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130  131  132  133  134  135  136  137  138  139  230  231  232  233  234  235  236  237  238  239  303  313  323  330  331  332  333  334  335  336  337  338  339  343  353  363  373  383  393  430  431  432  433  434  435  436  437  438  439  530  531  532  533  534  535  536  537  538  539  630  631  632  633  634  635  636  637  638  639  730  731  732  733  734  735  736  737  738  739  830  831  832  833  834  835  836  837  838  839  930  931  932  933  934  935  936  937  938  939  Total =  99 such numbers.

Just add the two given angles    130 + 80

I can tell you 1 and 4   Are the same measure

if the upper and lower slanted line as are parallel,   Then 1 4 6 8 are all the same measure

249 in base 11 =  9   +     4 x11     +     2 x 11^2
3ab in base 12 = 12   +    11x12    +    3 x12^2           Add all of that together.....

(4x-5)(2x+3) - (x-8)(3x+2) = area

8x^2 +12x-10x -15     -    3x^2 -2x+24x+16  = area

5x^2 +24x +1 = area

Let the number of gallon of 8% butterfat needed =M

Then, the number of gallons of 2% butterfat needed =297 - M

0.08M  +  0.02 * [297 - M] =0.06 * 297, solve for M

M = 198 gallons of 8% butterfat will be needed

297  -  198 =99 gallons of 2% butterfat will be needed.

2)

1041, 1141, 1241, 1341, 1441, 1541, 1641, 1741 = all possible values of n in base 8

ALL the above values of n in base 8 are exactly the same values in base 10. So:
sum(1041, 1141, 1241, 1341, 1441, 1541, 1641, 1741) =11,128 in base 10

This site will help you.

I did.  I'm still posting as a guest not because I'm trying to maintain an anonymity,  

but simply because I just can't think of a good username... yet. My name is Ron.  

_.

Someone pls help me, thanks. 

Hmm!   What about k = -2?

Rearrange to get 

3y = (k-1)x  and

(k-1)y = 3x

Divide one by the other, the x and y cancel, and you will be left with a quadratic in k.

It's my problem I got the equation wrong, I'm sorry. 

It was my probem I got the equation wrong. 

Actually I meant the second equation to be \(\frac{x^2}{9}+y^2 = 1\) but thank you for the answer anyways. 

Like this:

\(a_1=7\\~\\ a_2=3*a_{(2-1)}-6\\ a_2=3*a_{1}-6\\ a_2=3*7-6\\ a_2=21-6\\ a_2=15\\~\\ a_3=3*a_{(3-1)}-6\\ etc \)

answered.

I am not sure but this is my best guess.

Forget about Henry, there are 11 people which are to be divided into groups of 3,3, and 5

There are 11C5 ways to choose the group of 5

Now there are 6C3 ways to choose a group of 3 BUT this is double counting, I need to divide by 2

so I have    11C5 * (6C3 /2)

Now there are 2 options for where to put Henry.

so I now have    11C5 * (6C3 /2) * 2 = 462*20/2*2 = 9240 option.

The equation of a sidways parabola is

\((y-k)^2=4a(x-h)\qquad \text{where the vertex is (h,k)}\)

Sub in h,k

then sub in the point on the parabola, to solve for a

You try now.

Angle TUV = Angle TUW + Angle WUV. Therefore, 9x+1 = 12x-20. If we subtract 9x from both sides, we get, 1 = 3x-20. Subtracting one from both sides will give us 0 = 3x-21. Thus, we see that 3x = 21 and x = 7. 

I wonder who could have posted the above answer...... 

I don't know how to prove it, but your question inspired me to create this regular polygon grapher on desmos:

Plot a point C that divides the segment into the ratio AC : AB= 3/4

C ( 4, 4 )

The points (2,5), (3, 3) and (k, 1) all lie in a straight line.

(a) Find the value of k.​
(b) find the equation of the line

Hello Guest!

b)

\(m=\frac{y_2-y_1}{x_2-x_1}=\frac{3-5}{3-2}=-2\)

\(y=m(x-x_1)+y_1\\ y=-2(x-2)+5\)

\(y=-2x+9\)

a)

\(1=-2k+9\\ 2k=8\)

\(k=4\)

  !

Michelle decides to mix grades of gasoline in her truck. She puts in 9 gallons of regular and 11 gallons of premium for a total cost of $62.38. If premium gasoline costs $0.18 more per gallon than regular, what was the price of each grade of gasoline?

Hello Guest!

\(9r+11p=62.38\\ 9r+11(r+0.18)=62.38\\ 20r=62.38-11\cdot 0.18\\ 20r=60.4 \)

\(r=3.02\)

The price of regular is  $3.02/gallon

\(p=3.02+0.18\)

\(p=3.20\)

The price of premium is  $3.20/gallon

  !

Angles sum to 180 in a triangle

b   +    b-12     +     2b-8  = 180

    Solve for b       Then   a = b-12     c= 2b-8