Fill in the blank, so that that the resulting expression is the square of a binomial:
x^2 + 6/5*x +__
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\(x^2+\frac{6}{5}x+\)__
\(a^2+2ab+b^2\\ a=x\\ 2ab=\frac{5}{6}x\)
\(2xb=\frac{6}{5}x\\ b=\frac{6\cdot x}{5\cdot 2\cdot x}\\ b=\frac{3}{5}\)
\(x^2+\frac{6}{5}x+(\frac{3}{5})^2=(x+\frac{3}{5})^2\)
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