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(u + 2v)*w = -7, (w - u)*v = -6, (3v - 2w)*u = 9.

The other integer is 55.

thank you! :)

foley has run 12 km    and edith has run 16 km       if   edith had run 1/2 of the 16.... 8km     foley would have only covered 6 km

edith will run the remaining 8 km foley will still have 6 km to go  .

Answer is:

\(y=6x-5\)

WHAT sphere?  

you are welcome!   

6s +3t = 79.50

3s +2t = 41            we are looking for shirt price so let's eliminate t's     multiply second eq by -1.5

-4.5s -3t = -61.5     and add  to the first equation

1.5 s      = 18

s= $ 12

Thank you so much!!! These are the same answers that I got, but I wanted to double check! :D Thank you for your help ElectricPavlov! 

y = mx + b

y = y coordinate

x = x coordinate

m = slope

plug n' solve

150/1700 x 100% = 8.82 %

150 is 8.82 % of  1700

750/1700 x 100% = 44.12%

750 is 44.12% of 1700

Thanks Heureka and Tiggsy.

Now I have some homework   

An easy way is to assume that you play a certain number of games, say 100.

Since you have finished 75% of the season, you have played 75% of 100 games, which is 75 games.

You have won 40% of these 75 games; so, you have won 40% of 75 games, which is 30 games.

You want to end the season with same number of wins as losses, which would be 50 games.

Therefore, you will need to win 50 - 30 = 20 games.

Since there are only 25 games left, you will need to win 20 / 25  =  0.80  =  80% of your remaining games.

[No matter how many games you assume that you play in a season, this percentage will remain the same.]

Let the width (perpendicular to the wall) of the rectangular area be X. There are two of these widths.

The length of the fence will then be  132 - 2X.

The area becomes:  Area  =  X(132-2X).

It can be shown that this produces a maximum area when X = 33.  (Use calculus; first derivative.)

Place this value back into the Area equation to find the area.

Together Jay and Kay brought 2.00 + 1.75  = 3.75 gallons.

To divide it equally among the three persons, each person will get 3.75 / 3  = 1.25 gallons.

Jay will give up 2.00 - 1.25  =  0.75 gallons (and keep 1.25 gallons).

Kay will give up 1.75 - 1.25  =  0.50 gallons (and keep 1.25 gallons).

Together, Jay and Kay will give up 1.25 gallons.

Jay gave up 0.75 gallons which is 0.75 / 1.25  =  0.60  or  60%.

Kay gave up 0.50 gallons which is 0.50 / 1.25  =  0.40  or  60%.

So, Jay should get 60% of the $2.00  --->   0.60 x $2.00  =  $1.20.

Kay should get 40% of the $2.00        --->   0.40 x $2.00  =  $0.80.

That is a good observation guest.    

Let CD be x units in length and let the height be h

so what is BC?

what is DE?

You need to find    AreaACD = xh/2

Set up formulas for the two areas that you know.

Solve them simultaneously to find the value of xh 

Note: you probably can solve for x and h independently but it is easier to find the value of xh

Josh=4x-9

Jenny=x

51=Josh+Jenny

51=4x-9+x

51=5x-9

60=5x

x=12

Jenny has 12 fruit chews

Thanx GA....missed the 1/2 as long part  !!!!!  

I apologize !!!!!

the voltage increased 5 times   and the resistance is cut in half    so the current will increase   5 x 2 times

10 x 200 = 2000 mamps   

D'Oh !  

rate * time = distance

distance to and from is the same

r * 6.4   = 2d        or      r * 3.2 = d

d/(r-50) + d /(r+50) = 6.667         (I changed the minutes to hours)

3.2r /(r-50)  + 3.2r (r+50) = 6.667

3.2r (r+50) + 3.2r ( r-50) = 6.667 ( r+50)(r-50)

3.2 r^2  + 160r   + 3.2r^2  - 160r  =  6.667 r^2 -16667.5

-.2667 r^2 + 16667.5 = 0                   quadratic formula shows x = 250 m/hr

250 m/hr x 6.4 hrs = roundtrip distance = 1600 miles       800 miles one way

Actually, it is wrong, EP.

The voltage increased five (5) times, and because the wire is now half as long, the resistance is now 125 ohms

or (1/2 * 250) ohms. This means (2) amps or (2000) miliamps of current now pass through the wire. 

GA

i know! that's what i entered lol and it was marked wrong

20 t * 36 m / 4800 ft^2 = .15 t m /ft^2

.15 t m / ft^2    *  3600 ft^2  / 9 t   =  60 min

It is not incorrect      1 amp = 1000 milliamps  ,   silly !