All Answers

#1

+37171

+1

First half losses = 84/2 * 3/7 = 18

Second half losses 84/2 * 5/14 = 15 add them together.......

ElectricPavlovOct 16, 2020

#4

0

Anyone willing to confirm?

EP already said "Agree with CTG."

GuestOct 16, 2020

#3

+37171

0

Yep....typo ! D'Oh ! Thanx for fixin' it CTG.....

ElectricPavlovOct 16, 2020

#2

+2096

-2

I'll latex it to make it a bit easier

EP's answer was great though :)

\(\frac{3xy}{x}-47\)

This is the same as crossing out the x's.

\(3y-47\)

I think EP also had a typo or something.. the question was 3xy, not 34xy

CalTheGreatOct 16, 2020

#2

+37171

+1

Squares between 100 200 inclusive 100 121 144 169 196

101 197 add them together ! *** edited ***

ElectricPavlovOct 16, 2020

#1

+2096

-2

Let's start by listing out the perfect squares that are between 100 and 200.

11^2=121

12^2=144

13^2=169

14^2=196

Now, let's see if the numbers that are 1 or 2 more than these squares are prime.

121+1=122 NOT PRIME

121+2=123 NOT PRIME

144+1=145 NOT PRIME

144+2=146 NOT PRIME

169+1=170 NOT PRIME

169+2=171 PRIME

196+1=197 PRIME

196+2=198 NOT PRIME

171+197=368

CalTheGreatOct 16, 2020

#1

+37171

+1

Find the hypotenuse (which is the side length of the square) via the pythagorean theorem

a²+ b²= c²

^{5^2 +8^2 = c^2 c = sqrt (89)}

Area of square = side^2 sqrt(89)² = 89 units ²

ElectricPavlovOct 16, 2020

#1

+2096

-2

Here is a hint :)

Notice that the triangle is equilateral, and the height of every trapezoid or triangle is the same.

We also know that triangles can be fit together to form trapezoids.

CalTheGreatOct 16, 2020

#3

+2096

-2

Ty EP :)

I think the question means "write 316 AS square roots" which would get you my answer... I'm not sure though.

Anyone willing to confirm?

CalTheGreatOct 16, 2020

#4

+37171

0

Thanx !

ElectricPavlovOct 16, 2020

#2

+37171

0

Agree with CTG .... strong work !

or did you mean 316 = sqrt(99856) ?

ElectricPavlovOct 16, 2020

#3

+2096

-2

For future uses, the quadratic formula is:

\(\frac{-b\pm\sqrt{b^2-4ac}}{2a}\)

.

CalTheGreatOct 16, 2020

#2

+37171

+1

For one solution thie discriminant of the quadratic = 0 b^2 - 4ac = 0

64 - 4 ac = 0

so another equation relating a and c 64 - 4 ac = ac = 16 and given c = 12-a

a (12-a) = 16

-a^2 + 12a - 16 = 0 quadratic formula shows a = 6 - 2sqrt 5

and c = 6 + 2 sqrt 5

ElectricPavlovOct 16, 2020

#2

+2096

-1

The first step to solving it:

\(a^2+b^2=1936\)

So we get:

\(a^2-b^2=704\)

\(a^2+b^2=1936\)

Now we can eliminate a or b :)

CalTheGreatOct 16, 2020

#1

+2096

-1

Hint: Here are the possible values of a and c. Try plugging them in and solving it.

a=5, c=7

a=4, c=8

a=3, c=9

a=2, c=10

a=1, c=11

Tell me if you need more help :)

CalTheGreatOct 16, 2020

#1

+2096

-1

The square root of 316 is:

2sqrt(79)

CalTheGreatOct 16, 2020

#1

0

14.95

GuestOct 16, 2020

#4

+1490

+1

Why is this post blocked?!?

DraganOct 16, 2020

#1

0

The number of rectangles is 264.

GuestOct 16, 2020

#1

+44

0

very cool. I will be sure to enter my credit card information and my roblox username and password :)

SpaggehityOct 16, 2020

#2

+44

0

Nice pfp

SpaggehityOct 16, 2020

#1

+37171

+1

Doubling the recipe calls for doubling the amount of flour

3 1/4 x 2 = ........ cups

ElectricPavlovOct 16, 2020

#1

0

Between 10,000 and 99,999, there are 90,000 five-digit integers. Out of that 90,000 there are exactly 24,000 integers that are NOT divisible by any number in the set of {1, 2, 3, 4, 5}, with the exception, of course, of being divisible by 1.

Therefore, the probability is: 24,000 / 90,000 = 4 / 15

GuestOct 16, 2020

#6

+2096

-1

Yes, thank you! :D

CalTheGreatOct 16, 2020

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