"y varies directly as 6 more than three times x"
-- there is a multiplier in this formula, call this multiplier "m"
-- then this equation becomes: y = m·(6 + 3x)
"when y is 2, then x is 1"
-- substituting these values into our formula, we have: 2 = m·(6 + 3·1)
-- solving for m: 2 = m·(9)
m = 2/9
-- therefore, our formula is: y = (2/9)·(6 + 3x)
"when y is 3, the value of x is k"
-- substituting these values into our formula, we have: 3 = (2/9)·(6 + 3k)
-- solving for k: 27 = 12 + 6k
15 = 6k
k = 5/2 or 2.5
Now, you need to find: -|-2k + 3|
-- substitute 2.5 into this expression to find the answer.