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I tested it, and I think it goes down all it goes. If you use latex, I guess you can put it in text, or you can press the latex button like this:

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\) Just press the latex button.

That is the method I used the othe day while solving one of these....it might be a little shorter to arrive at the number if you start with the largest divisor in the question: '6 '  with remainder 5

11   23    29   35    41   47    53    59   

I do not know an eaiser (or another) way to solve these.....maybe something with the modulo function (of which I am not very familiar)....

   Let me know if you find the true 'mathematical way' !     ~ EP  

If it's that long, I guess you can take a screenshot of what the problem is, and then upload it here. Press the image button. I hope a moderator will help you, but for now, I guess you can take a screenshot 

-iamadumb6thgrader

Similar triangles

10 is to 6 as     ? is to 15

10/6 = ?/15     solve for ?     (mutiply both sides of the equation by 15)

Angle PBC works out to 24.5 degrees.

1200  factors  as      2^4 * 3  * 5^2 =   2 * 2 * 2 * 2 * 3 * 5 * 5  =  4 * 4 * 3 * 5 * 5

So....the number of different identifiable roll sequenes  =

        5!                        120      

    _______  =            ____    =     30

     2!  * 2!                      4

Nice explanation, EP!

xD but thanks.

Oh, that makes sense. Thanks.

The 187th digit is =8 of 98. In other words, if you counted ALL the digits from 1, 2, 3......11, 12,.......98, the 8 would be the 187th digit.

So, the 188th digit =9  - or the first 9 of 99 with the same reasoning as above.

Anyone ever tell you that you are rather impolite and demanding?  They should.....

1-9   is 9 digits

10 - 99  is 180 more digits      total so far 189

187   would be  in  '98'     as in '8'      188 would be the first '9' in page  99

 1 and 3 are the same

angle 2 = 90 - angle 1

angle 7 is in a triangle and is the same as   180 - angle 2 - angle 2 = .......

Angle O   is 90^o

x=32^o

y = 180 - x - 23 - 90 = .......

6.695 x 10⁶       

So I do the quadratic formula for both of the equations, and find their descriminents?
 

What do I do with them?

Use "Sum of consecutive squares" formula to sum them up:

n =99; a = 1/6 * (2*n + 1)*n*(n + 1) =328,350

Here is some help.....YOU finish it ...it is easy! 

Let  A  =  tan^-1(1/3)   --->   tan(A) = 1/3

Let  B  =  tan^-1(1/7)   --->   tan(B) = 1/7

Let  C  =  tan^-1(1/5)   --->   tan(C) = 1/5

Problem:  tan( A - C + B )   --->   tan( A + B - C )   --->   tan( (A + B) - C )

Since:  tan(X - Y)  =  [ tan(X) - tan(Y) ] / [ 1 + tan(X)·tan(Y) ]

With  X = A + B  and  Y = C   --->    tan( (A + B) - C )

                                                 =     [ tan(A + B) - tan(C) ] / [ 1 + tan(A + B)·tan(C) ]

Since:  tan(X + Y)  =  [ tan(X) + tan(Y) ] / [ 1 - tan(X)·tan(Y) ]

With  X = A  and  Y = B   --->   [ tan(A + B) - tan(C) ] / [ 1 + tan(A + B)·tan(C) ]

=   [ ( tan(A) + tan(B) ) / ( 1 - tan(A)·tan(B) )  - tan(C) ]  /  [1 + ( tan(A) + tan(B) ) / ( 1 - tan(A)·tan(B) )·tan(C) ]

=  [ ( 7 + 3 ) / ( 21 - 1 ) -  (1/5) ]  /  [ 1 + ( 7 + 3 ) / ( 21 - 1 )·(1/5) ]

=  ( 3 / 10) / ( 11 / 21 )

=  3/11

Here's a hint: Try using the discriminant.

Thanks, EP -- I appreciate your comment!

The measure of angle(A) will be one-half the measure of the intercepted arc:

one-half of 168^o  =   .....

You may want to look here:  https://tutorial.math.lamar.edu/classes/calci/defnofdefiniteintegral.aspx

EGAD!   WIsh I could give you more 'points' for THAT one !     ~ EP

Since the number 6 was created by 2 * 3, you might want to consider 15 as 3*5.