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I think he/she means: 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 1 + 0(for 10) + 1 +1(for 11) + 1 + 2(for 12)......etc.

If you sum up ALL the digits from 0 to 99 = 900. The number of ALL these digits =190

900 / 190 =4.7368 - This is mean of the 190 digits.

Here is the increasing order:
C = 0.43527528164,  E = 1,    A=1.122462048,    B=1.498307077,    D = 2

Yes!  Thank you!!

It's correct! I've done it as a guest. 

Look at a diagram:   2x + 90º + x = 180º

                                 3x = 90º

                                 x = 30º

                                 3x + x = 120º         ( Larger angle of that quadrilateral is 120º )

                                 3x + 30º = 120º

                                 3x = 90º

                                 x = 30º  

( I feel I'm 13 years old again. )

First find the sum of the numbers.

Also, since 0 has no value, I'll take it out for now.

The number series 1, 2, 3, 4, . . . . , 98, 99.
The first term a = 1
The common difference d = 1
Total number of terms n = 99

apply the input parameter values in the formula
Sum = n/2 x (a + Tn)
= 99/2 x (1 + 99)
= 9900/2
1 + 2 + 3 + 4 + . . . . + 98 + 99 = 4950

Therefore, 4950 is the sum of positive integers from 1 to 99.

Next find the average.

The amount of numbers = 100

4950/100 = 49.5

So your final answer is  49.5

It's the sum of it's digits. The largest number possible if you add up the digits is 99=9+9=18, so it's impossible that the mean would be 49.5.

Angle JKL = 104 - 2*33

1/      Find the length of hypotenuse:   LN = sqrt( MN² + LM² )

2/      sin(∠L) = MN / LN   

Yes, it's that simple!!!

cube=x^3

squrae roots=√x

x^3/√x=x^6

I think It's 12^2=144 am I right?

we see that y+3x=180 and 3y=180 so y=60 and 3x=120 so x=40 and 2x+6y=80+360=440 so 2x+6y=(D)440

so the mean is (0+99)*100/2=4950 then 4950/100=49.5 so the mean is 49.5

OMG thx so much!! I forgot thats what it meant!!!!

I need help with this problem.

Sorry but thats inncorrect 

What is your question exactly? How to write fraactions? How to perform operations on them? Please specify :)

isnt pi/2 1.5? so there is a break which means it is DNE

n    n^2  Remainder when n is divided by 5
1    1       1
4    16    4
6    36    1
9     81   4
11   121   1
14   196  4
16   256  1
19   361  4
21   441  1
24   576  4

There are an infinite number of integers whose squares mod 5 =1 and which leave a remainder of 1 or 4 as you can see on the right hand side.

The explanation is here:   https://www.mathsisfun.com/algebra/trig-four-quadrants.html

Sine is negative in 3rd and in 4th quadrant

sin( 226.88639405º ) = - 0.73         ( 3rd quadrant )

sin( 313.113606º ) = - 0.73           ( 4th quadrant )

The last 10 digits are:  6148926743