Happy New Year and Merry Eastern Orthodox Christmas, JB

Your particularly particular post presents as particularly peculiar. Where you enjoying a particularly potent Port?

In keeping with the particular tradition, I am posting the particular Christmas memoir on Eastern Orthodox Christmas Day.

GA

Happy New Year and Merry Eastern Orthodox Christmas, Ron

Your Christmas wish and New Year’s blessing are really nice. Thank you.

GA 

Hi Guest!

All you have to do is subtract 180-80=? because the submarine is 180 feet BELOW sea level, and then accends (rises) 80 feet, so you are taking how far down they went and subtracting how far they went back up out! I would like you to do thw subtraction problem below, and see if you can get your answer. If you still need help just ask :D :P

                                                                            180-80=?

I hope this was helpfull! :D :P

-Grace

Like so:

As follows:

Answer:

13

Step-by-step explanation:

There are 6 ways to choose the first number and 5 ways to choose the second number to paint so the total number of ways is 6 * 5 = 30 but we are over counting by a factor of 2 since 1 and 6 is the same as 6 and 1 so it's 30/2 = 15, not 30. The only choices that have a product of 6 are 2 and 3 or 1 and 6 so the answer is 15 - 2 = 13.

2520

\(10!/5!3!2!\)

Let f(r) = 1 + r + r^2 + ... = 1/(1 - r).

Taking the derivative: f'(r) = 1 + 2r + 3r^2 + ... = 2r/(1 - r)^2.

Then r + 2r^2 + 3r^3 + ... = 2r^2/(1 - r)^2.

Therefore, T = 2r^2/(1 - r)^2.

Hello Guest!

_ _ _ _ _ _

Let each of those spots represent a book. 

There are 4 spots where the math books can be, making 4*3 = 12 different placements of them.

After the placing the math books, there are 4 other books that can be placed in 4*3*2*1 ways. 

Thus, our answer is (4*3)*(4*3*2*1) = 228

I hope this helped. :)))

=^._.^=

Hi Guest!

The easiest way to do this problem would be to graph it, and look for the point of intersection, x = 1/3, y = -2/3. 

However, I'm going to assume that you don't have a graphing calculator on hand. 

I'm going to try to make it so that the only x remains in the equation.  

3x + y = 1/3

2x - 3y = 8/3

One way to cancel out y in this equation, 2x - 3y = 8/3, is to add 3y. 

3x + y = 1/3

9x + 3y = 1

Then, we can just add. 

(9x + 3y) + (2x - 3y) = 1 + 8/3

11x = 11/3

x = 1/3

Knowing x, we can just plug it in for y. 

2(1/3) - 3y = 8/3

2/3 - 3y = 8/3

-3y = 6/3

y = -2/3

I hope this helped. :))))

=^._.^=

Ok so,

Let the number of hours after 2:00 p.m. that the two engineers arrive at Starbucks be x and y, and let the number of hours after 2:00 p.m. that the boss arrives at Starbucks be z. Then \(0\le x,y,z\le2\) and in three dimensions, we are choosing a random point within this cube with volume 8. We must have \(z>x\) and \(z>y\); this forms a square pyramid with base area 4 and height 2, or volume 8/3.

However, if one of the engineers decides to leave early, the meeting will fail. The engineers will leave early if \(x>y+1\) or \(y>x+1\). The intersections of these with our pyramid gives two smaller triangular pyramids each with base area 1/2 and height 1, or volume 1/6.

In all, the probability of the meeting occurring is the volume of the big square pyramid minus the volumes of the smaller triangular pyramids divided by the volume of the cube: \(\frac{8/3-1/6-1/6}8=\frac{7/3}8=\boxed{7/24}\)

By Lagrange Multipliers, you get the optimal value when x = y = 1:

x^2 + y^2 + 1 >= c(x + y)

3 >= 2c

c <= 3/2

So the largest constant c is 3/2.

You must go up 2 and right 8, so the answer is \(\binom{10}{2}=\boxed{45}\)

250 + 125 + 125 + 62.5 + 62.5 + 31.25 + 31.25 = \(\boxed{687.5}\)

Please explain. I'm looking for how to do it.

If the combination  can't start with  0

1 / [ 9 * 10^4 ]   =   1 / 90000

If  it can start with 0

1 / 10^5     =   1 / 100,000