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1/2 hours   + 1/3 hours  = 1/combined hours

3 /6  + 2/6  = 5/6 = 1/combined hours

  combined hours = 6/5 hour  = 1  1/6 hour       (1 hour 10 minutes)

Law of cosines

a^2 + b^2 - 2ab cos(theta) = c^2

2050^2 + 3000^2 - 2 (2050)(3000)cos (theta) = 1420^2      theta in this will be the angle between the highway and your line of sight to the first tower

                                                                                                  in a right triangle....the angle you want is 180-90-theta

theta = 24.57

180-90-24.57  = 65.4^o

sorry that is wrong D:

The probability is 1/5.

There are 4^4 = 256 ways of disitributing the balls.

Sicne FR has the same length as FG, arc RG is equal to arc FG.  Then arc RG is 130, so angle RPG is equal to (130 - 28)/2 = 51 degrees.

The probability that Larry chooses a 7 is 28/297.

No, that is incorrect. Although it does seem reasonable and they add up to 360, one half of 36 doesn't equal a third of 72, etc. 

Unless, of course, you can prove me wrong.

Distance is same for both

rate x time = distance

kathy rate = Cheryl rate + 2

(c+2) 5.4 = c 9.    Solve for c. Cathy speed.    Then Kathy speed= c+2

Let x= Cheryl's speed 

Then, x+2 = Kathy's speed

Distance = (Rate)(Time)

5.4(x+2) = 9x

5.4x + 10.8 = 9x

           3.6x = 10.8

               x = 3

Cheryl's speed is 3 mph and Kathy's speed is 5 mph.

- charis :)) ur welcome !

9 people to choose from (Mark is excluded)

9 c n    Where n is the number of people on the committee

8 out of 13 ml is compound B

8/13  x  1287 = ........ ml of B needed

btw.....THAT is an enormous number of kcal per day!!!!    You sure it isn't  just Cal?

We want the angles to form an arithmetic progression, so they are 36, 72, 108 144 degrees.  The largest angle is then 144 degrees.

5.5 x 10⁵  kcal/person day   /  3.7x 10⁶ kcal/bbl  =.......   bbl /person day x 365 days / year=  ......bbl/person-yr

There is no way that you can get a median smaller than 83 (two numbers smaller than 83 will give a median of 83).

Also, there is no way that you can get a median larger than 94.

But, you can choose numbers so that you get each of the numbers between 83 and 94.

So, there are 12 possible final medians.

Nope, I've tried but nope...