All Answers 353101 Answers

He is still here but he is just taking a break

(9+6)*7/2 since 9 is base₁ or US, 7 is base₂ or QR, and 7 is the height or RT so the area=(9+6)*7/2=52.5.

a(n) approaches 0.

I just plugged in a couple of values and it led to a pattern. For example, plug in 0 to n, and using the fact that a(0)=0, you will get a(1)=1. Then plug in 1 to n, and you will get a(2)=1/2. This will be an infinite series, and for every consecutive term, the result will be divided by 2.

1, 1/2, 1/4, 1/8, ... , 1/2^(n)

- hellospeedmind

It is off topic

He did not delete his account he just took a break and anyways he just came back a few hours ago

He actually just came back a few hours ago

CPhill just went back a few hours ago! Yay!

Not Exactly he just came back a few hours ago so he's not exactly leaving but just for a break

Calculators are bad for learning if you want to learn then don't use a calculator. They do the solving for you so you don't get used to solving those things. so it's not that good to use a calculator if you want to learn!

Highschool is the LAST school before doing the BIG TEST

took the test 

if you took my test, who is the answer?

If you know the formula, why don't you just plug in the values?

You can do this just by listing the ways:

H-H-H-T  =  (½)·(½)·(½)·(½)  =  1/16

H-H-T-H  =  (½)·(½)·(½)·(½)  =  1/16

H-T-H-H  =  (½)·(½)·(½)·(½)  =  1/16

T-H-H-H  =  (½)·(½)·(½)·(½)  =  1/16

T-T-T-H  =  (½)·(½)·(½)·(½)  =  1/16

T-T-H-T  =  (½)·(½)·(½)·(½)  =  1/16

T-H-T-T  =  (½)·(½)·(½)·(½)  =  1/16

H-T-T-T  =  (½)·(½)·(½)·(½)  =  1/16

Adding the individual results give ½

There is another way, using combinations ...

It's acually not correct...

thank you its very helpful

p - 2q  =  0     --->                       p - 2q       =  0

q - 2r  =  0     --->   x 2   --->            2q - 4r  =  0

Add down:                                 p         - 4r  =  0

p - 4r  =  0     --->                      p - 4r  =  0

p + r  =  5     --->   x -1   --->    -p  -  r  =  -5

Add down:                                   - 5r  =  -5

                                                        r  =  1

p + r  =  5   --->   p + 1  =  5     --->     p  =  4

q - 2r  =  0   --->   q - 2(1)  =  0     --->   q  =  2

First we have to figure out what 1001011-100110. If you use a calculator (or if you use scratch paper) you get: 900901. Binary is basically base 2. If you know how to convert between base 10 and another base (in this case, it is base 2) this is a rather simple problem; it just takes a lottt of computing. If you compute (it does take a while) you get 11011011111100100101

The angles in a right triangle form an arithmetic progression.  If the smallest angle is 13 degrees, then what is the largest angle? 

The total of the internal angles of every triangle is 180^o   

The right angle in the right triangle takes up 90^o of those 180^o   

Thus, the largest angle in a right triangle always has to be the right angle, i.e. 90^o  

_.

When we simplify it, it equals 4x^2-8x+8+-7x^3+21x-7 
4^2=16
8^2=64
7^2=49

21^2=441

If we add them we get 570.

Add equations: (p - 2q) + (q - 2r) + (p + r) = 0 + 0 + 5 ==> 2p - q - r = 5

Divide first equation by 2: p/2 - q = 0

Subtract equations: 5p/2 - r = 0 == > r = 5p/2

Substitute into third equation: p + 5p/2 = 5 ==> 7p/2 = 5 ==> p = 10/7

First equation: p - 2q = 0 ==> q = p/2 = 5/7

Second equation: q - 2r = 0 ==> r = q/2 = 5/14

Solution: (10/7, 5/7, 5/14)