-15/2, 0), (k, 0) and (k, 2k/3+5)

Hence base length b = k + 15/2 and height h = 2k/3 + 5

Calculate area from (1/2)bh and set equal to 20 to find the highest possible k.  Take the floor value of the result as k is an integer. The lowest value of k is -7 since k must be greater than -15/2.

Hence determine the possible integer values of k and sum them.

Pythagorean theorem says

d²  +    (d+7)²   = 17²

d^2 + d^2 + 14d + 49 = 289

2d^2 + 14d -240 = 0      Quadratic formula yields d=8     or -15 (throw out)

8 + 7 = 15 = height

n = necklaces         amount of gold in necklaces = 16n

b = 7-n                    amount of gold ib bracelets = 6 (7-n)         summed = 72 grams

16n        +        6(7-n)          = 72        solve for 'n' the number of necklaces , then bracelets = 7-n   

isosceles triangle   means two legs are the same length     and base is 1/12 as long as leg

x = leg length

x + x  + x/12  =63     solve fo 'x' the leg length    then base = x/12

See https://web2.0calc.com/questions/find-the-sum_5#r2

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