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Add  all the known times together

6 +  5  + 5 + 6 + 5  =  27 min

2 + 53 + 45 + 0 + 34  =  134 s  =   2 min 14 s

So......the total of her times  =  29 min 14s

34 s =  14/60  ≈  .23 min

So....her total times so far ≈ 29.23  min

And note that 5 min 50 s   =   5 + 50/60   ≈  5.83 min

So  let  x  be  the time she needs (in minutes)   and we have that

29.23  +  x

___________  =    5.83                     multiply   both   sides by 6

       6

29.23  +  x  =34.98

x =  34.98  - 29.23  =    5.75 m

And  note that      5.75 m  =    5 + .75(60)  ≈   5m  +45s   =   

 (5 min + 45 s)  = time she needs in her 6th race 

5 min 50s =  350                 total seconds for 6 races = 2100 seconds

2100 - 362 - 353- 345-360-334 = .......   seconds for last race to qualify

28 = -4.9t^2 + 23.8t

-4.9t^2 + 23.8t -28 = 0      quadratic formula to solve   a = -4.9    b = 23.8   c = -28

\(t = {-b \pm \sqrt{b^2-4ac} \over 2a}\)         

                           you'll get TWO t values ....one is for the  time when proj is going up....the larger one is for when proj is coming down

3x =12     divide both sides of the equation by 3

x = 4

3x=12

 p q + 2 p + q = 348
q r + 4 q + 3 r = 373
r s + 8 r + 6 s = 544

By way of a computer code, we have:

r = 31 and s = 8 and p = 34 and q = 8

1 - x mod 6 = 1
     x mod 20 = 9
     x mod 45 = 4 for x

Using CRT + MMI, we have:

r = 1

x =180n + 49, where n=0, 1, 2, 3........etc.

help me asap i have a test due today she said we can cheet

I seriuosly doubt that......and the word is 'cheat'         Haha

More detailed explanation pls?

-2x^2 - 50x  + 23

-2 (x^2 +25x)     + 23

-2(x+12.5)²    +312.5    + 23

-2(x+12.5)²  + 335.5

Are you allowed to cheat on tests?????

0 ht  is when the ball hits the ground

0 = -4.9 t^2 + 42t  + 18.9      a = -4.9     b = 42     c = 18.9    for Quadratic Formula:

\(t = {-b \pm \sqrt{b^2-4ac} \over 2a}\) 

Sub in the values to find    t = 9 seconds     or     - .428 (throw out )

x/3 = 5

Multily both sides by 3

x = 15

We need to find the inverse of the  given function....for f(x), we can write, y

y = 1 - √  [1 - x^2]      rearrange as

√  [1 - x^2]   = 1 - y      square both sides

1 - x^2  = (1 - y)^2

1 - x^2   =  y^2 - 2y + 1    subtract 1 from both sides

-x^2  = y^2  - 2y        mutiply through  by -1

x^2  = 2y  - y^2        take both roots

x  = ±√ [ 2y - y^2 ]      "swap"  x  and  y

y  = ±√ [2x - x^2 ]

We only need the top half of this graph   ⇒   y  = √ [2x - x^2 ]

The area enclosed by both functions will be twice the area of the area between  y = x  and  y  = 1 - √  [1 - x^2]

Note that the area  bounded  by the y axis from 0 to 1 , the line y = 1 from 0 to 1   and the line  y  =  x   will from a triangle with a base  and height of 1....so...it's area =  (1/2) base * height  = (1/2)(1)(1)  = 1/2  units^2

And note that the area formed  y axis from 0 to 1, the line y  =1 from 0 to 1  and the function  y = 1 - √  [1 - x^2]    will be the area of a quarter circle with a radius of  1 = pi

So....this area  less the area of the triangle will   =  1/2  of the area we are seeking

So....the total area  = pi - 2

(4 x 10⁵ )²  = 16 x 10¹⁰ = 1.6 x 10¹¹

A + B + C + D + E = -1 + 2 + 4 + 2 + -1 = 6.

5 * 5/6 =   (5*5)/6 = 25/6 = 4  1/6

Quadratic formula for ax^2 + bx + c: x = (-b pm sqrt(b^2 - 4ac))/2a

Plug into the formula to get t = 23 seconds

Thanks for trying but the answer is 4624

Note that 62^2 = 3828 and 64^2 = 4096 and 4096 - 3828 = 268, so the larger square is 4096.

1. The set of all n that works is n congruent to 18 mod 30.

5. The odd digits 1, 3, 5, 7, 9 are the possible values of the tens digit.

V = 4/3*pi*r^3

dV/dt = 4/3*pi*r^2

S = 4*pi*r^2

dS/dt = 8*pi*r

dr/dt = -4635

r = 10

dS/dt = 80

The rate of the change of the surface of the sphere is -80 in^3/sec.

2   ways to pick the host team          2

EACH of remaining 3 teams have 7c2 ways to pick committee members     7c2 * 7c2 * 7c2

and the host team has 7c2 ways to pick committee members       7c2

3*  7c2 * 7c2 * 7c2 * 7c2 = 4 x 21 x 21 x 21 x 21 = 777924 ways

8 is the answer

So the answer is 2