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CPhill, I'm not sure how to solve this, can you solve it?

First you subtract 2 from 6, 4, and 12, because the 2 people that are taking all three courses are part of the people that are taking at least 2 courses. 

You now have 4 people taking only chemistry and physics, 2 people taking only chemistry and math, and 10 people taking only physics and math. 

Now we want to find the number of people taking only one course.

We have 26 people taking physics but 14 of them are also taking another course. So 26 - 14 = 12 people taking only physics.

We have 16 people taking chemistry but 6 of them are also taking another course. So 16 - 6 = 10 people taking only chemistry.

We have 28 people taking math but 12 of them are also taking another course. So 28 - 12 = 16 people taking only Math.

We have 2 + 2 + 4 + 10 + 10 + 12 + 16 = 56 people taking courses.

100 - 56 = 44 people taking no courses.

44/100 = 11/25 probability that he or she is not in any courses.

First one

a)  P(yellow sweet)  = 3/10  = B

b) There are no orange sweets.....so.....the probability of NOT picking an orange  one  is  just  1   = D

The website here is NOT to give you free answers. Maybe include an explanation of what you've done so far. Then it would be more reasonable for people to give you a solution. Appreciate some hints. Maybe try doing the problem with the same process as the hint.

I calculated the perimeter of the dodecagon. The answer is not the sum of two dodecagons, but nice try Cal!

Oh, thank you for the tip, Melody. I will post more often on the Forum.

thank you for showing me how to do it now i get it 

y = 6x + 7

y = -5x - 1

y =1/4x - 8

Thanks!

First you factor the equation into \((x-10)(x+9) = 0\).

So you're solutions are \(10\) and \(-9\). The sum of 10 and -9 is \(1\).

THANK YOU

x = 20/(tan 38)   =  20/(.781286) = .....                      if 38 is in degrees

By vietas formulas:

a + b = -(-1)/1 = 1/1 = 1

Vietas formulas state:

Given a quadratic(it can be any polynomial, I'd recommend searching up vieta's formulas)

\(ax^2+bx+c = 0\)

and roots: x₁, x₂

x₁ + x₂ = \(\frac{-b}a\)

x₁*x₂ = \(\frac ca\)

3000000 users/day    /    ( 3600 s/hr  *  24 hr/day )

3 000 000 / (3600*24) =.....

pi d   is circumference

11pi/18   /   2pi    is   fraction of circumference

(11pi /18)  /  2pi      *  pi *d    =   78.6       solve for 'd'     then radius is 1/2 d

x = score in 3 innings

x+5 = score in remaining innings    summed = 9

x      +     x+5             = 9       solve for x the 3 inning score, then the remaining innings score is  x+5

8x+3y=52

10x-3y=38     Add the two equations to get

18x     = 90    divide by 18

x = 5               Use this value of 'x' in one of the equations to compute 'y'

2m / 25 m/hr = .......    time to cross

(time to cross) * 17 m/hr   = distance downstream

Area of triangle = 1/2   base  *  height

Base and height are both   6 sqrt2

1/2 *(6sqrt2)(6sqrt2) =.......

When the 2nd digit is 0, then there are 80 such numbers =8 x 10 =80
When the 2nd digit is 2, then there are 60 such numbers =6 x 10 =60
when the 2nd digit is 4, then there are 20 such numbers = 2 x 10 =20
So, the overall total then is: 160 x 9 (from 1 to 9 in the first place) = 1,440 such numbers.

The following computer code verifies that:

a=1;b=0;c=0;d=0;p=0; cycle:n=a*1000+b*100+c*10+d;if(b%2==0 and d>=2*b and d!=0 and d!=1, goto loop, goto next); loop:printn," ",;p=p+1; next:d++;if(d<10, goto cycle, 0);d=0;c++;if(c<10, goto cycle, 0);d=0;c=0;b++;if(b<10, goto cycle,0);b=0;c=0;d=0;a++;if(a<10, goto cycle,0);print"Total = ",p

OUTPUT = 1,440 such numbers.

I simply did 35/5*3 and there you have it

For bases greater than ten, use A for 10, B for 11 etc. So:

if the probability of a 6 is 1/5 then that of not 6 is 4/5 as the two probabilities must sum to 1.

For b), because the probabilities of the two rolls are independent you multiply together the probabilities that lie on the route that provides two sixes.

For A it's simply asking how far Jo has walked after 10 minutes. So A is 1km.

For B I believe it's asking for how many miles Jo will walk per hour for the speed.

So, 1km is 0.6 miles; so in 30 minutes Jo has walked 4km. So 4km is 2.5 miles.

So, in 1 hour Jo would walk for 5 miles.

So for B, Jo is walking at 5 miles per hour.

Answers:

A) 1km

B) 5 miles per hour

Hope you understand my writing as I sometimes go off on a tangent and my writing ends up making sense only to me

Have a nice day

Thanks