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Thanks a lot! 

i assume the second part is 1/a+1/b

1/-5 +1/3 = -2/15

1.56 x 103 = 160.68

2 places to the right the decimal did move

(1/2)²+(1/3)²=13x solve for x

(1/4)²+(1/5)²=41y solve for y

1/4+1/9=13x

1/16+1/25=41y

13/36=13x

41/400=41y

1/36=x

1/400=y

√(1/36) / √(1/400) = (1/6) / (1/20)

20/6 or 10/3

V=πr²H

V=15πr² orginal

V=Hπ(2r)² new

15πr²=hπ4r²

15=4h

15/4=h of new

2.2 x 3.7 is 8.14

the error is the 0 should be an 8

yes, 1pm+6 hours is 7pm. LA is 3 hours behind PA, so 7pm-3 is 4pm. 2 hours to get ready and get there, 4pm+2=6pm right on time

Note that this means that for any value of r, the two equations must have only one solution. You know that y = r - x, so x^2+(r-x)^2=2r. Expand this, create a quadratic in terms of x, and set the discriminant to be 0. That should give you r.

THX, OlympusHero !!!.....I didn't realize  that this procedure  had a name

Here's a website  that explains it pretty well  :  https://www.onlinemath4all.com/area-of-quadrilateral-when-four-vertices-are-given.html

We could figure this using some trig, but there is a "formula"   to figure it faster

Listing the points in a counter-clockwise manner  :

A =  (x1 , y1 )  = (2,5)

B= ( x2, y2)  = (-5, 2)

C = (x3, y3)  = (-3, -6) 

D = (x4, y4)  = ( 6, -3)

Area =  (1/2) {(x1y2 + x2y3 + x3y4 + x4y1)  - (x2y1 + x3y2 + x4y3 + x1y4)}

Area  = (1/2)  [ ( 2*2  + (-5)(-6) + (-3)(-3)  + (6)(5) )  -  ( (-5)(5) + (-3)(2) + (6)(-6) + (2)(-3) )  

Area  =  (1/2) [  (4 + 30 + 9 + 30)  -   ( -25 - 6 - 36 - 6 ) ]

Area = (1/2)  [ 73  -  (- 73) ] 

Area =  (1/2)  (146)  =       73 units^2 

We can write \(x^4+6x^3-ax^2-45x-15=q(x)(x^2-x-6)+3\). Factoring \(x^2-x-6\) gives \((x-3)(x+2)\). So what significant numbers can you plug into the first equation to get the answer? Can you take it from here?

I would like to note that this works in general; CPhill's method can always be used, it is a formula.

Have you tried using the Shoelace Formula?

whats the answer just want to see if I got it right

Hello, Phill!

Why don't you come back here and correct all your errors before they become mistakes?

a  

We know  the angle, the adjacent side  and we  are looking for the opposite side  = O

The tangent relates these  =  opp/ adj

tan (37°)  =   O / 6.5

Solve this  →     6.5 * tan (37°) =   O

b

We  know  the  angle, the adjacent side   and we are looking  for the hypotenuse, H

The cosine relates these  = adj / hyp

cos (37°)   =  6.5 / H          rearrange  ahd solve this

H =  6.5 / cos (37°)   

Add H   +  O   to get the tree height

Let me know if you get stuck

Makes you wonder if some of  these guys even read their own questions.....

         1  

a.    –––  of an hour   -   this happens to be 12 minutes.  

         5          

b.    5 tasks.  That was the first sentence of the problem. 

_.

(3,4)        and  4x + 3y + 6   =  0 

distance =    l  4(3)  + 3(4) +  6  l            l 30 l                 30

                   _________________ =      _______    =    ____  =     6 units

                    sqrt  ( 4^2 + 3^2 )               sqrt (25)             5

Ur welcome     !!!!

In a circle with center O, AD is a diameter, ABC is a chord, BO = 5, and ABO = arc CD = 45 degrees. Find the length of BC.

1/   Using the law of sines find AB, AO      (AO * 2 = AD)

2/   Using trig find AC         (ACD is the right triangle)

3/   Subtract AB from AC and you'll get your answer.

Note  that  18hrs  after  7AM friday  =  12 hours  + 6 hrs

7AM  +  12 hrs =    7PM  Friday

7PM Friday  +  6 hrs  =  1 AM Saturday

 + 30  more minutes   =     1:30 AM  Saurday

However....this is in terms of  Philadelphia time

There is an 18 hour time difference  between  Philadelphia and Auckland

Adding  18 hrs  to  1:30 AM Saturday  gives us  7:30 PM Saturday  = pickup time

thank you😎👍

See  the graph  here  : https://www.desmos.com/calculator/fq91ehpnuv

This  area  forms a trapezoid ....height  =5     with bases of  2  and 5

Area =  (1/2) (height) ( sum of base lengths)   =  

(1/2) (5) ( 2 + 5)  =

(5/2) * 7  =

35/2  units^2    =   17.5 units^2