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This question is missing something...

Angle B = 2 * 28 = 56 degrees

Angle C depends on the measure of the angle A

1/    If angle A is 90 degrees, then the measure of angle C is 34 degrees

2/    If angle A is 60 degrees, then the angle C is 64 degrees

I see now. I put 11 - 3 in the beginning so I had -3 times everything.

x coordinate     [(2 / 4)*3] + (-5) = - 3.5

y coordinate    [(7 / 4)*3] + (-4) = 1.25

(1/2 + 2/3 + 3/4 + 4/5)^2 + (1/2 + 2/3 + 3/4 + 4/5) *1/2 - (1 + 1/2 + 2/3 + 3/4 + 4/5) * (2/3 + 3/4 + 4/5)=

[26569 / 3600] + [163 / 120] - [223 / 60 * 133 / 60]

[31459 / 3600]            -              [29659 / 3600]

1800 / 3600 = 1/2 - which is the final answer.

PV = FV / [1.02^3] . If FV =1,000

PV =1000/ 1.061208

PV =$942.32

Note: Calculate 1.02^3 FIRST, then divide FV by the result.

Lets use (a^2)*(h/3).

h is calculated by finding the square’s diagonal (√(12^2 + 12^2) which comes to √288 or 12√2. 

So, from the corner to the centre of the square is 6√2. This gives a right triangle with hypotenuse of 12 and base of 6√2.
12^2 - (6√2)^2 = 144 - 72. Therefore, the perpendicular height is √72 which is 6√2.

Plug that into the formula and get 144*((6√2)/3) which gives 144*(2√2) or 288√2.

A close decimal equivalent is 407.3 units^3

Hope that helps!!

Change it into a polynomial: 

x^2-4x-5=0

Simplify from there by factoring:

(x-5)(x+1)=0

x = 5, -1

Angle CAB = Angle CBA

180 - 66 = 114

114/2 = 57 degress - angle CBA = angle CAB

180 - CBA - CBD=45 degrees =

180 - 57 - 45 = 78 degrees - angle DBE

90 - 78 = 12 degrees - angle BDE

thanks

Numbers are   x    x+2     and     x+4

    x   +   x+2     + 8     =  3 (x+4) - 11       solve for 'x'    then the third number is    x+4

Well, of course you know the shortest distance between two points is a straight line

Use the distance formula between the two points

d²  = (-4-4)²    +   (-2-3)²             Note : this gives you d²     ....   so you will need to take the sqrt

B = 40 degrees, C = 52 degrees.

Exactly five of the statements are true.

The volume works out to 144*sqrt(5).

DID YOU DIVIDE: 3.88 / 4 ?? IF YOU DID, WHAT IS THE ANSWER? 0.97 cents !!!!???

Let the number of Liters of 25% boric acid =B
Then, the number of Liters of 50% boric acid =30 - B

0.25B + 0.50[30 - B] =0.40 * 30, solve for B

B = 12 Liters of 25% boric acid.
30 - 12 = 18 Liters of 50% boric acid.

That isnt the correct answer. The real answer is 0.97 cents we did this problem in class and the answer was 97 cents so im not sure what grade you are in but im in 6th and i knew that.but nice try :)

Let the number of weeks when the 2 tanks equalize =W

248 - 3W =372 - 5W, solve for W

5W - 3W =372 - 248

2W = 124

W = 124 / 2

W = 62 weeks - when both tanks will be the same.

Move everything to make it a quadratic equaation:

x^2-4x=5

x^2-4x-5=0

Factor and solve for x:

(x-5)(x+1)=0

x=5, -1

Thank you!! I'm really trying to learn how to do these problems. 

5x - 4 < 2x + 5.        add 4 to both sides of the equation

5x < 2x + 9              subtract 2x from both sides

3x <9                       divide both sides by 3

x < 3              Interval     (- inf, 3)

21 coins

n

p = 4n

d = n+1

q = n-1

n  +  4n  +   n+1    +   n-1 = 21

7n = =21

n = 3

then   p = 12      d = 4   q = 2

Use the RATIONAL ROOT THEOREM to find solutions for these. factors of the lead constant=96/factors of the lead coefficient=1= 1 x 96, 2 x 48, 3 x 32, 4 x 24, 6 x 16, or 8 x 12. The possible roots are 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96. 2 is a solution, so we can factor out an x+2. (x-2)*{x^4+6x^3-12x^2-56x+96}/{x-2}, and that equals (x^3+8x^2+4x-48)(x+2). Now simplifying this actually $=x^3+\frac{8x^3-12x^2-56x+96}{x-2}$, and keep dividing this way until you get $x^3+8x^2+4x-48$ . So now this is easily factorable, $=\left(x-2\right)^2\left(x+4\right)\left(x+6\right)$I am pretty sure D is right but look out for a graph that intersects x in 3 places: 2, -4, and -6!

-Pangolin14 :D

S H E_5      = 4 1 2

   H E_5       =    12

_______

S E S_5       =4 2 4

This was actually pretty hard! Also, I suggest not to post these types of questions because it suggests something.... Math is not a place for this kind of joking around.

Ok, let's begin.

In base 10, we write expanded notation of a number xyz as 100x+10y+z, or 10^2*x+10^1*y+10^0*z. This works the same in other bases. 

Therefore we have 25S+5H+E+5H+E=25S+5E+5S in base 10. Next we combine like terms, getting 2E+10H+25S=30S+5E, and we need to find positive integer solutions to S,H, and E that are less than 10, or digits. Simplifying like terms again, we get 10H=5S+3E. It's pretty obvious what S, E, and H are now. By guess and check, H=2, S=2, and E=0. 220 is SHE in base 5. I don't think this question has an answer though because 220+20 is not 202.