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ok Im pretty sure its 94, M being 23 and N being 4 hope this helps

1/175  is a    fraction with a repeating decimal  = . 00571428

Red part   is the repeating part

We can  solve this

2  +  6n   = 4000

6n =  4000  - 2

6n = 3998

n =  666  +  2/3

The  4000th digit  is  the second  interger in the  pattern   =   7

OM = sqrt  (1^2  + 2^2)  = sqrt (5)

Because OCB is a right triangle  with CBO  =  90 °

Then BM  is a geometric mean  such that

   CM/BM  = BM / OM

BM^2  = CMsqrt (5)

CM =  BM^2 /sqrt (5) 

And   OACB  forms a  kite

Its area  =(1/2) product of the  diagonal lengths

So

(1/2)  ( BM + BM )  ( OM + CM)

(1/2) ( 2BM)  (  sqrt (5) + BM^2 / sqrt (5) )

BM sqrt (5)  +  BM^3 / sqrt (5)  =   sqrt (11/5) r^2

r ^2  =  [ BM sqrt (5)  + BM^3 /sqrt (5) ] / sqrt (11/5)

r^2  =  OM^2  + BM^2

[ BM sqrt (5)  + BM^3 /sqrt (5) ] / sqrt (11/5)  =  5 + BM^2

sqrt (5)  [ BM sqrt (5)  + BM^3 / sqrt (5) ]  / sqrt (11)  = 5 + BM^2

5 (BM) + BM^3   = 5sqrt (11)  + BM^2 sqrt (11)

5(BM)  + BM^2 (BM)  = 5 (sqrt (11)) + BM^2 (sqrt (11) )

Note  that  this will be true when   BM  = sqrt (11)

r = sqrt  ( BM^2  + OM^2) =  sqrt  ( 5 + 11)   =sqrt (16)  = 4

thank you :D

NOT FOR MATH 100%

how do u tell sum ur well happy 

3x + 9 = 6(x - 3)      simplify

3x + 9 =  6x  - 18

9 + 18 =  6x   - 3x

27  = 3x

x   = 9

We can use the Law of Cosines to solve this

(6.1^2  - 3.2^2  - 7.4^2)  / (-2 * 3.2 * 7.4)  =  cos S

To find S   we  have  that

arccos  [  (6.1^2  - 3.2^2  - 7.4^2)  / (-2 * 3.2 * 7.4)  ]   =  S   ≈ 54.1° 

f(x)    =  1x^2  + 4x   - 5

The form is    f(x)  = ax^2 + bx + c

This is a polynomial.....a polynomial always has a domain of  all real numbers  (it is continuous  on the x axis )

This si a parabola that turns upward.....we  can find  the  x value that  gives a minimum  by

-b/ (2a)   = -4 / ( 2 (1)  =   -2

To find the  y value  for this x

1 (-2)^2  + 4(-2)  - 5  =   4 - 8  - 5   = -9

1 is the  minimum value in the range....and  there is no max  ( the function continues "upward" forever )

So....the range is  [ -9, infinity  )

If we draw QR, as QN is a perpendicular and midpoint, QPR is isosceles with QP=QR. This means that O is the centroid of QPR, so OR = 2*OM. However, we are not sure how to find OM, but see that we can draw a perpendicular MX from M to PN, which gives us similar triangles PMX and PQN. Next, we note that as PN = 16/2 = 8, and QN = 10, PQ = 2√41. Thus, PM = √41. 

As PM/PQ = MX/QN = PX/PN, X is the midpoint of PN, and MX = 5. Thus, PX = 4. So, as MX = 5 and XR = 16 - 4 = 12, MR = 13, so OR = 13/3 * 2 = 26/3.

- (-2)^2  - ( 2 (-2) - 8 ( -4) ) + 5(-4)   =

- ( 4)  - (  -4 + 32 )   - 20   =

-4  - ( 28)    - 20   =  

-52

it says quartic, that's why I was skeptical about that solution.

The rest  of the  circle has the  arc of (360  - 75 - 130 )  =  155

The  measure of   x  =  (1/2)  ( 155  - 75)  =  (1/2) ( 80)   = 40°

thank you

The answer is g=0.5

The perimeter of a triangle      P = 12√3 + 12

1500  ( 1.13)^t      t   =  2     ....so....

1500 ( 1.13)^2   =  

1500 (1.2769)   =

$1915.35  after 2 years

Just put   2   in there where 't' is and compute....

#Pages = 35 + 23m

(1/4)   = probability of a walk      (3/4)   = probability of no walk

There are two appearances.....choose either one.....and we  have that

C (2,1)  (1/4) (3/4)   =   3 / 8

x^2 + 2

so  p(-2)  + 7 p(6)

 =     6     + 266= 272

Thx, Firebolt....here's another way with something known as Pick's Theorem

Lattice points =  points with integer coordinates

Area = [  lattice points in the interior of the  figure ]  + [ lattice points on the  boundary  / 2 ]    - 1

So we have

50  +  16/2   -  1   =

50  + 8  -  1   =

57

Monic indicates there is only one variable used, so we can say that $p(x) = ax^4 + bx^3 + cx^2 + dx + f,$ where $a,b,c,d,$ and $f$ are the coefficients. It appears to be that when we input $x$ as $1$, we just get $a + b + c + d + f = 3,$ and with $3$, we get $81a + 27b + 9c + 3d + f = 11,$ and with $5$ we have $625a + 125b + 25c + 5d + f = 27. $

We are trying to solve for $16a - 8b + 4c - 2d + f + 7 \cdot (1296a + 216b + 36c + 6d + f).$

See if you can simplify and/or find out this equation. Another thing you might notice is that if we have p(x) = y, then $\overline{abcdf}$ is a 5 digit number in base x, which equals y in base 10!

Area = pi*r^2

254.34 = pi*r^2

254.34 = 3.14*r^2

81 = r^2

r = 9

So, the diameter = 2r, so the diameter = 18.

You can split this into smaller parts and calculate the area, or use the Shoelace Theorem. Since I can't demonstrate splitting the shape here, I can use the shoelace theorem. 

Either way will give you 87/2 .

(3 + 5^2 -8)4

I'm assuming you mean \((3 + 5^2 -8)^4\), but I'll solve it both ways.

\((3 + 5^2 -8)^4 = (3+25-8)^4 = 20^4 = 160,000\)

Or, if you meant \(4(3 + 5^2 -8)\), then \(4(3 + 5^2 -8) = 4(3 + 25 -8) = 4(20) = 80\)

I hope this helped. :)