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BLUE  are   5  out of  (2+2+5+7) =   5 / 16   of 320

5/16 * 320 = ........

The roots of x^4 + 3x^3 + 5x^2 + 7x + 9 are

-1.6673 - 0.9330*i

-1.6673 + 0.9330*i

0.1673 - 1.5613*i

0.1673 + 1.5613*i

Plugging these into (a + b + c)(a + b + d)(a + c + d)(b + c + d), we get -12.

Take one of the MF groups.

Are there not 12 ways in which that can be set up ?

Any one of three of the men with any one of the four women.

AXF = 90     add the two angles 10 and 28 for BXE

Using trigonometric identities, we get g(x) = tan(x).

x - 0.08x =0.92x

0.92x = 23

x = 23 / 0.92 = 25 inches - actual width of the table.

If you're trying to find out what b is then you should know that b is the y-intercept. So you just choose one of the coordinates and substitute it into the equation. I'll use A's coordinates.

y=-3x+b

4=-3(-2)+b

4=6+b

So to get from 6 to 4 you subtract 2.

b = -2

$ 8500 - 4236.87  + 3200 - 989.42 = available credit =  $ .........

I think you meant she pays a 10 % deposit

10 % of 234900 =   .10( 234900) = $ ............

2  I assume there is only the 20 students in the class

        CUMULATIVE average

                ( 12*92   +   8 * 96 ) / ( 12 + 8 ) = ...........

1   x = stock price

     40% decrease    leaves 60% value   =  .6x

     then a 50% increase         .6x  *   1.5 = .9x     .9 means the stock is worth 90% of its original price (10 decrease from original price)

Let's see you have a go at this, making use of the answer I gave here: https://web2.0calc.com/questions/please-help-thank-you_42#r1

Note that

A^-1 = [ 0  1]

         [-1  0]

T = [-1]

      [-1]

U = [2]

      [3]

V = [3]

      [1]

W = [ 2]

       [-1]

"For what values of a does the equation (a^2 + 2a)x^2 + (3a - 2)x+1 = 0 yield no real solutions x?".

1/5 = 0.2 = 20%

100% - 20% - 10% = 70%

He left 70%

∠A = ∠C = 90 - arcsin(3/5)

use the law of sines to find AD

AD = 4.879

hint :    triangle BPC is an isosceles triangle

Hints:

Let the length of sides be 2 units.

Let E be the midpoint of DC

and

Let F be the midpoint of AB

Find PF

Find PE

Use trig to find angle C in triangle  CEP

Please let guest do it from here.

If x^2+4bx+10 has at least one real root, find all possible values of b. Express your answer in interval notation.

Hello Guest!

\(x^2+4bx+10=0\)

\(x=-2b\pm \sqrt{4b^2-10}\\ 4b^2\ge10\\ b\ge\sqrt{\frac{5}{2}}\)

\(b\ge 1.5811\)

\(b\in \mathbb {R}\ |b\ge 1.5811\)    \([\sqrt{\frac{5}{2}}]\)

  !

Use the three equal side test.

In how many different ways can 3 men and 4 women be placed into two groups of two people and one group of three people if there must be at least one man and one woman in each group? Note that identically sized groups are indistinguishable.

If you only care about gender 

FFF    MM MWF        

MFF   MM FF

MFF    MF MF

MMF   MF  FF

MMM  FF  FF

So I get 1 ways

No it is CORRECT

Although I do not understand Dragan's logic

Question 3

The planetarium sells movie tickets to adults and students. Marsha bought 2 adult tickets and 3 student tickets for $27.50.$ Jay bought 1 adult ticket and 2 student tickets for $16.25.$

A. Write a system of equations to represent the situation.

Let $a$ and $s$ be variables representing the cost for each of the adult tickets and student tickets, respectively. Then the equation representing the total cost for Marsha's tickets is $2 a + 3 s = 27.50.$ 2a is the total cost for adult, and 3s is the total cost for student tickets. Now we will deal with Jay's tickets. The equation for Jay's total cost would be $a+2s=16.25.$ For the same reasons, a and 2s are total costs for Jay's adult and student tickets. The system of two fully simplified equations and two variables required to solve this question are:

$$2 a + 3 s = 27.50.$$

and

$$a+2s=16.25.$$

B.  Determine the cost of each adult ticket and each student ticket. (Show your work or explain how you used a graph to determine your answer.)

We know how to solve a system of equations, either by substitution, or elimination. Elimination seems to be the most efficient, as $2 \cdot a = 2a,$ and to our convenience, $2\cdot 2s-3s=s,$ which allows us to solve our equation by multiplying $a+2s=16.25$ by two and subtracting $2 a + 3 s = 27.50.$ That yields $s=5.00,$ and thus $a=6.25.$ 

C. Marsha bought additional tickets for her friends that decided to come to the movie. She bought a total of 4 adult tickets and 7 student tickets. What was her total cost? (Show your work.)

From #B, we know adult tickets ($a$) cost 6.25 and student tickets ($s$) cost 5.00, so we can multiply 6.25 per 4 tickets for 25 and 7 times 5 for 35. So her total cost is 25+35=$60 

See the answer here:  https://web2.0calc.com/questions/help_53845

First train has a 50 m/hr x 3 hr = 150 mile head start

Second train is going 60 - 50 = 10 m/hr faster and will close this 150 mile distance

  in 15 hours to catch the first train

2pm + 3 hours + 15 hours = 8 am